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James Prescott Joule

James Prescott Joule, FRS

A course on the Salford brewer who measured, with thermometers read to a two-hundredth of a degree, how much work makes a given amount of heat, and so turned the conservation of energy from a conjecture into a fact of the laboratory.

Born 24 December 1818, Salford Died 11 October 1889, Sale Equivalent 772.692 ft·lbf per lb·°F (1850) Level advanced undergraduate
The paddle-wheel calorimeter, schematic. Two weights fall, the paddles churn the water against fixed vanes, and the water warms by a fraction of a degree.
Lesson 00

How to use this course

James Prescott Joule held no university post and earned his living from a brewery. Between 1840 and 1850 he showed that an electric current heats a wire in proportion to the square of the current, that the heat produced by mechanical work is always in the same ratio to the work, and that this ratio is the same whether the work is done by electricity, by compressing a gas or by stirring water. His number, about 772 foot-pounds of work for each pound of water warmed one degree Fahrenheit, is within one percent of the modern value. The SI unit of energy carries his name.

Prerequisites for Part II
  • First-year calculus and mechanics: work, kinetic and potential energy.
  • Direct-current circuits: Ohm’s law, electromotive force, internal resistance.
  • An introductory course in thermodynamics: heat capacity, the ideal gas, internal energy.
  • For Lesson 09, partial derivatives and the Maxwell relations are helpful.

Each technical lesson opens with a paragraph for the general reader, then gives statements, derivations and exercises with folded solutions. Several exercises use Joule’s own numbers, in his units. Converting them is part of the training: it shows how small the effects were and how carefully he had to work. The physics lessons follow his work in order: electrical heating (1840–41), motors and magnets (1838–1847), the equivalent of heat (1843–1850), kinetic theory (1851) and the experiments with William Thomson (from 1852).

Reference

Timeline

1818Born 24 December in New Bailey Street, Salford, to Benjamin Joule (1784–1858), a wealthy brewer, and Alice Prescott.
c. 1834With his elder brother Benjamin, taught arithmetic and geometry by John Dalton for about two years.
1838First papers, on electromagnetic engines, in William Sturgeon’s Annals of Electricity.
1840On the Production of Heat by Voltaic Electricity communicated to the Royal Society: heat proportional to resistance times the square of the current.
1841Full paper on the heat evolved by conductors and in electrolytic cells, Philosophical Magazine.
1843August: reads his paper on the calorific effects of magneto-electricity and the mechanical value of heat at the British Association in Cork. First value: 838 foot-pounds.
1845Papers on the compression and rarefaction of air. June: paddle-wheel results read at the British Association in Cambridge.
1847June: British Association in Oxford; meets William Thomson. Public lecture in Manchester, On Matter, Living Force, and Heat. 18 August: marries Amelia Grimes.
1850On the Mechanical Equivalent of Heat, Philosophical Transactions: 772.692 foot-pounds. Elected Fellow of the Royal Society.
1851Publishes the first estimate of the speed of gas molecules: 6225 feet per second for hydrogen at 60 °F.
1852Royal Medal. Begins the porous-plug experiments with Thomson.
1854Death of his wife Amelia. The family brewery is sold.
1857–71Honorary degrees from Trinity College Dublin (1857), Oxford (1860) and Edinburgh (1871).
1860First term as president of the Manchester Literary and Philosophical Society.
1870Copley Medal of the Royal Society.
1878Final determination of the equivalent, 772.55. Civil list pension of £200 a year.
1880Albert Medal of the Royal Society of Arts.
1889Dies 11 October at home in Sale, Cheshire; buried in Brooklands cemetery. The joule is adopted as a unit by the International Electrical Congress that August.
Part I · Formation
Lesson 01

Salford and Dalton, 1818–1837

James Prescott Joule was born on 24 December 1818 in New Bailey Street, Salford, across the river Irwell from Manchester. His father, Benjamin Joule, owned a prosperous brewery; his mother was Alice Prescott. The family had money, and the boys were educated at home.

Manchester in the 1830s was the first industrial city in the world. Steam engines drove its mills, and engineers there cared about one number above all: the work an engine delivered for a given amount of coal, called its duty. Joule grew up among people who measured efficiency for a living, and his science kept that habit.

Lessons with Dalton

Around 1834, when James was fifteen, he and his elder brother Benjamin were sent for lessons to John Dalton, the founder of the chemical atomic theory, who taught private pupils at the rooms of the Manchester Literary and Philosophical Society. Dalton taught them arithmetic and geometry. The lessons lasted about two years, until Dalton’s health failed after a stroke. Dalton gave him an example: careful quantitative measurement, done privately, with home-made apparatus, could change a science.

Joule continued with other tutors, including the chemist John Davis. He began experimenting at home, in rooms of the family house fitted as a laboratory, and joined his father in managing the brewery.

Lesson 02

Electricity in the brewery, 1838–1842

In the late 1830s the electric motor looked like the coming rival of the steam engine. Moritz Jacobi had driven a boat on the Neva with an electromagnetic engine, and William Sturgeon, who had built the first practical electromagnet, ran a journal, the Annals of Electricity, full of designs for such engines. Joule’s first papers, from 1838, appeared there. He wanted to know whether electric motors could replace the steam engines in the brewery.

Sturgeon moved to Manchester in 1840, and Joule joined the circle of scientific men around him. Joule’s approach to the motor was an engineer’s. He measured the work each engine did against the zinc it consumed in the battery. The answer was discouraging. Zinc cost far more than coal, and an engine fed by a battery could not compete with steam (Lesson 05). But the investigation raised a deeper question. If the battery’s chemical action can produce either heat in the wires or work at the motor, what is the exchange rate between them?

The heating law

To answer it Joule first had to know how much heat a current produces. In 1840 he communicated to the Royal Society a paper On the Production of Heat by Voltaic Electricity, which stated that the heat produced in a wire in a given time is proportional to its resistance and to the square of the current. The Society printed only an abstract. The full paper, On the Heat evolved by Metallic Conductors of Electricity, and in the Cells of a Battery during Electrolysis, appeared in the Philosophical Magazine in 1841. Lesson 04 treats it. To make it, Joule had to build his own galvanometers and fix a reproducible unit of current, since none existed.

Lesson 03

Against the caloric, 1843–1847

Most physicists of 1840 held that heat is a weightless fluid, caloric, which can move from body to body but is neither created nor destroyed. Sadi Carnot’s theory of the steam engine rested on it. Joule’s electrical work convinced him that heat could be generated. In August 1843, at the British Association meeting in Cork, he read a paper On the Calorific Effects of Magneto-Electricity, and on the Mechanical Value of Heat. He had turned a small generator by falling weights and measured the heat produced in its coil. A pound of water warmed by one degree Fahrenheit, he concluded, needed the work of 838 pounds falling one foot. A postscript added a second result, from forcing water through narrow tubes: 770 foot-pounds. The audience responded with silence.

He tried again with gases. Compressing air in a vessel under water warmed the water; letting it expand cooled it. The Royal Society declined his paper, which appeared in the Philosophical Magazine in 1845. In June 1845, at the British Association meeting in Cambridge, he described a new method: a brass paddle wheel, driven by falling weights, stirring water in a can. Its first value was 890 foot-pounds. In a letter to the Philosophical Magazine he averaged his methods to 817, and suggested that water at the foot of Niagara should be about a fifth of a degree warmer than at the top.

Oxford, 1847

In June 1847 the British Association met in Oxford. Joule presented his paddle-wheel results. In the discussion a young Glasgow professor, William Thomson, later Lord Kelvin, raised objections. Thomson believed in Carnot’s theory and could not accept that heat is consumed when work is done. He was also struck by the experiments, and the two men began a long friendship (Lesson 11). George Gabriel Stokes and Michael Faraday were also present.

That spring Joule had set out his views for a lay audience in Manchester, in a lecture On Matter, Living Force, and Heat, printed in a local newspaper. Living force (vis viva) cannot be destroyed, he argued. When it seems to vanish, as when a moving body stops, it reappears as heat.

On 18 August 1847 he married Amelia Grimes. On the honeymoon in the Alps he met Thomson again near Chamonix. The two planned to measure the warming of water at the Cascade de Sallanches. The measurement proved impractical.

Part II · The physics
Lesson 04

The heating law of currents

For the general reader. A wire carrying a current gets warm. Joule found the rule: double the current and the heat goes up four times; double the resistance at the same current and the heat doubles. The rule governs toasters, fuses and the power lost in transmission lines. It also told him that the heat comes from the chemical work of the battery, not from some fluid carried along the wire.

Goals
  • State Joule’s first law in circuit and field form.
  • Derive it from the work done by the electric field.
  • Follow Joule’s energy balance for the whole circuit, battery included.
Joule’s law (1840–41)

A steady current \(I\) through a conductor of resistance \(R\) produces heat at the rate

\[ P = I^2R = IV = \frac{V^2}{R}, \]

where \(V=IR\) is the potential difference across it. In a continuous medium with conductivity \(\sigma\), current density \(\mathbf J=\sigma\mathbf E\), the heat produced per unit volume per unit time is \(\mathbf J\cdot\mathbf E=J^2/\sigma=\sigma E^2\).

Derivation

When a charge \(dq\) moves through a potential difference \(V\), the field does work \(V\,dq\) on it. In a resistor the carriers do not speed up on average: they collide with the lattice and pass the work on as disordered motion, that is, heat. In time \(dt\) the charge \(I\,dt\) passes, so the heat is \(VI\,dt\). Ohm’s law \(V=IR\) gives \(P=I^2R\). Locally, the force on the carriers in a volume element is \(\rho_q\mathbf E\), and its power is \(\rho_q\mathbf v\cdot\mathbf E=\mathbf J\cdot\mathbf E\).

Joule did not have the potential concept in this form, nor a standard unit of resistance. He wound wires of different lengths and metals, placed each in a glass jar of water, passed currents measured by a tangent galvanometer, and timed the temperature rise. He measured resistance by comparison with a standard wire. The square law came out of the data.

The whole circuit

Joule went further. He measured the heat produced inside the battery cells and in electrolytic cells as well as in the wires, and found that the total heat in the circuit, per unit of zinc consumed, is fixed. It equals the heat that the same chemical reaction would give if carried out directly, without the current. In modern terms, a cell of electromotive force \(\mathcal E\) delivering charge \(q\) does work \(\mathcal E q\), and all of it appears as heat when the current does nothing else. If an electrolytic cell in the circuit decomposes water, the heat is reduced by the chemical energy stored. The current is a carrier of energy from the zinc to the wire, a view Joule held by 1841.

Exercise 4.1A kettle element draws 10 A at 230 V. How long does it take to bring 1.5 kg of water from 15 °C to 100 °C, ignoring losses? What is the element’s resistance? (Specific heat of water 4186 J kg\(^{-1}\) K\(^{-1}\).)

Show solution
\(P=IV=2300\) W, \(R=V/I=23\ \Omega\). Heat needed \(1.5\times4186\times85=5.34\times10^5\) J. Time \(5.34\times10^5/2300\approx232\) s, just under four minutes.

Exercise 4.2A power line delivers power \(P\) at voltage \(V\) through cables of total resistance \(R\). Show that the fraction lost as heat is \(PR/V^2\). By what factor do the losses fall if the voltage is raised from 11 kV to 400 kV?

Show solution
The current is \(I=P/V\), so the loss is \(I^2R=P^2R/V^2\), and the fraction is \(PR/V^2\). Raising \(V\) by a factor \(400/11\approx36.4\) cuts losses by \(36.4^2\approx1320\). This is why transmission uses high voltage.

Exercise 4.3Two wires of resistances \(R_1\) and \(R_2\) are connected (a) in series, (b) in parallel, to an ideal source of voltage \(V\). In which arrangement does the higher-resistance wire get more heat, and why does this agree with Joule’s statement that heat is proportional to resistance?

Show solution
(a) Same current: \(P_k=I^2R_k\), so the larger resistance gets more heat, as Joule stated for a common current. (b) Same voltage: \(P_k=V^2/R_k\), so the smaller resistance gets more. Joule’s law, heat \(\propto I^2R\), is a statement at fixed current; the parallel case does not contradict it because the currents differ.
Lesson 05

Engines, batteries and magnets

For the general reader. Joule began as an inventor of electric motors. He found that when a motor does work, the battery’s current drops and the wires warm less: the work is paid for out of heat that would otherwise have appeared. He also found that iron grows very slightly longer when it is magnetized. Both results came from measuring an engine as an engineer would.

Goals
  • Write the energy balance of a battery driving a motor with back electromotive force.
  • Find the maximum mechanical power and the efficiency at that point.
  • Compare the energy in zinc with that in coal, as Joule did.
  • Estimate the size of magnetostriction.

The motor’s energy balance

A battery of electromotive force \(\mathcal E\) drives a motor through a total resistance \(R\). A turning motor generates a back electromotive force \(\varepsilon\), proportional to its speed. The current is \(I=(\mathcal E-\varepsilon)/R\). Multiply \(\mathcal E=IR+\varepsilon\) by \(I\):

\[ \mathcal E I = I^2R + \varepsilon I. \]

The battery’s power splits into Joule heat and mechanical power \(\varepsilon I\). A stalled motor has \(\varepsilon=0\), maximum current, and turns everything into heat. As the motor speeds up, the current and the heat fall. This is what Joule observed: the heat in a circuit is reduced when the motor does work, in proportion to the work.

Proposition (maximum power)

For fixed \(\mathcal E\) and \(R\), the mechanical power \(\varepsilon(\mathcal E-\varepsilon)/R\) is greatest when \(\varepsilon=\mathcal E/2\). Its maximum is \(\mathcal E^2/4R\), and the efficiency \(\varepsilon/\mathcal E\) is then 50 percent.

Higher efficiency requires the motor to run faster, close to \(\varepsilon=\mathcal E\), where it delivers little power. No adjustment of the motor can extract more from the battery than the chemical energy of the zinc consumed.

Zinc against coal

Joule measured the duty of his engines, in work per pound of zinc, and compared it with the duty of the best Cornish steam engines, in work per pound of coal. Zinc gave far less work per pound and cost far more. He concluded that battery motors could not compete with steam, a judgment that held until generators driven by steam replaced batteries as the source of current.

Magnetostriction

In the course of his work on electromagnets Joule discovered that an iron bar lengthens slightly when magnetized along its length, while its volume stays nearly constant. He described the effect in 1847 in the Philosophical Magazine. The fractional change \(\lambda=\Delta\ell/\ell\) is of order \(10^{-6}\) to \(10^{-5}\) in iron at saturation. The effect is the source of the hum of transformers: in an alternating field the core changes length twice per cycle.

Exercise 5.1Prove the maximum-power proposition, and compute the heat produced in the circuit at maximum power.

Show solution
\(P_{\rm mech}(\varepsilon)=\varepsilon(\mathcal E-\varepsilon)/R\) is a downward parabola with zeros at 0 and \(\mathcal E\), so its maximum is at \(\varepsilon=\mathcal E/2\), giving \(\mathcal E^2/4R\). The current is \(\mathcal E/2R\), the Joule heat \(I^2R=\mathcal E^2/4R\), equal to the mechanical power, and the battery supplies \(\mathcal EI=\mathcal E^2/2R\).

Exercise 5.2A Daniell cell has \(\mathcal E\approx1.1\) V, and each zinc atom gives up two electrons. How much electrical energy is available per gram of zinc? Compare with about 30 kJ per gram from burning good coal. (Faraday constant \(96\,485\) C mol\(^{-1}\); molar mass of zinc 65.4 g mol\(^{-1}\).)

Show solution
Charge per gram: \(2\times96\,485/65.4\approx2950\) C. Energy: \(1.1\times2950\approx3.2\) kJ per gram, about a tenth of coal’s heat of combustion. Even a steam engine converting 10 percent of coal’s heat to work matches a perfect zinc motor per gram of fuel, and zinc cost many times more than coal.

Exercise 5.3An iron rod 1 m long has saturation magnetostriction \(\lambda\approx-7\times10^{-6}\) (polycrystalline iron contracts at high fields, though it lengthens at the moderate fields Joule used). What is the change in length? How does this compare with the thermal expansion of iron, coefficient \(1.2\times10^{-5}\ \mathrm K^{-1}\), for a 1 K change?

Show solution
\(\Delta\ell=7\times10^{-6}\) m \(=7\ \mu\)m. A 1 K change gives \(12\ \mu\)m. Joule had to keep the temperature of his rods steady to well under a degree to see the effect, and he read the length with a microscope and lever.
Lesson 06

The mechanical value of heat, 1843–1845

For the general reader. If heat is a substance, work cannot create it. Joule set out to show that work does create heat, always at the same rate of exchange. He used a generator, water forced through tubes, and air squeezed in a pump. Each method gave roughly the same number, and the agreement was the evidence.

Goals
  • Understand the magneto-electric experiment of 1843.
  • Compute the work of isothermal compression and compare it with the heat released.
  • See what the free expansion experiment proved.
  • State the first law and the role of the equivalent \(J\).

The magneto-electric experiment

A coil wound on an iron core rotated between the poles of an electromagnet, inside a tube of water. Joule measured the heat produced in the coil by the induced current, with the circuit closed through a galvanometer. The key point was that the induced current carried no heat from anywhere: the coil was the only place it could come from, and the only input was the mechanical work of turning. Running the machine with and without a battery in the circuit, and in both directions, he showed that a current induced by motion heats exactly as a battery current does. Turning the coil by falling weights, he related the heat to the work: 838 foot-pounds per pound of water per degree Fahrenheit.

Compression and expansion of air

In 1844 and 1845 Joule pumped air into a strong copper vessel immersed in water, measured the work of the pump and the heat given to the water, and then did the reverse, letting compressed air escape and measuring the cooling. For an ideal gas compressed slowly at temperature \(T\) from volume \(V_1\) to \(V_2\), the work done on the gas is

\[ W = \int_{V_2}^{V_1} p\,dV = nRT\ln\frac{V_1}{V_2} = p_1V_1\ln\frac{V_1}{V_2}. \]

If heat is a form of work, this work must appear as heat \(Q=W/J\) in the water. His results were close to 800 foot-pounds; the rarefaction experiments gave 795.

Free expansion

The decisive experiment of 1845 used two equal copper vessels joined by a stopcock, one filled with air at about 22 atmospheres, the other evacuated, both in one water bath. On opening the stopcock the air rushed into the empty vessel. The bath showed no measurable change of temperature. The expanding air did no external work, and it neither gained nor lost heat. When the vessels were placed in separate baths, the one losing gas cooled and the one gaining gas warmed, by equal amounts. On the caloric view the expansion of a gas ought to absorb heat in its own right. Joule concluded that a gas absorbs heat on expansion only to the extent that it does external work.

The first law (modern form)

For any system there is a function of state \(U\), the internal energy, such that in every process

\[ \Delta U = Q - W, \]

where \(Q\) is the heat supplied to the system and \(W\) the work done by it, both measured in the same unit. Before 1850 heat was measured in calories or British thermal units and work in foot-pounds or kilogram-metres; Joule’s equivalent \(J\) is the conversion factor, and his result is that \(J\) is a constant independent of the process. For an ideal gas, free expansion shows \(U=U(T)\), independent of volume.

Exercise 6.1Convert Joule’s 1843 value, 838 foot-pounds per pound of water per degree Fahrenheit, to joules per calorie. Compare with 4.186. (1 ft·lbf \(=1.3558\) J; 1 lb \(=453.59\) g; 1 °F \(=5/9\) K.)

Show solution
838 ft·lbf \(=1136.2\) J. Warming 1 lb by 1 °F needs \(453.59\times\tfrac59=252.0\) cal. So \(J=1136.2/252.0=4.51\) J/cal, about 8 percent high. The 770 from the water tubes gives \(4.14\), about 1 percent low.

Exercise 6.2A vessel of 2 litres contains air at 1 atm and 288 K. It is compressed isothermally to 0.2 L, ten times the original pressure. How much heat must flow into the bath? If the bath and vessel together are equivalent to 10 kg of water, how much does the bath warm?

Show solution
\(W=p_1V_1\ln(V_1/V_2)=1.013\times10^5\times2\times10^{-3}\times\ln10=466\) J. Since \(U\) depends only on \(T\), all of it leaves as heat. \(\Delta T=466/(10\times4186)=0.011\) K. Joule needed many strokes of the pump, high pressures and sensitive thermometers to see the effect.

Exercise 6.3For a van der Waals gas, \(U=nC_{V,m}T-an^2/V\). Find the temperature change in a free expansion from \(V_1\) to \(V_2\). For 1 mol of air (\(a=0.137\) Pa m\(^6\) mol\(^{-2}\), \(C_{V,m}=20.8\) J mol\(^{-1}\) K\(^{-1}\)) expanding from 1 L to 2 L, evaluate it. Why did Joule see nothing?

Show solution
\(\Delta U=0\) gives \(nC_{V,m}\Delta T=an^2(1/V_2-1/V_1)\), so \(\Delta T=-\frac{an}{C_{V,m}}\big(\frac1{V_1}-\frac1{V_2}\big)\). Numerically \(\Delta T=-\frac{0.137}{20.8}(1000-500)=-3.3\) K in the gas. But the gas’s heat capacity (about 21 J/K) is tiny next to that of a water bath (thousands of J/K), so the bath changes by a thousandth of a degree or less. Joule recognized this weakness, which led to the porous-plug method of Lesson 09.
Lesson 07

The paddle wheel, 1845–1850

For the general reader. The most famous experiment in the history of energy is also one of the simplest. Weights fall and turn a paddle wheel in a can of water; the water gets warmer. The difficulty is that the warming is about half a degree Fahrenheit. Joule built thermometers he could read to a two-hundredth of a degree, accounted for every loss, and obtained a number within one percent of today’s.

Goals
  • Describe the 1850 apparatus and its data reduction.
  • Estimate the corrections and the resulting precision.
  • Use the result to predict the warming of water at a waterfall.

The apparatus

In the final form described in the 1850 paper, a brass paddle wheel with eight sets of revolving arms turned between four sets of fixed vanes inside a copper vessel of water. The vanes stopped the water from rotating as a whole, so the work went into turbulent friction. Two lead weights of about 29 pounds each hung from cords wound on a wooden drum on the paddle axle. They fell about 63 inches, slowly, at roughly 2.4 inches per second. The drum was then disconnected, the weights wound up, and the fall repeated, twenty times per experiment, taking about 35 minutes. Each run of the apparatus was paired with a run without stirring to measure heat exchange with the room.

Reduction of the data

The work done on the water in one experiment is

\[ W = n\,(Mg\,h - \tfrac12 M v^2) - W_{\rm f}, \]

where \(n\) is the number of falls, \(M\) the total falling mass, \(h\) the height, \(v\) the landing speed and \(W_{\rm f}\) the work lost to friction in the pulleys and the stiffness of the cords, which Joule measured separately. The heat is

\[ Q = (m_{\rm w}c_{\rm w} + C_{\rm app})\,(\Delta T - \delta T_{\rm rad}), \]

with \(C_{\rm app}\) the heat capacity of the vessel and paddles, measured by Joule, and \(\delta T_{\rm rad}\) the correction from the paired run. Then \(J=W/Q\). Joule also corrected for the buoyancy of the air on the weights, giving values “in vacuo”.

Joule’s conclusions (1850)

(1) The quantity of heat produced by the friction of bodies, solid or liquid, is always proportional to the quantity of work expended. (2) The heat capable of raising one pound of water, weighed in vacuo between 55° and 60° F, by one degree Fahrenheit requires the work of 772 pounds falling through one foot.

He repeated the experiment with mercury and with cast-iron discs rubbing in mercury, getting values between about 772 and 776. He judged the water result, 772.692, the most reliable, and thought even that slightly high because some work went into vibration and sound.

Exercise 7.1Two weights of 29 lb each fall 63 inches, twenty times. Compute the work in foot-pounds. Joule’s corrected figure for one experiment was 6067 foot-pounds. What fraction did the corrections remove? Then estimate the kinetic energy lost at landing, using the speed 2.42 in/s.

Show solution
\(W=2\times29\times(63/12)\times20=6090\) ft·lbf. The correction is \(23/6090\approx0.4\) percent, mostly pulley friction. Kinetic energy per landing: \(v=0.202\) ft/s, \(\tfrac12(58/32.17)(0.202)^2=0.037\) ft·lbf, times 20 is 0.7 ft·lbf, about one part in \(10^4\). Joule included it anyway.

Exercise 7.2Suppose the vessel, water and paddles together are equivalent to 14 lb of water. What temperature rise does 6067 ft·lbf produce, using \(J=772\)? If the thermometer can be read to 1/200 °F, what is the best possible precision of a single run?

Show solution
\(Q=6067/772=7.86\) lb·°F, so \(\Delta T=7.86/14=0.56\) °F. A reading error of 0.005 °F at each end gives up to 0.01 °F, about 2 percent of 0.56. Averaging many runs and pairing them with radiation runs brought Joule’s final result to well under 1 percent.

Exercise 7.3Joule suggested that water falling at Niagara, about 160 feet, should be warmed. Using his 1845 figure of 817 ft·lbf per lb·°F, and then the modern value, find the warming in °F and in kelvin.

Show solution
A pound falling 160 ft releases 160 ft·lbf. With 817: \(160/817=0.196\) °F, the fifth of a degree he quoted. With the modern 778.2: \(0.206\) °F \(=0.114\) K. In SI, \(\Delta T=gh/c=9.81\times48.8/4186=0.114\) K. Spray, evaporation and mixing make it hard to observe.
Lesson 08

The speed of gas molecules

For the general reader. If heat is motion, the pressure of a gas could be the drumming of its particles on the walls. Joule took this idea from John Herapath and computed, from the pressure and density of hydrogen, how fast its particles must move. The answer, over six thousand feet per second, was the first numerical estimate of a molecular speed.

Goals
  • Derive \(p=\tfrac13\rho\overline{v^2}\).
  • Reproduce Joule’s speed for hydrogen.
  • See how the model gives an absolute zero and a specific heat, and where it fails.

Pressure from impacts

Joule’s paper Some Remarks on Heat and the Constitution of Elastic Fluids, published in 1851, imagined a cube of gas whose particles move in three groups, one along each axis. A particle of mass \(m\) moving along \(x\) with speed \(v\) between walls a distance \(L\) apart strikes one wall every \(2L/v\) seconds, delivering momentum \(2mv\) each time. The force on the wall is \(mv^2/L\). With \(N\) particles, one third along each axis, the pressure on a wall of area \(L^2\) is

\[ p=\frac{1}{L^2}\cdot\frac{N}{3}\cdot\frac{mv^2}{L}=\frac13\,\rho\,v^2, \qquad \rho=\frac{Nm}{L^3}. \]
Proposition (kinetic pressure)

For a gas of non-interacting particles with an isotropic distribution of velocities, \(p=\tfrac13\rho\,\overline{v^2}\), so the root-mean-square speed is \(v_{\rm rms}=\sqrt{3p/\rho}\). The three-beam model gives the same result as a full average over directions.

Joule took a cubic foot of hydrogen at 60 °F and 30 inches of mercury and found a speed of 6225 feet per second. At the freezing point he obtained 6055. Since \(p\propto\rho v^2\) and, for a fixed density, \(p\) is proportional to the absolute temperature, \(v^2\) must vanish at the absolute zero. From the expansion of gases he placed it 491 °F below the freezing point of water, that is, at \(-459\) °F.

Exercise 8.1Hydrogen at 15.6 °C (60 °F) and 1 atm has density 0.0852 kg m\(^{-3}\). Compute \(v_{\rm rms}\) in m/s and ft/s and compare with Joule. Then compute it for oxygen at the same temperature.

Show solution
\(v_{\rm rms}=\sqrt{3\times1.013\times10^5/0.0852}=1889\) m/s \(=6200\) ft/s, within half a percent of Joule’s 6225. Oxygen is 16 times heavier per molecule, so its speed is 4 times smaller: 472 m/s.

Exercise 8.2In this model the internal energy per unit mass is \(\tfrac12\overline{v^2}=\tfrac32p/\rho\). Show that the specific heat at constant volume is \(c_V=\tfrac32R/M\). Evaluate it for hydrogen (\(M=2.016\) g/mol) relative to water, and compare with the measured value of about 2.4. What does the discrepancy mean?

Show solution
\(p/\rho=RT/M\), so \(u=\tfrac32RT/M\) and \(c_V=\tfrac32R/M=1.5\times8.314/0.002016=6190\) J kg\(^{-1}\) K\(^{-1}\), or 1.48 relative to water. The measured \(c_V\) of hydrogen is about 10.2 kJ kg\(^{-1}\) K\(^{-1}\), or 2.4. The extra comes from the rotation of the diatomic molecules, which Clausius pointed out in 1857; equipartition gives \(\tfrac52R/M\), i.e. 2.46.
Lesson 09

The Joule–Thomson effect

For the general reader. Joule’s free-expansion test was too crude to detect small forces between gas molecules. With William Thomson he designed a better one: push gas steadily through a plug of cotton or silk from high pressure to low, and measure its temperature on both sides. Most gases come out slightly cooler. The effect, repeated in stages, later made it possible to liquefy air.

Goals
  • Show that throttling conserves enthalpy.
  • Derive the Joule–Thomson coefficient.
  • Find the inversion temperature of a van der Waals gas.

Throttling

Gas flows steadily through an insulated porous plug. Follow a fixed amount of gas that occupies volume \(V_1\) at pressure \(p_1\) before the plug and \(V_2\) at \(p_2\) after. The gas behind pushes it in, doing work \(p_1V_1\); it pushes the gas ahead, doing work \(p_2V_2\). No heat flows and the kinetic energy of the slow flow is negligible, so

\[ U_2-U_1=p_1V_1-p_2V_2 \quad\Longrightarrow\quad H_1=H_2,\qquad H=U+pV. \]
Proposition (Joule–Thomson coefficient)

The temperature change per unit pressure drop at constant enthalpy is

\[ \mu_{\rm JT}=\Big(\frac{\partial T}{\partial p}\Big)_H=\frac{1}{C_p}\Big[T\Big(\frac{\partial V}{\partial T}\Big)_p-V\Big]. \]

It vanishes for an ideal gas. Where \(\mu_{\rm JT}>0\) the gas cools on expansion.

Derivation. From \(dH=T\,dS+V\,dp\) and \(dS=\frac{C_p}{T}dT-\big(\frac{\partial V}{\partial T}\big)_p dp\) (a Maxwell relation), \(dH=C_p\,dT+\big[V-T\big(\frac{\partial V}{\partial T}\big)_p\big]dp\). Setting \(dH=0\) gives the formula.

Joule and Thomson began the experiments in 1852 and published them in a series of papers On the Thermal Effects of Fluids in Motion. Air and carbon dioxide cooled; hydrogen, at room temperature, warmed very slightly. The measurements also allowed them to compare the gas thermometer with Thomson’s absolute scale of temperature (see the Kelvin module).

Van der Waals estimate

For a dilute van der Waals gas, to first order in \(a\) and \(b\), \(V_m\approx RT/p+b-a/RT\). Then

\[ \mu_{\rm JT}\approx\frac{1}{C_{p,m}}\Big(\frac{2a}{RT}-b\Big), \qquad T_{\rm inv}=\frac{2a}{Rb}. \]

Below \(T_{\rm inv}\) attraction dominates and the gas cools; above it, the finite size of the molecules dominates and it warms.

Exercise 9.1Derive \(\mu_{\rm JT}\) for the dilute van der Waals gas from the approximate \(V_m\) above.

Show solution
\(\big(\partial V_m/\partial T\big)_p=R/p+a/RT^2\). So \(T(\partial V_m/\partial T)_p-V_m=RT/p+a/RT-RT/p-b+a/RT=2a/RT-b\). Divide by \(C_{p,m}\).

Exercise 9.2For nitrogen, \(a=0.137\) Pa m\(^6\) mol\(^{-2}\), \(b=3.87\times10^{-5}\) m\(^3\) mol\(^{-1}\), \(C_{p,m}=29.1\) J mol\(^{-1}\) K\(^{-1}\). Estimate \(\mu_{\rm JT}\) at 300 K in K/atm and the inversion temperature. For hydrogen, \(a=0.0248\), \(b=2.66\times10^{-5}\): find \(T_{\rm inv}\) and explain Joule and Thomson’s observation.

Show solution
Nitrogen: \(2a/RT=0.274/2494=1.10\times10^{-4}\), minus \(b\) gives \(7.1\times10^{-5}\) m\(^3\)/mol; divided by 29.1, \(\mu\approx2.4\times10^{-6}\) K/Pa \(\approx0.25\) K/atm (measured about 0.2). \(T_{\rm inv}=0.274/(8.314\times3.87\times10^{-5})\approx850\) K (measured about 620 K). Hydrogen: \(T_{\rm inv}=0.0496/(8.314\times2.66\times10^{-5})\approx224\) K (measured about 200 K). Room temperature is above it, so hydrogen warms, as observed. It must be precooled, for example with liquid nitrogen, before throttling can liquefy it.
Lesson 10

From the equivalent to the joule

For the general reader. Joule measured a conversion factor between two units, one for heat and one for work. Once his result was accepted, heat was understood as energy, and the factor could be absorbed into the definition of the units. Today the joule measures all energy, and the calorie survives only as a defined multiple of it.

Goals
  • Convert Joule’s results to SI and assess their accuracy.
  • Follow how the unit called the joule was introduced.
  • Understand why the specific heat of water made the calorie ambiguous.

Joule’s numbers in modern units

One British thermal unit, the heat that warms one pound of water by one degree Fahrenheit, corresponds today to about 778.2 ft·lbf. Joule’s determinations, in foot-pounds per pound-degree Fahrenheit, were:

1843Magneto-electric: 838 (8 percent high). Water through tubes: 770.
1845Rarefaction of air: 795. Paddle wheel, first trial: 890. Mean of methods: 817.
1847Paddle wheel with water, sperm oil, mercury: 781.5, 782.1, 787.6.
1850Paddle wheel, water: 772.692 (0.7 percent low).
1878Final determination: 772.55.

The agreement among methods mattered more than any single figure. In 1879 the American physicist Henry Rowland repeated the stirring experiment on a larger scale, driving the paddles with an engine, and showed that the specific heat of water varies by a fraction of a percent over the ordinary range of temperatures. A calorie therefore depends on which degree of the thermometer it refers to.

Units of energy

The joule is the work done by a force of one newton through one metre: \(1\ \mathrm J=1\ \mathrm{kg\,m^2\,s^{-2}}=10^7\) erg. The calories in use are defined multiples: the thermochemical calorie is \(4.184\) J exactly, the International Table calorie \(4.1868\) J exactly. The fifteen-degree calorie, the heat to warm 1 g of water from 14.5 °C to 15.5 °C, is about \(4.1855\) J.

William Siemens proposed the name joule for \(10^7\) erg at the British Association in 1882. The International Electrical Congress adopted it, with the watt, on 31 August 1889, six weeks before Joule’s death. In 1948 the General Conference on Weights and Measures chose the joule as the unit of heat and discouraged use of the calorie.

Exercise 10.1Convert 772.692 and 772.55 ft·lbf per lb·°F to joules per International Table calorie. (1 Btu \(=1055.06\) J \(=251.996\) cal\(_{\rm IT}\); 1 ft·lbf \(=1.355\,818\) J.)

Show solution
\(772.692\times1.355\,818=1047.6\) J, divided by 251.996 gives 4.157 J/cal. For 772.55, 4.156 J/cal. Both are about 0.7 percent below 4.1868.

Exercise 10.2A food label states 250 kcal per serving. How high could a 70 kg person climb on that energy if muscles convert 25 percent of it to work? Joule would have put this as a question about the mechanical equivalent of food.

Show solution
\(250\) kcal \(=250\times4184=1.05\times10^6\) J; a quarter is \(2.6\times10^5\) J. Height \(=2.6\times10^5/(70\times9.81)\approx380\) m.
Part III · Life and legacy
Lesson 11

Recognition and partnership, 1848–1870

Within three years of the Oxford meeting the scientific world had changed its mind. In 1850 the Royal Society published Joule’s paddle-wheel paper in its Philosophical Transactions and elected him a Fellow. In the same year Rudolf Clausius in Berlin, and in 1851 William Thomson in Glasgow, combined Joule’s equivalence of heat and work with Carnot’s principle and founded thermodynamics on two laws. The Royal Society gave Joule a Royal Medal in 1852.

Joule and Thomson

The collaboration with Thomson began in 1852. Joule did the experiments in Manchester; Thomson supplied theory and much of the planning, by letter. Their porous-plug experiments (Lesson 09) were the most lasting result. They also compared the air thermometer with Thomson’s absolute scale and studied the heating of bodies moving rapidly through air. The partnership was one between equals of very different kinds: a private experimenter and a professor of mathematical physics.

Loss and change

Joule and Amelia had three children: Benjamin Arthur (1850–1922), Alice Amelia (1852–1899) and Joe, born in 1854, who lived only three weeks. Amelia died in 1854. The same year the family brewery was sold. Joule lived on private means and continued to experiment in a laboratory at home. He received honorary degrees from Trinity College Dublin (1857), Oxford (1860) and Edinburgh (1871). He served the Manchester Literary and Philosophical Society as secretary and, several times from 1860, as president.

Mayer and the priority question

In 1848 Joule learned that the German physician Julius Robert Mayer had stated the equivalence of heat and work in 1842 and computed a value from the properties of gases. A short exchange in the Paris Comptes rendus followed. Joule argued that a number deduced from gas data without experiment was a hypothesis; Mayer replied that the idea and its first numerical expression were his. In 1862 John Tyndall championed Mayer at the Royal Institution, and Thomson and Peter Guthrie Tait answered in Joule’s defence, which turned the matter into a dispute between British and German science. Joule himself was more measured. The Royal Society gave him the Copley Medal in 1870 and gave it to Mayer the next year.

DiscussionMayer had the principle first; Joule had the measurements. Thomas Kuhn later counted at least a dozen people who, between 1830 and 1850, grasped parts of energy conservation. What should “discovery” mean when an idea emerges in several places at once, and how did each man’s social position affect his reception?

Lesson 12

Last years and legacy, 1870–1889

Joule kept experimenting into the 1870s, refining thermometers and returning to the equivalent of heat. In 1878 he published a final determination by the paddle-wheel method, 772.55 foot-pounds. That year the government granted him a civil list pension of £200 a year, his private income having fallen. The Royal Society of Arts gave him its Albert Medal in 1880. The Physical Society of London published his collected papers in two volumes, in 1884 and 1887.

His health declined through the 1880s. He died at his home in Sale, Cheshire, on 11 October 1889, aged 70, and was buried in Brooklands cemetery in Sale. His gravestone is inscribed with the number 772.55. A memorial stands in the north choir aisle of Westminster Abbey, and a marble statue by Alfred Gilbert in Manchester Town Hall.

Legacy

  • Energy: the experimental basis of the first law of thermodynamics, and with it the end of the caloric theory.
  • Electricity: Joule heating, \(I^2R\), in every circuit design and in the theory of power transmission.
  • Gases: free expansion, the first molecular speed, and with Thomson the throttling effect behind refrigeration and gas liquefaction.
  • Method: precision measurement as a route to principle. Joule showed that a fraction of a degree, measured reliably, could decide a question of natural philosophy.
  • Units: the joule, the SI unit of energy, work and heat.

Final projectWrite a two-page laboratory proposal to repeat Joule’s paddle-wheel measurement with modern equipment (an electric motor and torque sensor, a platinum resistance thermometer). Estimate each source of error, and say what precision you could reach and what would limit it.

Reference

Connections

People linked to James Prescott Joule across this collection. A name without a link has no page here yet. See James Prescott Joule in the network of all 337 lives →

Teachers and advisors

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Influenced

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Reference

Sources and further reading

Biography

  1. James Prescott Joule, Wikipedia.
  2. James Prescott Joule, New World Encyclopedia.
  3. James Prescott Joule, Encyclopaedia Britannica.
  4. D. S. L. Cardwell, James Joule: A Biography, Manchester University Press, 1989.
  5. O. Reynolds, Memoir of James Prescott Joule, Manchester Literary and Philosophical Society, 1892.
  6. H. O. Sibum, Reworking the mechanical value of heat: instruments of precision and gestures of accuracy in early Victorian England, Stud. Hist. Phil. Sci. 26 (1995) 73–106.

Physics

  1. J. P. Joule, On the heat evolved by metallic conductors of electricity, and in the cells of a battery during electrolysis, Phil. Mag. 19 (1841) 260.
  2. J. P. Joule, On the calorific effects of magneto-electricity, and on the mechanical value of heat, Phil. Mag. 23 (1843).
  3. J. P. Joule, On the existence of an equivalent relation between heat and the ordinary forms of mechanical power, Phil. Mag. 27 (1845) 205. Text at ChemTeam.
  4. J. P. Joule, On the mechanical equivalent of heat, Phil. Trans. R. Soc. 140 (1850) 61–82. OCR text.
  5. J. P. Joule, Some remarks on heat and the constitution of elastic fluids (1851). Excerpt, Classic Chemistry, Le Moyne College.
  6. J. P. Joule and W. Thomson, On the thermal effects of fluids in motion, Phil. Trans. R. Soc. (1853–1862).
  7. The Scientific Papers of James Prescott Joule, 2 vols., Physical Society of London, 1884–1887.
  8. T. S. Kuhn, Energy conservation as an example of simultaneous discovery, in M. Clagett (ed.), Critical Problems in the History of Science, University of Wisconsin Press, 1959.
  9. Mechanical equivalent of heat and Joule (unit), Wikipedia.