courseshub.world · Lives in Mathematics and Physics

Lazare Carnot

Lazare Nicolas Marguerite Carnot

A course in two strands: the life of the engineer officer who organized the armies of the French Revolution, and the mechanics of machines, the theory of shocks and the geometry of position that he wrote between campaigns.

Born 13 May 1753, Nolay Died 2 August 1823, Magdeburg Committee of Public Safety 1793–1794 Level advanced undergraduate
Carnot’s theorem. The perpendiculars from the circumcentre O to the three sides add up to R + r, the circumradius plus the inradius.
Lesson 00

How to use this course

Lazare Carnot is remembered in France as the “organizer of victory”, the member of the Committee of Public Safety who raised, armed and directed the armies of the Republic in 1793 and 1794. He was also a serious scientist. His essay on machines of 1783 was the first theoretical treatise of engineering mechanics, and it contains a theorem on the loss of live force in collisions that still bears his name. His books on geometry helped launch the modern study of signed magnitudes and projective configurations, and his son Sadi built thermodynamics on ideas taken from his father’s mechanics.

Prerequisites for Part II
  • Newtonian mechanics: momentum, kinetic energy, work, constraints.
  • Elementary vectors and the scalar product.
  • Euclidean geometry of the triangle and its circles; the theorems of Menelaus and Ceva.
  • For Lesson 07, a first course in calculus and the idea of a limit.

Each technical lesson opens with an italic paragraph for the general reader, then gives precise statements in modern notation, derivations, and exercises with folded solutions. Carnot’s own notation was verbal and cumbersome; where we translate, we say so.

Reference

Timeline

1753Born 13 May at Nolay, Burgundy, son of the notary and judge Claude Carnot and Marguerite Pothier.
1767Enters the Oratorian college at Autun; later studies at the seminary of Autun.
1771Third in the entrance examination for the Royal Engineering School at Mézières, where Gaspard Monge teaches.
1773Graduates 1 January as first lieutenant in the engineer corps.
1777–80Memoir on machines for the Paris Academy prize; honourable mention.
1783Essai sur les machines en général. Promoted captain in December.
1784Prize of the Dijon Academy for his Éloge de Vauban.
1785–86Entry to the Berlin Academy prize on the theory of the infinite; honourable mention.
1791Marries Sophie Dupont, 17 May. Elected to the Legislative Assembly.
1792Elected to the National Convention.
1793Votes for the death of Louis XVI. Joins the Committee of Public Safety on 14 August. With Jourdan wins the battle of Wattignies in October.
1794Survives the fall of Robespierre; leaves the Committee in October. Takes part in founding the École polytechnique.
1795–97One of the five Directors. Member of the new Institut. Son Sadi born 1 June 1796.
1797Flees after the coup of 18 Fructidor (4 September); exile in Switzerland and Germany.
1797Réflexions sur la métaphysique du calcul infinitésimal.
1800Returns; Minister of War, 2 April – 8 October.
1801De la corrélation des figures de géométrie. Son Hippolyte born.
1802Tribune; votes against the life consulship, and in 1804 against the Empire.
1803Géométrie de position; Principes fondamentaux de l’équilibre et du mouvement.
1806Memoir on the distances between five points, with an essay on transversals.
1809De la défense des places fortes.
1814Governor of Antwerp; holds the city until ordered to surrender after Napoleon’s abdication.
1815Minister of the Interior in the Hundred Days, 20 March – 22 June; count and peer.
1816Exiled as a regicide; Warsaw, then Magdeburg from November.
1823Dies at Magdeburg, 2 August.
1889His remains are transferred to the Panthéon in Paris.
Part I · Formation
Lesson 01

Nolay and Autun, 1753–1771

Lazare Nicolas Marguerite Carnot was born on 13 May 1753 at Nolay, a small town in Burgundy between Beaune and Autun. His father, Claude Carnot, was a notary and local judge; his mother was Marguerite Pothier. The family was large, and several brothers had public careers. Lazare and his brother Claude-Marie both entered the army as engineers.

At fourteen he went to the college at Autun run by the Oratorians, a teaching order known for its attention to mathematics and the sciences. He then studied at the Sulpician seminary in Autun, where he read logic, theology and mathematics. The Church was a possible path, but his father steered both sons toward the technical corps of the army, one of the few routes by which a family of the provincial bourgeoisie could reach a commission.

To prepare for the entrance examination of the engineering school he spent time at a preparatory school in Paris. There he came to the notice of Jean le Rond d’Alembert, whose Traité de dynamique would later shape his mechanics. In February 1771 he placed third in the examination.

Lesson 02

Mézières and the engineer corps, 1771–1789

The École royale du génie at Mézières was the best technical school in Europe. Students learned fortification, surveying, stone-cutting, hydraulics and mechanics. Its most famous teacher, Gaspard Monge, was developing descriptive geometry there, a method for representing three-dimensional objects by projections that the army kept secret for years. Carnot graduated on 1 January 1773 as a first lieutenant and was posted to garrison towns in the north and east, including Calais, Cherbourg and Arras.

Garrison life left time for study. In 1777 the Paris Academy of Sciences set a prize question on the theory of simple machines, including friction and the stiffness of ropes. Carnot submitted a memoir, revised it for a second round in 1780, and received an honourable mention; the prize went to Charles-Augustin de Coulomb for his study of friction. Carnot published the theoretical part as the Essai sur les machines en général in 1783, and a second printing under his name followed in 1786. It is the subject of Lessons 04 to 06.

In 1784 he won the prize of the Dijon Academy for a eulogy of Vauban, the great military engineer of Louis XIV, which defended walled fortresses against the fashion for mobile field armies. He also entered the Berlin Academy’s competition on the theory of the infinite in mathematics, set in 1784; his entry received an honourable mention and became, much revised, the Réflexions of 1797 (Lesson 07). He was promoted captain in December 1783 and elected to the Dijon Academy in 1787.

In Arras he joined a literary society, the Rosati, among whose members was the young lawyer Maximilien Robespierre. In 1790 he was injured in a riding accident and nursed by Sophie Dupont, from a family of Saint-Omer; they married on 17 May 1791.

Lesson 03

The organizer of victory, 1789–1797

The Revolution opened politics to men like Carnot. In 1791 the Pas-de-Calais elected him to the Legislative Assembly, where he sat on the committee for public instruction and on military committees. In 1792 he was elected to the National Convention. In January 1793 he voted for the death of Louis XVI, the vote that later made him a proscribed regicide.

France was then at war with most of Europe. Carnot was sent on mission to the armies, and on 14 August 1793 he joined the Committee of Public Safety, the twelve-member executive of the Terror, with responsibility for war. Together with Prieur de la Côte-d’Or, also an engineer, he turned the mass levy of August 1793 into an organized army: he planned campaigns, standardized supply, promoted young officers on merit and pressed for concentrated offensives. In October 1793 he was at the front with Jean-Baptiste Jourdan for the victory of Wattignies, which relieved the siege of Maubeuge. By 1794 the Republic had more than half a million men under arms, and the invasions had been turned back. The Convention’s phrase for him, the organizer of victory, stuck.

He signed many of the Committee’s orders, including some of the Terror’s, but his work was the war, and he clashed with Robespierre and Saint-Just. He survived the fall of Robespierre in July 1794 and left the Committee in October. With Monge and others he took part in founding the École centrale des travaux publics, soon renamed the École polytechnique, which became the nursery of French science and engineering.

In November 1795 he became one of the five Directors who ruled France under the new constitution, and in 1796 he presided over the Directory. He supported the appointment of Napoleon Bonaparte to command the Army of Italy. Moderate by now, he lost the struggle with his fellow Directors, and in the coup of 18 Fructidor (4 September 1797) he was proscribed. He escaped to Switzerland and then to Germany. At the Institut, where he had sat in the mechanical arts section, he was struck off and replaced by Bonaparte.

Part II · Mechanics and geometry
Lesson 04

Machines, live force and work

For the general reader. Eighteenth-century engineers wanted to know how much a water wheel, a pulley or a pump could really do. Carnot’s answer was that a machine only transmits motion; it creates nothing. What it transmits is measured by force times distance, a quantity he called the moment of activity and we call work. The best machine is the one that loses least of it.

Goals
  • Define a machine abstractly, as Carnot did.
  • Derive the work–energy relation and its use for machines.
  • Explain why “no machine can give out more work than it receives”.

Carnot’s definition

Carnot defined a machine as an intermediary body or system that transmits motion between bodies, the movers and the resistances, that do not act on one another directly. His theory therefore ignored the detailed construction of the machine and asked only about the relations between the motions it permits. This abstraction is the origin of the idea, later central to engineering mechanics, that machines can be compared by energy accounting alone.

Live force and moment of activity

Carnot used the live force (vis viva) \(\sum m v^2\) of Leibniz and the Bernoullis. A weight \(P=mg\) raised through height \(h\) requires a “moment of activity” \(Ph\), and a body falling freely through \(h\) gains \(v^2=2gh\). In modern form:

Work–energy theorem

For a system of particles with masses \(m_i\), velocities \(\mathbf v_i\) and total forces \(\mathbf F_i\),

\[ \frac{d}{dt}\sum_i\tfrac12 m_i\lvert\mathbf v_i\rvert^2=\sum_i\mathbf F_i\cdot\mathbf v_i,\qquad\text{so}\qquad \Delta\Big(\sum_i\tfrac12m_iv_i^2\Big)=\sum_i\int\mathbf F_i\cdot d\mathbf r_i. \]

If the constraint forces do no work and the applied forces derive from a potential \(V\), then \(\sum\tfrac12m_iv_i^2+V\) is constant.

Proof. Dot Newton’s law \(m_i\dot{\mathbf v}_i=\mathbf F_i\) with \(\mathbf v_i\) and sum; the left side is the time derivative of the kinetic energy. Integrate in time. \(\square\)

Applied to a machine working in a steady cycle, with movers doing work \(W_{\text{in}}\) and resistances absorbing \(W_{\text{out}}\), the kinetic energy returns to its initial value, so \(W_{\text{in}}=W_{\text{out}}+W_{\text{lost}}\), with \(W_{\text{lost}}\ge0\) for friction and shocks. Gaspard-Gustave Coriolis proposed the word travail (work) for Carnot’s moment of activity in 1829, and the factor \(\tfrac12\) in kinetic energy became standard at the same time.

Exercise 4.1A water wheel receives 120 litres of water per second falling through 3 m. What is the greatest power it could deliver?

Show solution
Mass flow 120 kg/s; power \(=\dot m g h=120\times9.81\times3\approx3.5\ \mathrm{kW}\). Any real wheel delivers less, because of shocks at entry and kinetic energy left in the outflow (Lesson 06).

Exercise 4.2A frictionless lever with arms \(a\) and \(b\) balances weights \(P\) and \(Q\). Use work, as Carnot would, to derive \(Pa=Qb\).

Show solution
Rotate the lever by a small angle \(\delta\varphi\): \(P\) descends \(a\,\delta\varphi\) and \(Q\) rises \(b\,\delta\varphi\). In equilibrium the work done by the movers equals that absorbed: \(Pa\,\delta\varphi=Qb\,\delta\varphi\), so \(Pa=Qb\).
Lesson 05

Geometric motions

For the general reader. A lever can only turn, a piston can only slide. Carnot called the motions that a system’s shape allows, whatever forces are acting, its geometric motions. He showed that the laws of equilibrium and of impact can be read off by testing forces against these motions. The idea is very close to the virtual displacements of Lagrange, and Carnot reached it independently in the language of an engineer.

Goals
  • Define geometric motions for systems with reversible constraints.
  • State Carnot’s principle of equilibrium and compare it with virtual work.
  • Derive conservation of momentum and angular momentum from rigid geometric motions.

Definition

Consider particles at positions \(\mathbf r_i\) subject to ideal constraints. A set of velocities \(\mathbf u_i\) is a geometric motion if the system could move with those velocities without violating the constraints, and if the reversed velocities \(-\mathbf u_i\) are also allowed. In his 1803 Principes fondamentaux, Carnot characterized these as motions during which the constraints do no work. In modern terms, the \(\mathbf u_i\) form the tangent space of the configuration manifold, the reversible virtual velocities.

Principle (Carnot 1783; compare Lagrange 1788)

Let \(\mathbf R_i\) be the constraint forces. For ideal constraints, \(\sum_i\mathbf R_i\cdot\mathbf u_i=0\) for every geometric motion \(\mathbf u\). Consequently, a system subject to applied forces \(\mathbf F_i\) is in equilibrium if and only if

\[ \sum_i\mathbf F_i\cdot\mathbf u_i=0\quad\text{for every geometric motion }\mathbf u. \]

Carnot’s own fundamental equation, for systems of hard bodies, was written with the velocities “lost” in the motion. If \(\mathbf v_i\) is the velocity a body would have had and \(\mathbf w_i\) the velocity it actually has, the lost velocity is \(\mathbf v_i-\mathbf w_i\), and

\[ \sum_i m_i(\mathbf v_i-\mathbf w_i)\cdot\mathbf u_i=0\quad\text{for every geometric motion }\mathbf u. \]

This is a version of d’Alembert’s principle: the lost motions would be in equilibrium among themselves.

Conservation laws from rigid motions

For a free system with internal constraints only, any rigid translation \(\mathbf u_i=\mathbf a\) and any rigid rotation \(\mathbf u_i=\boldsymbol\omega\times\mathbf r_i\) is a geometric motion. Inserting them in the fundamental equation gives conservation of momentum and angular momentum across impulsive interactions. Carnot obtained the conservation of moment of momentum this way.

Exercise 5.1Two beads of masses \(m_1,m_2\) on a smooth horizontal wire are joined by a rigid rod. Describe the geometric motions and use the principle to find when forces \(F_1,F_2\) along the wire are in equilibrium.

Show solution
The rod forces equal velocities, so the geometric motions are \(u_1=u_2=u\). Equilibrium requires \(F_1u+F_2u=0\) for all \(u\), that is, \(F_1+F_2=0\).

Exercise 5.2Show that, for a free system of particles, taking \(\mathbf u_i=\boldsymbol\omega\times\mathbf r_i\) in Carnot’s fundamental equation gives conservation of total angular momentum during an internal impact.

Show solution
With \(\mathbf v_i,\mathbf w_i\) the velocities before and after impact, \(\sum m_i(\mathbf v_i-\mathbf w_i)\cdot(\boldsymbol\omega\times\mathbf r_i)=\boldsymbol\omega\cdot\sum m_i\mathbf r_i\times(\mathbf v_i-\mathbf w_i)=0\) for every \(\boldsymbol\omega\). Hence \(\sum m_i\mathbf r_i\times\mathbf v_i=\sum m_i\mathbf r_i\times\mathbf w_i\).
Lesson 06

Carnot’s theorem on shocks

For the general reader. When two lumps of clay collide and stick, momentum survives but some motion disappears into heat and deformation. Carnot found an exact formula for the loss: it equals the kinetic energy that the bodies would have if they moved with the velocities they lost. The same formula, applied to water suddenly widening in a pipe, gives the loss of head that engineers call the Borda–Carnot equation.

Goals
  • State and prove Carnot’s theorem for inelastic impacts.
  • Apply it to collisions and to sudden expansions in pipes.
  • Draw the engineering moral: avoid shocks.
Theorem (Carnot, 1783)

Let a system of “hard” bodies (perfectly inelastic, with ideal constraints) undergo a sudden impact in which the velocities jump from \(\mathbf v_i\) to \(\mathbf w_i\), and suppose the post-impact velocities \(\mathbf w_i\) form a geometric motion. Then

\[ \sum_i m_i\lvert\mathbf v_i\rvert^2=\sum_i m_i\lvert\mathbf w_i\rvert^2+\sum_i m_i\lvert\mathbf v_i-\mathbf w_i\rvert^2. \]

The live force lost in the shock equals the live force of the lost velocities.

Proof. In a perfectly inelastic impact the bodies end up moving together in a way the constraints allow, so \(\mathbf w\) is a geometric motion. The impulsive internal forces are \(m_i(\mathbf w_i-\mathbf v_i)\), and by the principle of Lesson 05 they do no work on a geometric motion: \(\sum m_i(\mathbf v_i-\mathbf w_i)\cdot\mathbf w_i=0\). Now expand

\[ \sum m_i\lvert\mathbf v_i\rvert^2=\sum m_i\lvert\mathbf w_i+(\mathbf v_i-\mathbf w_i)\rvert^2=\sum m_i\lvert\mathbf w_i\rvert^2+2\sum m_i\mathbf w_i\cdot(\mathbf v_i-\mathbf w_i)+\sum m_i\lvert\mathbf v_i-\mathbf w_i\rvert^2, \]

and the middle term vanishes. \(\square\)

The identity is a Pythagorean decomposition. With the mass-weighted inner product \(\langle\mathbf a,\mathbf b\rangle=\sum m_i\mathbf a_i\cdot\mathbf b_i\), the post-impact velocity \(\mathbf w\) is the orthogonal projection of \(\mathbf v\) onto the subspace of geometric motions. So the shock always loses energy, and loses none only if the motion was already compatible with the constraints. Carnot drew the engineering conclusion that a machine should transmit motion gradually, without percussion.

The Borda–Carnot equation

When an incompressible fluid flowing at speed \(v_1\) in a pipe passes a sudden enlargement into a pipe where its speed is \(v_2<v_1\), the fast stream collides with the slower fluid. Momentum balance on the control volume, with the upstream pressure acting over the large section, gives the mechanical energy lost per unit volume,

\[ \Delta E=\tfrac12\rho\,(v_1-v_2)^2, \]

the “kinetic energy of the lost velocity”. Jean-Charles de Borda had found this result in 1766; Carnot’s theorem explains it as an instance of a general law.

Exercise 6.1A mass \(m_1\) moving at speed \(V\) strikes a mass \(m_2\) at rest, and they stick. Verify Carnot’s theorem directly.

Show solution
Momentum gives \(w=\frac{m_1V}{m_1+m_2}\). Lost velocities: \(V-w=\frac{m_2V}{m_1+m_2}\) for body 1 and \(0-w\) for body 2. Their live force is \(m_1\frac{m_2^2V^2}{(m_1+m_2)^2}+m_2\frac{m_1^2V^2}{(m_1+m_2)^2}=\frac{m_1m_2V^2}{m_1+m_2}\). And \(m_1V^2-(m_1+m_2)w^2=m_1V^2\big(1-\frac{m_1}{m_1+m_2}\big)=\frac{m_1m_2V^2}{m_1+m_2}\). They agree.

Exercise 6.2Water flows at \(4\ \mathrm{m/s}\) in a pipe of section \(A_1\), which suddenly widens to \(A_2=4A_1\). Find the head loss \(\Delta E/\rho g\).

Show solution
Continuity gives \(v_2=1\ \mathrm{m/s}\). Head loss \(=(v_1-v_2)^2/2g=9/19.6\approx0.46\ \mathrm m\). A gradual diffuser recovers most of it, which is Carnot’s advice in hydraulic form.

Exercise 6.3Show that Carnot’s theorem fails for a perfectly elastic collision, and explain which hypothesis is violated.

Show solution
In an elastic collision kinetic energy is conserved, but the lost velocities are non-zero, so the right side exceeds the left. The hypothesis that fails is that \(\mathbf w\) is a geometric motion: after an elastic impact the bodies separate, so the constraint “move together” no longer holds and the impulses do work on \(\mathbf w\).
Lesson 07

The metaphysics of the calculus

For the general reader. Eighteenth-century calculus worked, but no one could say why. Infinitely small quantities were treated as zero when convenient and as non-zero otherwise, and George Berkeley had mocked them as the “ghosts of departed quantities”. Carnot argued that the method is exact because its errors cancel: one deliberately makes two small mistakes whose effects compensate, and the final equation contains no trace of either.

Goals
  • State Carnot’s principle of compensation of errors.
  • Work a classical example in his style and in limit language.
  • Place his view between Leibnizian infinitesimals and Cauchy’s limits.

Compensation of errors

The Réflexions sur la métaphysique du calcul infinitésimal (1797, much expanded 1813) grew from Carnot’s entry to the Berlin prize. Its central thesis can be put as follows.

Carnot’s principle (paraphrased)

Suppose an exact relation between finite quantities is sought. Introduce auxiliary quantities that may be taken as small as one wishes, and write an equation that is only approximately true, with an error that can be made arbitrarily small. If, after the auxiliary quantities are eliminated, the resulting relation involves only fixed quantities, then it is exactly true: a fixed relation that holds to within every positive error holds with no error.

In modern terms, if two fixed numbers \(A\) and \(B\) satisfy \(\lvert A-B\rvert<\varepsilon\) for every \(\varepsilon>0\), then \(A=B\). This is the core of the limit method that Augustin-Louis Cauchy made rigorous in the 1820s. Carnot’s contribution was to explain why the infinitesimal algorithms, applied according to their rules, never produce a false final result.

An example

Find the subtangent of the parabola \(y^2=px\) at \((x,y)\). Let \(MT\) be the tangent and take a nearby point at \((x+h,y+k)\) on the curve. Treating the chord as the tangent (an error) gives subtangent \(\approx y\,h/k\). From the curve, \(2yk+k^2=ph\), and dropping \(k^2\) (a second error) gives \(h/k\approx2y/p\). Combining, subtangent \(=2y^2/p=2x\). The two errors compensate exactly, as the limit computation confirms: \(dx/dy=2y/p\) and the subtangent is \(y\,dx/dy=2x\).

Exercise 7.1Carry out the same two-error argument for the curve \(y=x^3\) and find the slope at \(x\). Then show, by keeping the neglected terms, that the errors cancel in the limit.

Show solution
\(k=(x+h)^3-x^3=3x^2h+3xh^2+h^3\). Dropping the higher terms gives \(k/h\approx3x^2\). Exactly, \(k/h=3x^2+3xh+h^2\), and the difference from \(3x^2\) is less than any \(\varepsilon\) for small \(h\); since the slope of the tangent is a fixed number independent of \(h\), it equals \(3x^2\).

Exercise 7.2Berkeley objected that in computing \(\frac{(x+h)^2-x^2}{h}=2x+h\) one first assumes \(h\ne0\) to divide, then sets \(h=0\). How does Carnot’s principle answer him, and how does the limit definition?

Show solution
Carnot: \(h\) is never zero; the chord slope \(2x+h\) differs from the fixed tangent slope by an amount that can be made smaller than any given error, so the tangent slope is exactly \(2x\). Limits: the derivative is defined as \(\lim_{h\to0}(2x+h)\), which equals \(2x\) without ever setting \(h=0\). Both replace “set \(h=0\)” by a statement about arbitrarily small \(h\).
Lesson 08

Geometry of position and signed quantities

For the general reader. A Greek geometer proving a theorem had to redraw it for every case: point inside the segment, point outside, and so on. Carnot wanted one statement that covered all positions at once. His solution was to give lengths and angles a sign that records their position, and to follow a figure as it is continuously deformed. The approach led directly to the projective geometry of Jean-Victor Poncelet and Michel Chasles.

Goals
  • Understand Carnot’s correlation of figures and signed magnitudes.
  • Prove Carnot’s theorem on the circumcentre, inradius and circumradius.
  • See how signs let one statement cover acute and obtuse triangles.

Correlation of figures

In De la corrélation des figures de géométrie (1801) and Géométrie de position (1803), Carnot compared a “primitive” figure with “correlative” figures obtained by moving its points continuously. A relation proved for the primitive figure carries over, but some quantities may change sign when a point passes through another. Carnot himself held that negative quantities had no existence alone and only marked a reversal of position, a view that later geometers dropped in favour of signed segments \(\overline{AB}=-\overline{BA}\) on oriented lines. The method of following a theorem through all positions became Poncelet’s principle of continuity.

Carnot’s theorem (triangle)

Let triangle \(ABC\) have circumcentre \(O\), circumradius \(R\) and inradius \(r\). Let \(d_a,d_b,d_c\) be the distances from \(O\) to the lines \(BC,CA,AB\), each taken with a minus sign when \(O\) and the opposite vertex lie on different sides of that line. Then

\[ d_a+d_b+d_c=R+r. \]

Proof

The central angle on chord \(BC\) is \(2A\), so \(d_a=R\cos A\), and the sign convention makes this hold also when \(A\) is obtuse (\(\cos A<0\)). Hence \(d_a+d_b+d_c=R(\cos A+\cos B+\cos C)\). The identity

\[ \cos A+\cos B+\cos C=1+\frac{r}{R} \]

finishes the proof. To prove it, write \(\cos A+\cos B=2\sin\frac C2\cos\frac{A-B}2\) and \(1-\cos C=2\sin^2\frac C2\), so the left side minus 1 is \(2\sin\frac C2\big(\cos\frac{A-B}2-\cos\frac{A+B}2\big)=4\sin\frac A2\sin\frac B2\sin\frac C2\), and \(r=4R\sin\frac A2\sin\frac B2\sin\frac C2\) is standard. \(\square\)

Exercise 8.1Check Carnot’s theorem for the 3–4–5 right triangle.

Show solution
\(O\) is the midpoint of the hypotenuse, so \(d_c=0\) and \(d_a,d_b\) are half the other legs: \(2\) and \(1.5\). The sum is \(3.5\). \(R=2.5\), \(r=(3+4-5)/2=1\), so \(R+r=3.5\).

Exercise 8.2Show that for an equilateral triangle the theorem reduces to \(R=2r\).

Show solution
All three distances equal \(r\), since the circumcentre is the incentre. So \(3r=R+r\), i.e. \(R=2r\). By Euler’s inequality \(R\ge2r\), this is the extreme case.

Exercise 8.3Take a triangle with \(A=120^\circ\), \(B=C=30^\circ\) and \(R=1\). Compute \(d_a,d_b,d_c\) with signs and verify the theorem.

Show solution
\(d_a=\cos120^\circ=-\tfrac12\) (negative: \(O\) lies beyond \(BC\), away from \(A\)), \(d_b=d_c=\cos30^\circ=\tfrac{\sqrt3}2\). Sum \(=\sqrt3-\tfrac12\approx1.232\). Inradius: \(r=4\sin60^\circ\sin^215^\circ=2\sqrt3\cdot\frac{1-\cos30^\circ}{2}=\sqrt3-\tfrac32\approx0.232\). So \(R+r\approx1.232\). Without the sign, the identity would fail.
Lesson 09

Transversals, conics and five points

For the general reader. A line crossing the three sides of a triangle cuts them in ratios whose product is always one; this is the ancient theorem of Menelaus. Carnot made such “transversal” theorems a subject in their own right and extended them from lines to curves. His theorem on conics is a direct ancestor of the cross-ratio methods of projective geometry.

Goals
  • Recall Menelaus’ theorem with signed ratios.
  • State and prove Carnot’s theorem for a conic cutting the sides of a triangle.
  • Understand the relation among the ten distances of five points in space.
Menelaus (signed form)

A line meets the lines \(BC,CA,AB\) at \(A_1,B_1,C_1\) if and only if

\[ \frac{\overline{BA_1}}{\overline{A_1C}}\cdot\frac{\overline{CB_1}}{\overline{B_1A}}\cdot\frac{\overline{AC_1}}{\overline{C_1B}}=-1. \]
Carnot’s theorem for conics (1803–1806)

Let a conic meet the lines \(BC\) at \(A_1,A_2\), \(CA\) at \(B_1,B_2\), and \(AB\) at \(C_1,C_2\) (points possibly complex or coincident). Then, with signed segments,

\[ \frac{\overline{BA_1}\cdot\overline{BA_2}}{\overline{CA_1}\cdot\overline{CA_2}}\cdot\frac{\overline{CB_1}\cdot\overline{CB_2}}{\overline{AB_1}\cdot\overline{AB_2}}\cdot\frac{\overline{AC_1}\cdot\overline{AC_2}}{\overline{BC_1}\cdot\overline{BC_2}}=1. \]

Proof sketch. Let the conic be \(f(\mathbf x)=0\) with \(f\) a quadratic polynomial. Parametrize line \(BC\) by \(\mathbf x(t)=B+t(C-B)\); then \(g(t)=f(\mathbf x(t))\) is quadratic with roots \(t_1,t_2\) at \(A_1,A_2\), so \(g(t)=c\,(t-t_1)(t-t_2)\). Evaluating at \(t=0\) and \(t=1\):

\[ \frac{f(B)}{f(C)}=\frac{t_1t_2}{(1-t_1)(1-t_2)}=\frac{\overline{BA_1}\cdot\overline{BA_2}}{\overline{A_1C}\cdot\overline{A_2C}}=\frac{\overline{BA_1}\cdot\overline{BA_2}}{\overline{CA_1}\cdot\overline{CA_2}}, \]

since the two sign changes from \(\overline{A_iC}=-\overline{CA_i}\) cancel. Multiply the three such ratios: \(\frac{f(B)}{f(C)}\cdot\frac{f(C)}{f(A)}\cdot\frac{f(A)}{f(B)}=1\). (The vertices are assumed not on the conic.) \(\square\)

When the conic degenerates into the given transversal line taken twice, each pair of points coincides, and the theorem gives the square of Menelaus’ relation. The same argument works for curves of any degree \(n\), with \(n\) points on each side.

Five points in space

In his memoir of 1806 on the distances between five points, Carnot sought the relation that must hold among the ten mutual distances of five points in three-dimensional space, since only nine of them can be chosen freely. Arthur Cayley gave the relation its determinant form in 1841: if \(d_{ij}\) are the distances among points \(P_0,\dots,P_4\) in \(\mathbb R^3\), then

\[ \det\begin{pmatrix}0&1&1&\cdots&1\\1&0&d_{01}^2&\cdots&d_{04}^2\\1&d_{10}^2&0&\cdots&d_{14}^2\\\vdots&\vdots&&\ddots&\vdots\\1&d_{40}^2&d_{41}^2&\cdots&0\end{pmatrix}=0, \]

because this Cayley–Menger determinant is proportional to the squared volume of the 4-simplex on the five points, which is zero in three dimensions.

Exercise 9.1A line cuts side \(AB\) at its midpoint and side \(BC\) at the point \(A_1\) with \(\overline{BA_1}=2\,\overline{A_1C}\). Where does it meet line \(CA\)?

Show solution
Menelaus gives \(2\cdot\frac{\overline{CB_1}}{\overline{B_1A}}\cdot1=-1\), so \(\overline{CB_1}/\overline{B_1A}=-\tfrac12\). Put coordinates \(C=0\), \(A=1\) on line \(CA\) and \(B_1=x\): then \(x/(1-x)=-\tfrac12\), so \(x=-1\). The line meets \(CA\) outside the segment, beyond \(C\), at distance \(CA\) from \(C\).

Exercise 9.2Use the Cayley–Menger idea in the plane: show that four points \(P_0,\dots,P_3\) at mutual distance 1, except \(d_{23}=x\), lie in a plane only if \(x=\sqrt3\) or \(x=0\).

Show solution
\(P_0,P_1\) at distance 1, and \(P_2,P_3\) each at distance 1 from both, so \(P_2,P_3\) are the two apex points of equilateral triangles on \(P_0P_1\). In the plane there are two such points, at distance \(\sqrt3\) apart, or the same point (\(x=0\)). For \(0<x<\sqrt3\) the four points form a tetrahedron in space, and the \(5\times5\) Cayley–Menger determinant (proportional to its squared volume) is non-zero.
Lesson 10

From Lazare to Sadi: continuity and reversibility

For the general reader. In 1824 Lazare’s son Sadi Carnot asked how much work a heat engine can produce, and founded thermodynamics. His argument copied his father’s. A water wheel is best when the water enters without shock and leaves without speed; a heat engine is best when heat passes without any useless flow between bodies at different temperatures. Both are best when the process could run backwards.

Goals
  • State Lazare Carnot’s principle of continuity for machines.
  • Compare a hydraulic machine with Sadi Carnot’s heat engine.
  • Derive the maximum efficiency of each.

The principle of continuity

From the theorem of Lesson 06, every sudden change of velocity loses live force. Lazare concluded that a machine attains its maximum effect when motion is transmitted by insensible degrees, without percussion or turbulence, and when the fluid leaves with no remaining velocity. Engineers attributed this principle to him until the mid-nineteenth century, when it was absorbed into energy conservation.

Hydraulic and thermal maxima

Water. Water of mass flow \(\dot m\) falling through height \(h\) can deliver at most power \(\dot m g h\), attained when entry is shockless and exit velocity is zero; any such ideal machine run backwards is a pump.

Heat (Sadi Carnot, 1824). An engine working between reservoirs at absolute temperatures \(T_h>T_c\) has efficiency at most

\[ \eta_{\max}=1-\frac{T_c}{T_h}, \]

attained by reversible engines, in which heat passes only between bodies at equal temperature.

Sadi’s own analogy compared heat falling from a high temperature to a low one with water falling from a height. The analogy was imperfect, because in his caloric theory heat was conserved, while energy conservation required that some heat be converted into work. Rudolf Clausius and William Thomson rebuilt the argument on the first and second laws around 1850, keeping Sadi’s reversibility criterion, the descendant of Lazare’s geometric motions, which can be run in either direction.

Exercise 10.1A steam engine works between \(150^\circ\mathrm C\) and \(30^\circ\mathrm C\). Find the Carnot limit on its efficiency.

Show solution
\(T_h=423\ \mathrm K\), \(T_c=303\ \mathrm K\); \(\eta_{\max}=1-303/423\approx0.284\), about 28%.

Exercise 10.2Water leaves a water wheel with speed \(u\) after falling through height \(h\) and entering without shock. What fraction of the available power is lost?

Show solution
The lost power is the kinetic energy carried away, \(\tfrac12\dot m u^2\). As a fraction of \(\dot mgh\) it is \(u^2/2gh\). Lazare’s rule that the water should leave with no velocity sets this to zero.
Part III · Life and legacy
Lesson 11

Consulate, Empire and the Hundred Days, 1800–1815

After Bonaparte seized power in November 1799, Carnot returned to France. He served as Minister of War from 2 April to 8 October 1800, organizing the campaign that ended at Marengo, then resigned. He was readmitted to the Institut and in 1802 entered the Tribunate. There he voted against the life consulship in 1802 and against the proclamation of the Empire in 1804, publicly and nearly alone. After the coronation he withdrew from politics.

The next decade was his most productive in science. In 1801 came De la corrélation des figures de géométrie, in 1803 the Géométrie de position and the Principes fondamentaux de l’équilibre et du mouvement, and in 1806 the memoir on five points with its essay on transversals. He served on many Institut commissions reviewing inventions and mathematical memoirs. In 1809 he published De la défense des places fortes, which argued for active defence by sorties and vertical fire.

In January 1814, as the allied armies entered France, Carnot offered his services and was made governor of Antwerp. He held the city through the siege and surrendered it only on orders after Napoleon’s abdication. During the Hundred Days he was Minister of the Interior from 20 March to 22 June 1815, made a count of the Empire and a peer. In that office he took up public education, including plans for elementary schooling. After Waterloo he sat on the provisional government commission that ruled until the return of Louis XVIII.

DiscussionCarnot served the Terror, the Directory, Napoleon and the Hundred Days, yet voted against the Empire. Was he a consistent republican, a technocrat serving whoever held power, or something else? Use the dates in this course to argue your case.

Lesson 12

Exile, death and legacy, 1815–1823

The restored Bourbons proscribed the regicides who had served Napoleon in the Hundred Days. Carnot left France, went first to Warsaw, and from November 1816 lived at Magdeburg in Prussia. He was expelled from the Academy of Sciences in the purge of 1816. In exile he wrote verse and memoirs and followed the education of his sons. He died at Magdeburg on 2 August 1823, aged 70, and was buried there. In 1889, during the presidency of his grandson Sadi Carnot, his remains were brought to the Panthéon in Paris.

Family

His elder son, Nicolas Léonard Sadi Carnot (1796–1832), trained at the École polytechnique and published Réflexions sur la puissance motrice du feu in 1824, the founding work of thermodynamics. His younger son, Hippolyte Carnot (1801–1888), was a politician and minister of public instruction in 1848. Hippolyte’s son Marie François Sadi Carnot was President of the Republic from 1887 until his assassination in 1894.

Legacy

  • Mechanics: the first general theory of machines; work as the measure of what machines transmit; geometric motions; Carnot’s theorem on shocks; the Borda–Carnot head loss. Through Coriolis, Navier and Poncelet his ideas shaped the engineering mechanics of the École polytechnique.
  • Thermodynamics: the principle of continuity and the notion of a motion that can be reversed passed directly to Sadi Carnot.
  • Geometry: signed magnitudes, correlation of figures, and the theory of transversals, which fed Poncelet’s projective geometry and Chasles’s historical synthesis. Carnot’s theorems on the triangle and on conics are still taught.
  • Foundations: the compensation-of-errors account of the calculus, widely read and translated before Cauchy.
  • Public life: the organization of the revolutionary armies, a share in founding the École polytechnique, and a reputation for integrity across five regimes.

Final projectChoose one topic from Part II. Write a two-page account for a strong undergraduate that states the result in modern form, works one example, and explains what Carnot’s formulation saw that earlier treatments missed.

Reference

Connections

People linked to Lazare Carnot across this collection. A name without a link has no page here yet. See Lazare Carnot in the network of all 337 lives →

Teachers and advisors

Influenced by

Influenced

Colleagues and collaborators

Rivals

Family

Also mentioned in this life

Fields

On CoursesHub

Reference

Sources and further reading

Biography

  1. J. J. O’Connor and E. F. Robertson, Lazare Nicolas Marguerite Carnot, MacTutor History of Mathematics.
  2. Lazare Carnot, Wikipedia; Lazare Carnot, Wikipédia (French).
  3. C. C. Gillispie, Carnot, Lazare-Nicolas-Marguerite, Dictionary of Scientific Biography.
  4. Carnot, “The Great”, Fondation Napoléon.
  5. M. Reinhard, Le Grand Carnot, 2 vols., Hachette, 1950–52.

Science

  1. L. Carnot, Essai sur les machines en général, Dijon, 1783.
  2. L. Carnot, Réflexions sur la métaphysique du calcul infinitésimal, Paris, 1797; 2nd ed. 1813.
  3. L. Carnot, De la corrélation des figures de géométrie, Paris, 1801.
  4. L. Carnot, Géométrie de position, Paris, 1803.
  5. L. Carnot, Principes fondamentaux de l’équilibre et du mouvement, Paris, 1803.
  6. L. Carnot, Mémoire sur la relation qui existe entre les distances respectives de cinq points quelconques pris dans l’espace; suivi d’un essai sur la théorie des transversales, Paris, 1806.
  7. C. C. Gillispie, Lazare Carnot, Savant, Princeton University Press, 1971.
  8. C. C. Gillispie and R. Pisano, Lazare and Sadi Carnot: A Scientific and Filial Relationship, Springer, 2014.
  9. S. Carnot, Réflexions sur la puissance motrice du feu, Paris, 1824.
  10. Carnot’s theorem (inradius, circumradius) and Carnot’s theorem (conics), Wikipedia.
  11. Borda–Carnot equation, Wikipedia.