← Part IV: Nuclear Models
Chapter 10

Shell Model

Independent Particle Model

The nuclear shell model assumes that each nucleon moves independently in an average potential created by all other nucleons. This is remarkable because nucleons interact strongly -- the Pauli exclusion principle suppresses nucleon-nucleon collisions inside the nucleus, validating the independent particle picture.

The single-particle Hamiltonian is:

$$H = \frac{p^2}{2m} + V(r) + V_{\text{so}}(r)\,\mathbf{L}\cdot\mathbf{S}$$

The mean field $V(r)$ is taken as the Woods-Saxon potential, which provides a realistic representation of the nuclear density distribution.

Woods-Saxon + Spin-Orbit Potential

The full single-particle potential consists of three parts:

Central Potential

$$V_{\text{WS}}(r) = -\frac{V_0}{1 + \exp\!\left(\frac{r - R}{a}\right)}, \quad V_0 \approx 51 \text{ MeV}$$

Spin-Orbit Interaction

$$V_{\text{so}}(r) = -V_{\text{so}}^{(0)} \frac{1}{r}\frac{dV_{\text{WS}}}{dr}\,\mathbf{L}\cdot\mathbf{S}$$

Concentrated at the nuclear surface (where $dV/dr$ is largest). The nuclear spin-orbit force is ~20 times stronger than the atomic one and has opposite sign.

Coulomb Potential (protons only)

$$V_C(r) = \begin{cases} \frac{Ze^2}{4\pi\epsilon_0}\frac{1}{2R}\left(3 - \frac{r^2}{R^2}\right) & r < R \\ \frac{Ze^2}{4\pi\epsilon_0 r} & r > R \end{cases}$$

Magic Numbers Explained

The spin-orbit splitting of each $\ell$ level into $j = \ell + 1/2$ (lower energy) and $j = \ell - 1/2$ (higher energy) rearranges the level ordering to produce large energy gaps at the magic numbers:

Magic NumberShell ClosureKey LevelExample
21s1/2 filled1s1/2 (2)$^4$He
8+ 1p shell1p3/2, 1p1/2 (6)$^{16}$O
20+ 1d5/2, 2s1/2, 1d3/2sd shell (12)$^{40}$Ca
28+ 1f7/21f7/2 (8)$^{48}$Ca
50+ 2p, 1f5/2, 1g9/21g9/2 intruder (10)$^{132}$Sn
82+ 2d, 1g7/2, 1h11/21h11/2 intruder (12)$^{208}$Pb
126+ 2f, 1h9/2, 1i13/21i13/2 intruder (14)$^{208}$Pb (N)

Python Simulation: Woods-Saxon Levels

Woods-Saxon potential shape and single-particle energy levels with spin-orbit splitting.

Woods-Saxon Potential Energy Levels

Python

Nuclear mean field potential and single-particle level scheme for A=208

script.py125 lines

Click Run to execute the Python code

Code will be executed with Python 3 on the server

Fortran Implementation

Shell model single-particle energy calculator with full level scheme.

Shell Model Single-Particle Energies

Fortran

Full level scheme with magic numbers from harmonic oscillator + spin-orbit

shell_model_energies.f9087 lines

Click Run to execute the Fortran code

Code will be compiled with gfortran and executed on the server

Derivation: Magic Numbers from Spin-Orbit Coupling

The key insight of Mayer, Jensen, Haxel, and Suess (1949) was that a strong spin-orbit interaction splits the single-particle levels and rearranges the shell closures to reproduce the observed magic numbers. We derive this step by step.

Step 1: Harmonic Oscillator Without Spin-Orbit

The 3D harmonic oscillator has energy levels labeled by the principal quantum number $N$:

$$E_N = \left(N + \frac{3}{2}\right)\hbar\omega, \quad N = 0, 1, 2, 3, \ldots$$

Each $N$ shell has degeneracy $(N+1)(N+2)/2$ (without spin) or $(N+1)(N+2)$(with spin). The orbital angular momentum values in each shell are:

$$\ell = N, N-2, N-4, \ldots, 1 \text{ or } 0$$

The cumulative nucleon numbers at shell closures are:

$$\text{HO magic numbers: } 2, 8, 20, 40, 70, 112, 168, \ldots$$

These agree with experiment only for 2, 8, and 20. The observed 28, 50, 82, 126 are not reproduced.

Step 2: Adding $\ell^2$ Correction

The Woods-Saxon potential is flatter at the bottom than the harmonic oscillator. This difference can be modeled by adding an $\ell^2$ correction that lowers high-$\ell$ states relative to low-$\ell$ ones:

$$E_{N\ell} = \left(N + \frac{3}{2}\right)\hbar\omega + D\,\ell(\ell + 1)$$

where $D < 0$ (typically $D \approx -0.1\hbar\omega$). This breaks the degeneracy within each $N$ shell but does not change the shell closures significantly. The orbits with the highest $\ell$ in each shell are pushed down.

Step 3: The Spin-Orbit Interaction

The crucial addition is the spin-orbit term:

$$V_{\rm so} = -C_{\ell s}\,\mathbf{L}\cdot\mathbf{S}$$

with $C_{\ell s} > 0$ (attractive for $j = \ell + 1/2$). The eigenvalues of$\mathbf{L}\cdot\mathbf{S}$ for $j = \ell \pm 1/2$ are:

$$\langle\mathbf{L}\cdot\mathbf{S}\rangle = \frac{1}{2}[j(j+1) - \ell(\ell+1) - s(s+1)] = \begin{cases} +\frac{\ell}{2} & j = \ell + \frac{1}{2} \\ -\frac{\ell+1}{2} & j = \ell - \frac{1}{2} \end{cases}$$

The energy splitting between the two spin-orbit partners is:

$$\Delta E_{\rm so} = E_{j=\ell-1/2} - E_{j=\ell+1/2} = C_{\ell s}\left(\ell + \frac{1}{2}\right) = C_{\ell s}(2\ell + 1)/2$$

The splitting grows linearly with $\ell$. For high-$\ell$ orbits, the$j = \ell + 1/2$ level is pushed so far down that it joins the lower shell, creating new magic numbers.

Step 4: Reproducing Magic Numbers

With a spin-orbit strength $C_{\ell s} \approx 2\text{-}3$ MeV, the level ordering becomes:

  • - N=3 shell: The $1f_{7/2}$ ($\ell=3$, $j=7/2$, 8 states) is pushed down from the N=3 group into a gap, creating the magic number 28 = 20 + 8.
  • - N=4 shell: The $1g_{9/2}$ ($\ell=4$, $j=9/2$, 10 states) descends to fill the gap, giving 50 = 28 + 22 (where 22 = 2+4+6+10 from 2p, 1f$_{5/2}$, 1g$_{9/2}$).
  • - N=5 shell: The $1h_{11/2}$ ($\ell=5$, $j=11/2$, 12 states) intruder gives 82 = 50 + 32.
  • - N=6 shell: The $1i_{13/2}$ ($\ell=6$, $j=13/2$, 14 states) intruder gives 126 = 82 + 44.

Each magic number beyond 20 is created by the highest-$j$ intruder orbit from the shell above being pulled down by the spin-orbit interaction.

Harmonic Oscillator vs. Woods-Saxon Potentials

Harmonic Oscillator Level Spectrum

The spacing parameter of the harmonic oscillator potential is empirically fitted to:

$$\hbar\omega \approx 41\,A^{-1/3} \text{ MeV}$$

The radial wave functions are Laguerre polynomials times Gaussians:

$$R_{n_r\ell}(r) = N_{n_r\ell}\,r^\ell\,L_{n_r}^{\ell+1/2}\!\left(\frac{r^2}{b^2}\right)\exp\!\left(-\frac{r^2}{2b^2}\right)$$

where $b = \sqrt{\hbar/(m\omega)}$ is the oscillator length parameter ($b \approx 1.0\,A^{1/6}$ fm) and $n_r = 0, 1, 2, \ldots$ is the radial quantum number. The relation between $N$ and the quantum numbers is$N = 2n_r + \ell$.

Woods-Saxon Level Spectrum

The Woods-Saxon potential produces levels that must be found numerically. Key differences from the harmonic oscillator:

  • - Finite depth: Only a finite number of bound states exist ($E < 0$)
  • - Flat bottom: High-$\ell$ orbits are relatively lowered (the $\ell^2$ effect)
  • - Diffuse surface: Wave functions extend further outside the nucleus
  • - Better asymptotics: Exponential falloff instead of Gaussian, matching scattering states

The modified harmonic oscillator (Nilsson model) captures these effects approximately:

$$H_{\rm Nilsson} = -\frac{\hbar^2}{2m}\nabla^2 + \frac{1}{2}m\omega^2 r^2 + C\,\mathbf{L}\cdot\mathbf{S} + D\,\left[\ell^2 - \langle\ell^2\rangle_N\right]$$

Single-Particle Energies and the Nilsson Diagram

For deformed nuclei, the single-particle energies depend on the nuclear deformation parameter $\epsilon$ (or equivalently $\beta_2$). The Nilsson diagram plots these energies as a function of deformation.

Deformed Harmonic Oscillator

For an axially deformed nucleus, the oscillator frequencies differ along the symmetry axis ($z$) and perpendicular to it ($\perp$):

$$\omega_z = \omega_0(1 - \tfrac{2}{3}\epsilon), \quad \omega_\perp = \omega_0(1 + \tfrac{1}{3}\epsilon)$$

where $\epsilon$ is the Nilsson deformation parameter (related to $\beta_2$ by$\epsilon \approx 0.95\beta_2$). Volume conservation requires$\omega_z\omega_\perp^2 = \omega_0^3$.

$$E_{n_z, n_\perp} = \left(n_z + \frac{1}{2}\right)\hbar\omega_z + \left(n_\perp + 1\right)\hbar\omega_\perp$$

Nilsson Quantum Numbers

In a deformed potential, the good quantum numbers are the projection of total angular momentum on the symmetry axis $\Omega = K$ and parity $\pi$. Each Nilsson level is labeled:

$$\Omega^\pi [N\, n_z\, \Lambda]$$

where $N$ is the major oscillator shell, $n_z$ is the number of nodes along the symmetry axis, $\Lambda$ is the projection of orbital angular momentum, and$\Omega = \Lambda \pm 1/2$. At zero deformation, these reduce to spherical states.

Key features of the Nilsson diagram: (a) levels with large $\Omega$ slope downward for prolate deformation (since the orbit is concentrated in the equatorial plane, away from the tips); (b) level crossings create new deformed shell closures (e.g., at $\epsilon \approx 0.3$, new gaps appear at N or Z = 38, 64).

Residual Interactions and Nuclear Pairing

The Residual Interaction

The mean field captures the average nuclear interaction. The residual interaction is the difference between the true two-body interaction and the mean field:

$$H_{\rm res} = \sum_{i<j} V_{ij} - \sum_i U(r_i)$$

The most important residual interactions are:

  • - Pairing interaction: Short-range attraction between nucleons in time-reversed orbits. Dominates for like nucleons.
  • - Quadrupole-quadrupole interaction: Long-range part that drives nuclear deformation. Important for proton-neutron interactions.
  • - Monopole interaction: Shifts single-particle energies as shells are filled, responsible for shell evolution far from stability.

Nuclear Pairing: BCS Theory

Nuclear pairing is treated by analogy with the BCS (Bardeen-Cooper-Schrieffer) theory of superconductivity. The pairing Hamiltonian in the seniority scheme is:

$$H_{\rm pair} = \sum_k \varepsilon_k\,\hat{n}_k - G\sum_{k,k'>0} a_{k'}^\dagger a_{\bar{k}'}^\dagger a_{\bar{k}} a_k$$

where $G$ is the pairing strength and $k$ labels single-particle states with$\bar{k}$ the time-reversed partner. The BCS solution gives:

$$E_k = \sqrt{(\varepsilon_k - \lambda)^2 + \Delta^2}$$

where $\Delta$ is the pairing gap and $\lambda$ is the chemical potential. The gap equation is:

$$\frac{1}{G} = \sum_k \frac{1}{2E_k} = \sum_k \frac{1}{2\sqrt{(\varepsilon_k - \lambda)^2 + \Delta^2}}$$

The empirical pairing gap is approximately $\Delta \approx 12/\sqrt{A}$ MeV. Pairing explains: (a) the even-odd mass staggering, (b) the $0^+$ ground states of all even-even nuclei, (c) the moment of inertia being ~50% of the rigid-body value (superfluidity reduces it), and (d) the energy gap in the excitation spectrum.

Spectroscopic Predictions

Ground State Spins and Parities

The shell model predicts ground state quantum numbers from the last unpaired nucleon:

  • - Even-even nuclei: Always $J^\pi = 0^+$ (all nucleons paired)
  • - Odd-A nuclei: $J^\pi = j^\pi$ of the last odd nucleon. Parity is $(-1)^\ell$.
  • - Odd-odd nuclei: $|j_p - j_n| \leq J \leq j_p + j_n$ with Nordheim rules: Strong rule ($j_p = \ell_p + 1/2$, $j_n = \ell_n + 1/2$): $J = |j_p - j_n|$; Weak rule (mixed): $J = j_p + j_n$ or $J = |j_p - j_n|$.

Examples of successful predictions:

$^{17}$O (8p, 9n)

Last n: $1d_{5/2}$

$J^\pi = 5/2^+$

$^{41}$Ca (20p, 21n)

Last n: $1f_{7/2}$

$J^\pi = 7/2^-$

$^{209}$Bi (83p, 126n)

Last p: $1h_{9/2}$

$J^\pi = 9/2^-$

$^{207}$Pb (82p, 125n)

Last n: $2p_{1/2}$

$J^\pi = 1/2^-$

Nuclear Magnetic Moments

The magnetic moment of a nucleus is sensitive to the single-particle orbit of the valence nucleon. For a single nucleon in orbit $j = \ell \pm 1/2$:

$$\mu = g_j\,j\,\mu_N, \quad g_j = \frac{1}{2}\left(g_\ell + g_s\right) + \frac{1}{2}\left(g_\ell - g_s\right)\frac{\ell(\ell+1) - s(s+1)}{j(j+1)}$$

where the g-factors for free nucleons are:

Proton

$g_\ell^p = 1, \quad g_s^p = 5.586$

Neutron

$g_\ell^n = 0, \quad g_s^n = -3.826$

These give the Schmidt values (single-particle limits). Measured moments generally fall between the Schmidt values for the two possible $j = \ell \pm 1/2$ states, but are quenched by ~30-40% due to configuration mixing and meson exchange currents.

Schmidt Lines for Magnetic Moments

The Schmidt model predicts two lines for the magnetic moments of odd-A nuclei, one for $j = \ell + 1/2$ and one for $j = \ell - 1/2$. These define the limits within which experimental moments should fall.

Derivation of Schmidt Values

For $j = \ell + 1/2$ (spin parallel to orbital angular momentum):

$$\mu = \left(j - \frac{1}{2} + g_s/2\right)\mu_N = \left(\ell + g_s/2\right)\mu_N$$

For $j = \ell - 1/2$ (spin antiparallel):

$$\mu = j\left(g_\ell - \frac{g_s - g_\ell}{2\ell + 1}\cdot\frac{j+1}{j}\right)\mu_N$$

Explicitly for odd protons:

$$\mu_{\rm Schmidt}^{(p)} = \begin{cases} j + 2.293 & j = \ell + \frac{1}{2} \\ j\left(1 - \frac{4.586}{2j+2}\right) + \frac{4.586}{2j+2} & j = \ell - \frac{1}{2} \end{cases}$$

And for odd neutrons:

$$\mu_{\rm Schmidt}^{(n)} = \begin{cases} -1.913 & j = \ell + \frac{1}{2} \\ j\left(\frac{3.826}{2j+2}\right) - \frac{3.826}{2j+2} & j = \ell - \frac{1}{2} \end{cases}$$

Comparison with Experiment

Experimental magnetic moments generally fall between the two Schmidt lines but are systematically quenched toward the center. The quenching arises from:

  • - Configuration mixing: The ground state is not a pure single-particle state but contains admixtures of other configurations (~5-15% core excitation).
  • - Meson exchange currents: The nuclear current operator receives contributions from exchanged mesons (mainly pions), effectively reducing $g_s$ by ~30%.
  • - Core polarization: The valence nucleon polarizes the core, inducing small magnetic moments from the paired nucleons.

The effective spin g-factor is approximately $g_s^{\rm eff} \approx 0.7\,g_s^{\rm free}$. Using $g_s^{\rm eff}$ instead of $g_s^{\rm free}$ significantly improves the agreement between predicted and experimental magnetic moments.

Electric Quadrupole Moments

The single-particle quadrupole moment is:

$$Q_{\rm sp} = -\frac{2j - 1}{2(j + 1)}\langle r^2 \rangle$$

For a uniformly charged sphere, $\langle r^2 \rangle = \frac{3}{5}R^2$. The single-particle estimate gives small values ($|Q| \lesssim 0.3$ b for heavy nuclei). However, measured quadrupole moments of nuclei far from closed shells are often 5-20 times larger than the single-particle estimate:

$$Q \gg Q_{\rm sp} \implies \text{collective (deformed) behavior}$$

These enhanced quadrupole moments signal that the nucleus is statically deformed, requiring collective models (rotational or vibrational) for proper description. Typical deformations in the rare-earth region are $\beta_2 \approx 0.2\text{-}0.3$, giving intrinsic quadrupole moments $Q_0 = \frac{3}{\sqrt{5\pi}}ZR^2\beta_2 \approx 5\text{-}10$ b.

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