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Joseph von Fraunhofer

Joseph Ritter von Fraunhofer

A course in two strands: the life of an orphaned glazier’s apprentice, pulled from a collapsed house, who became Europe’s finest maker of lenses, and the optics he created to do it: the dark lines of the solar spectrum, the diffraction grating and the precision refracting telescope.

Born 6 March 1787, Straubing Died 7 June 1826, Munich Solar lines mapped 1814, 574 lines Level advanced undergraduate → graduate
The visible solar spectrum with Fraunhofer’s principal lines at their modern wavelengths. Line widths are schematic.
Lesson 00

How to use this course

Joseph von Fraunhofer had almost no schooling and died at 39. In about fifteen years of work he turned lens-making from a craft of trial and error into a science of measurement. To measure his glass he needed sharp reference colours, and he found them in the dark lines of sunlight. To measure the wavelengths of those lines he built the first diffraction gratings. His telescopes carried out the first reliable measurements of distances to stars. Spectroscopy, the science that tells us what stars are made of, begins in his workshop.

Prerequisites for Part II
  • Trigonometry, calculus and complex exponentials.
  • Snell’s law and the thin-lens formula.
  • Superposition of waves and the idea of interference.
  • For Lesson 07, the Fourier transform; for Lesson 09, the Bohr model of hydrogen.

Each technical lesson opens with a paragraph for the general reader, then gives precise statements, derivations and exercises with folded solutions. Part II follows Fraunhofer’s own path: from measuring glass (Lessons 04 to 06) to diffraction and gratings (Lessons 07 and 08), then to what later scientists made of his lines (Lesson 09) and to the telescopes that carried his name (Lesson 10).

Reference

Timeline

1787Born 6 March in Straubing, Bavaria, the eleventh child of the glazier Franz Xaver Fraunhofer and Maria Anna Fröhlich.
1797–98Loses his mother and then his father.
1799Apprenticed in Munich to the mirror-maker and glass-cutter Philipp Anton Weichselberger.
180121 July: the workshop building collapses; he is dug out alive after about four hours. Elector Maximilian Joseph and Joseph Utzschneider take an interest in him.
1806Joins the optical workshop of the Mathematisch-Mechanisches Institut of Utzschneider, Georg Reichenbach and Joseph Liebherr.
1807The optical workshop moves to the former monastery of Benediktbeuern; Pierre-Louis Guinand runs the glass melting.
1809Directs the optical workshop.
1814Becomes a partner in the firm. Maps the dark lines of the solar spectrum.
1814–15Memoir on the refractive and dispersive power of glass, in the Denkschriften of the Bavarian Academy.
1817Corresponding member of the Bavarian Academy of Sciences.
1819The optical workshop returns to Munich.
1821Memoir on diffraction: the grating and the first wavelengths of the solar lines. Extraordinary member of the Academy.
1822Honorary doctorate from the University of Erlangen.
1823Conservator of the Academy’s physical cabinet with a professor’s salary; lectures on optics.
1824The great refractor reaches Wilhelm Struve at Dorpat. Knighted in the Order of Merit of the Bavarian Crown: “von Fraunhofer”. Elected to the Leopoldina.
1826Dies in Munich on 7 June, aged 39.
1838Friedrich Wilhelm Bessel measures the parallax of 61 Cygni with a Fraunhofer heliometer.
1859Gustav Kirchhoff and Robert Bunsen explain the dark lines as absorption by elements in the Sun.
Part I · Formation
Lesson 01

Straubing and the collapsed house, 1787–1801

Joseph Fraunhofer was born on 6 March 1787 in Straubing, a town on the Danube in Lower Bavaria. He was the eleventh child of Franz Xaver Fraunhofer, a glazier, and Maria Anna Fröhlich. Both parents came from families in the glass trade. His mother died in 1797 and his father in 1798, leaving him an orphan at eleven with very little schooling.

His guardian apprenticed him in Munich to Philipp Anton Weichselberger, a mirror-maker and glass-cutter who worked him hard and gave him no time to study. On 21 July 1801 two old houses in a narrow Munich lane collapsed. Fraunhofer was buried in the rubble of Weichselberger’s building. Rescuers worked for about four hours, and he was the only occupant brought out alive. The master’s wife died.

A royal rescue

The Elector of Bavaria, Maximilian IV Joseph, came to the site, and the rescue made the boy briefly famous. The Elector gave him money and pressed his master to allow him time to study. Another visitor was Joseph Utzschneider, a government official and entrepreneur, who lent him books on optics and mathematics. Fraunhofer used the Elector’s gift to buy a glass-grinding machine and to free himself from part of his apprenticeship. Within a few years Utzschneider would bring him into the most advanced optical business in Germany.

Lesson 02

Benediktbeuern and the art of glass, 1806–1814

In the first years of the century Utzschneider, the instrument maker Georg Reichenbach and the mechanic Joseph Liebherr set up the Mathematisch-Mechanisches Institut in Munich to make surveying and astronomical instruments. Such instruments needed lenses, and good optical glass was then a near-monopoly of a few English makers. The firm set up its own glassworks. In 1806 Fraunhofer joined its optical workshop, and in 1807 the workshop moved to Benediktbeuern, a former Benedictine monastery in the Alpine foothills that the state had secularized.

The glass melting was in the hands of Pierre-Louis Guinand, a Swiss craftsman who had discovered that stirring molten glass with a clay rod removed the streaks (striae) that spoil large lenses. Fraunhofer learned the craft from him and then improved it. By 1809 he directed the optical workshop, and in 1811 he designed a new furnace. He made both crown glass, which disperses colours weakly, and flint glass, which contains lead and disperses them strongly.

From craft to calculation

Achromatic lenses, which combine crown and flint to cancel colour fringes, had been made in England since the 1750s, notably by John Dollond. Makers ground a lens, tested it, and corrected it by hand. Fraunhofer wanted to compute the lens from measured properties of the glass and then make it exactly. That required knowing the refractive index of each melt at several precisely defined colours. Colours, however, blend into one another in a spectrum. He needed fixed marks.

Lesson 03

The dark lines, 1814–1817

Fraunhofer first found a fixed mark in artificial light. In the spectrum of a lamp flame he saw a bright, sharp double line in the yellow, always at the same place. He used it to measure indices. Then he turned his apparatus to sunlight, admitted through a narrow slit and viewed through a prism mounted on a theodolite, a surveying instrument that measured angles precisely. He saw a great many dark lines crossing the spectrum.

The English chemist William Hyde Wollaston had seen a few such lines in 1802 and taken them for boundaries between colours. Fraunhofer showed they were something else. They kept the same positions with different prisms and different glasses, they appeared in light reflected from the Moon and planets, and they were sharp. He counted 574 of them, drew a map of the spectrum, and labelled the strongest with capital letters, from A in the deep red to H in the violet. The bright yellow double line of the lamp coincided with the dark double line he called D.

The lines solved his practical problem: they gave him reference wavelengths that anyone could find again. His memoir, Bestimmung des Brechungs- und Farbenzerstreuungs-Vermögens verschiedener Glasarten, in Bezug auf die Vervollkommnung achromatischer Fernröhre (Determination of the refractive and dispersive power of different kinds of glass, with regard to the perfection of achromatic telescopes), appeared in the Denkschriften of the Bavarian Academy for 1814–15. It tabulated refractive indices of his glasses at the lines B to H. He also pointed a telescope and prism at bright stars, and found that Sirius and other stars showed lines different from the Sun’s. In 1814 he became a partner in the firm, and in 1817 the Academy elected him a corresponding member.

Part II · The physics
Lesson 04

Refraction, dispersion and the prism

For the general reader. Glass slows light down, and it slows blue light slightly more than red. A prism therefore bends blue light more and spreads white light into a spectrum. To design lenses, Fraunhofer needed to know exactly how much each kind of glass bends each colour. He measured it by finding the angle at which a prism bends light least.

Goals
  • Derive the minimum-deviation formula for a prism.
  • Define dispersion and the Abbe number using Fraunhofer’s lines.
  • Understand Cauchy’s empirical formula for \(n(\lambda)\).

Minimum deviation

A prism of apex angle \(A\) and refractive index \(n\) deviates a ray by \(\delta=\theta_1+\theta_4-A\), where \(\theta_1\) is the angle of incidence on the first face and \(\theta_4\) the angle of emergence from the second, and the internal angles satisfy \(\sin\theta_1=n\sin\theta_2\), \(\sin\theta_4=n\sin\theta_3\), \(\theta_2+\theta_3=A\).

Proposition (minimum deviation)

The deviation \(\delta\) has a unique minimum \(\delta_{\min}\), reached when the ray passes symmetrically, \(\theta_2=\theta_3=A/2\). Then

\[ n=\frac{\sin\big(\tfrac12(A+\delta_{\min})\big)}{\sin\big(\tfrac12A\big)}. \]

Proof sketch. By reversibility of light paths, if a minimum occurs at \((\theta_2,\theta_3)\) it also occurs at \((\theta_3,\theta_2)\). Differentiating \(\delta\) with \(d\theta_2=-d\theta_3\) gives \(d\delta/d\theta_2=d\theta_1/d\theta_2-d\theta_4/d\theta_3\), and \(d\theta_1/d\theta_2=n\cos\theta_2/\cos\theta_1\) is strictly increasing in \(\theta_2\) when \(n>1\). So \(d\delta/d\theta_2\) vanishes only at \(\theta_2=\theta_3\), and that point is the minimum. Substituting \(\theta_2=A/2\), \(\theta_1=(A+\delta_{\min})/2\) into Snell’s law gives the formula. The minimum is stationary, so small errors in setting the prism do not affect the measured angle to first order. This is why Fraunhofer, and every refractometer since, used it.

Dispersion

The index varies with wavelength. In transparent glass in the visible, \(n\) decreases as \(\lambda\) increases (normal dispersion), and Augustin-Louis Cauchy’s empirical formula, \(n(\lambda)\approx A_0+B_0/\lambda^2\), fits well. Opticians still describe glass by its index at a yellow line and by its dispersion between the hydrogen lines that Fraunhofer named C (656.3 nm) and F (486.1 nm). Ernst Abbe later combined these into the Abbe number

\[ V=\frac{n_D-1}{n_F-n_C}, \]

large for low-dispersion crown glasses (about 60) and small for dense flints (about 30 to 40). Today the yellow helium d line (587.6 nm) is often used in place of D; the difference is small.

Exercise 4.1A 60° prism of crown glass gives a minimum deviation of 38.65° for sodium light. Find \(n_D\).

Show solution
\(n=\sin(49.325^\circ)/\sin30^\circ=0.7584/0.5=1.5168\).

Exercise 4.2A glass has \(n_C=1.5143\), \(n_D=1.5168\), \(n_F=1.5224\). Find its Abbe number and the difference in minimum deviation between C and F light through a 60° prism.

Show solution
\(V=0.5168/0.0081\approx63.8\). Differentiating the formula, \(d\delta_{\min}/dn=2\sin(A/2)/\cos\big(\tfrac12(A+\delta_{\min})\big)=1/\cos49.3^\circ\approx1.53\) rad. So \(\Delta\delta\approx1.53\times0.0081\approx0.0124\) rad \(\approx0.71^\circ\). Direct computation gives \(38.43^\circ\) for C and \(39.14^\circ\) for F.

Exercise 4.3Fit Cauchy’s formula \(n=A_0+B_0/\lambda^2\) to \(n_C\) and \(n_F\) of Exercise 4.2, and predict \(n_D\) at 589.3 nm.

Show solution
\(1/\lambda^2\) is \(2.3218\) and \(4.2315\ \mu\mathrm m^{-2}\) at C and F. So \(B_0=0.0081/1.9097\approx0.004241\ \mu\mathrm m^2\) and \(A_0=1.5143-0.004241\times2.3218\approx1.50445\). At D, \(1/\lambda^2=2.8796\) and \(n\approx1.50445+0.01221=1.5167\), within \(10^{-4}\) of the measured value.
Lesson 05

The achromatic lens

For the general reader. A single glass lens brings blue light to a focus closer than red, so stars seen through it are fringed with colour. Pairing a strong converging lens of crown glass with a weaker diverging lens of flint glass can cancel the colour while keeping the focusing power. Getting the balance right needs precise measurements of both glasses, which is exactly what Fraunhofer’s dark lines provided.

Goals
  • Derive the condition for a thin achromatic doublet.
  • Compute the powers of the two elements from Abbe numbers.
  • Understand the secondary spectrum that remains.

The doublet condition

A thin lens of index \(n\) has power \(\phi=1/f=(n-1)K\), where \(K=1/R_1-1/R_2\) depends only on the shape. Two thin lenses in contact have power \(\phi=\phi_1+\phi_2\). Varying the wavelength from F to C changes each power by \(\delta\phi_i=(n_{F,i}-n_{C,i})K_i=\phi_i/V_i\), where \(\phi_i\) is evaluated at D.

Achromatic condition (thin lenses in contact)

The doublet has equal focal lengths at C and F if and only if

\[ \frac{\phi_1}{V_1}+\frac{\phi_2}{V_2}=0. \]

With total power \(\phi\), the element powers are

\[ \phi_1=\phi\,\frac{V_1}{V_1-V_2},\qquad \phi_2=-\phi\,\frac{V_2}{V_1-V_2}. \]

The two glasses must have different Abbe numbers, and the larger the difference, the weaker the individual elements and the smaller their aberrations. For a converging doublet with crown first (\(V_1>V_2\)), the crown element is positive and the flint negative.

Secondary spectrum

Bringing C and F to a common focus does not bring every colour there. The residual depends on the partial dispersion \(P=(n_D-n_C)/(n_F-n_C)\) of each glass, and the focal shift of the yellow light relative to the common C–F focus is proportional to \((P_1-P_2)/(V_1-V_2)\). Ordinary crown and flint have similar \(P\) but not equal, so a small coloured halo remains. Fraunhofer measured partial dispersions at many lines and chose glasses and curvatures to minimize the visible residual; he also corrected spherical aberration and coma by his choice of curvatures. His objectives were the best of their day.

Exercise 5.1Design a thin achromatic doublet of focal length 1 m from a crown with \(V_1=64.2\) and a flint with \(V_2=36.4\). Find the focal lengths of the two elements.

Show solution
\(V_1-V_2=27.8\). \(\phi_1=64.2/27.8\approx2.309\ \mathrm{m}^{-1}\), so \(f_1\approx0.433\) m. \(\phi_2=-36.4/27.8\approx-1.309\ \mathrm{m}^{-1}\), so \(f_2\approx-0.764\) m. Check: \(2.309/64.2-1.309/36.4\approx0.0360-0.0360=0\).

Exercise 5.2A single crown lens with \(V=64\) has focal length 1 m at D. How far apart are its foci for C and F light? Compare with the depth of focus of an \(f/15\) telescope, roughly \(\pm2\lambda N^2\) with \(N=15\).

Show solution
\(\delta\phi=\phi/V\), so \(\delta f\approx f/V=1/64\approx15.6\) mm. The depth of focus is about \(\pm2\times0.55\ \mu\mathrm m\times225\approx\pm0.25\) mm. The colour error is about 60 times larger, which is why single-lens refractors had to be made enormously long.
Lesson 06

The prism spectroscope and its resolution

For the general reader. Fraunhofer saw hundreds of lines because his instrument was sharper than anything before it. The trick was to send light through a narrow slit and then to look at the spectrum with a telescope. How many lines a spectroscope can separate depends, surprisingly, only on the thickness of glass the light crosses at the prism’s base and on how strongly that glass disperses.

Goals
  • Describe the slit–prism–telescope arrangement.
  • Define resolving power and derive it for a prism.
  • Check what it takes to separate the sodium D lines.

The arrangement

Light from a narrow slit falls on a prism, and a telescope behind it focuses each wavelength to a separate image of the slit. A dark line is the image of the slit at a wavelength where light is missing. Wollaston had used a slit with the naked eye; Fraunhofer added the telescope and mounted it on a theodolite so that each line’s angular position could be read to seconds of arc. Later instruments added a collimating lens before the prism, so the prism receives a parallel beam.

Resolving power

The resolving power is \(R=\lambda/\Delta\lambda\), where \(\Delta\lambda\) is the smallest wavelength difference that can be distinguished. By Rayleigh’s criterion, two lines are just resolved when the diffraction maximum of one falls on the first minimum of the other. A beam of width \(a\) leaving the prism has angular diffraction half-width \(\lambda/a\) (Lesson 07).

Resolving power of a prism (Rayleigh, 1879)

For a prism used at minimum deviation and filled by the beam, with base length \(b\) (the largest thickness of glass traversed),

\[ R=\frac{\lambda}{\Delta\lambda}=b\,\left|\frac{dn}{d\lambda}\right|. \]

Derivation by Fermat’s principle. The emerging wavefront is a plane. Two wavelengths whose wavefronts differ in tilt by one diffraction width \(\lambda/a\) are just resolved. The ray along the base crosses glass of length \(b\); the ray past the apex crosses none. A change \(\Delta n\) changes the optical path difference between them by \(b\,\Delta n\), and tilts the outgoing wavefront by \(b\,\Delta n/a\). Setting \(b\,\Delta n/a=\lambda/a\) gives \(\Delta\lambda=\lambda/(b\,|dn/d\lambda|)\).

Exercise 6.1The D lines are at 588.995 and 589.592 nm. What resolving power is needed to separate them? What base length of flint glass with \(|dn/d\lambda|=1.0\times10^{-4}\ \mathrm{nm}^{-1}\) is enough?

Show solution
\(R=589.3/0.597\approx990\). Since \(dn/d\lambda=10^{5}\ \mathrm{m}^{-1}\), \(b=R/|dn/d\lambda|\approx990/10^5\ \mathrm m\approx1\) cm. A modest flint prism separates the D doublet, which is why Fraunhofer saw D as double.

Exercise 6.2Show that the angular dispersion of a prism at minimum deviation is \(\dfrac{d\delta}{d\lambda}=\dfrac{2\sin(A/2)}{\cos\theta_1}\dfrac{dn}{d\lambda}\), and explain why a wider slit reduces the number of lines one can see.

Show solution
At minimum deviation \(\sin\theta_1=n\sin(A/2)\) with \(\theta_1=(A+\delta)/2\). Differentiating, \(\tfrac12\cos\theta_1\,d\delta=\sin(A/2)\,dn\), which gives the formula. A slit of angular width \(w\) (as seen from the prism) produces line images of width \(w\); two lines closer in angle than \(w\) merge. So the slit must be narrow enough that its image is no wider than the diffraction width, and Fraunhofer’s fine slit was essential.
Lesson 07

Fraunhofer diffraction

For the general reader. Light passing through a small opening spreads out, and the pattern far away has bright and dark bands. Fraunhofer studied this using a telescope focused at infinity, which brings the far-away pattern up close. The pattern seen this way now bears his name. Mathematically, it is the Fourier transform of the opening.

Goals
  • Derive the far-field amplitude as a Fourier transform of the aperture.
  • Compute the single-slit and circular-aperture patterns.
  • State when the Fraunhofer approximation applies.

From Huygens–Fresnel to the Fourier transform

Let a plane wave of wavelength \(\lambda\), \(k=2\pi/\lambda\), fall normally on a screen with aperture function \(t(x,y)\) (1 in the opening, 0 elsewhere). By the Huygens–Fresnel principle the field at a distant point is a sum of secondary wavelets \(e^{ikr}/r\) from each point of the aperture. At distance \(L\), with observation point \((X,Y)\),

\[ r\approx L+\frac{X^2+Y^2}{2L}-\frac{xX+yY}{L}+\frac{x^2+y^2}{2L}. \]

If the aperture has size \(a\) with \(a^2\ll\lambda L\), the last term is negligible.

Fraunhofer approximation

When the Fresnel number \(N_F=a^2/(\lambda L)\) is small, or when the pattern is observed in the focal plane of a lens, the diffracted amplitude in direction \((\theta_x,\theta_y)\) is, up to a constant phase factor,

\[ U(\theta_x,\theta_y)\propto\iint t(x,y)\,e^{-ik(x\sin\theta_x+y\sin\theta_y)}\,dx\,dy, \]

the two-dimensional Fourier transform of the aperture, evaluated at spatial frequencies \((\sin\theta_x/\lambda,\ \sin\theta_y/\lambda)\).

When \(N_F\) is not small, the quadratic term matters and one obtains Fresnel diffraction, which Augustin Fresnel developed in 1818. A lens of focal length \(f\) adds exactly the quadratic phase needed to cancel it, so the pattern in its focal plane is the Fraunhofer pattern with \(\sin\theta=X/f\). Fraunhofer’s telescope did precisely this.

Single slit

For a slit of width \(a\), \(\int_{-a/2}^{a/2}e^{-ikx\sin\theta}dx=a\,\dfrac{\sin\beta}{\beta}\) with \(\beta=\tfrac12ka\sin\theta\), so

\[ I(\theta)=I_0\left(\frac{\sin\beta}{\beta}\right)^2,\qquad \beta=\frac{\pi a\sin\theta}{\lambda}. \]

Zeros occur at \(a\sin\theta=m\lambda\), \(m=\pm1,\pm2,\dots\). The central maximum has angular half-width \(\lambda/a\): the narrower the slit, the wider the spread.

Circular aperture

For a circular opening of diameter \(D\), the transform involves the Bessel function \(J_1\). George Airy worked it out in 1835:

\[ I(\theta)=I_0\left(\frac{2J_1(u)}{u}\right)^2,\qquad u=\frac{\pi D\sin\theta}{\lambda}. \]

The first zero of \(J_1\) is at \(u\approx3.8317\), so the first dark ring is at \(\sin\theta\approx1.22\,\lambda/D\). This bright central spot, the Airy disc, limits the sharpness of every telescope (Lesson 10).

Exercise 7.1Show that the secondary maxima of the single-slit pattern lie at solutions of \(\tan\beta=\beta\), and estimate the intensity of the first one relative to the centre.

Show solution
\(\frac{d}{d\beta}(\sin\beta/\beta)=(\beta\cos\beta-\sin\beta)/\beta^2=0\) gives \(\tan\beta=\beta\). The first nonzero root is \(\beta\approx4.493\), close to \(3\pi/2\). There \((\sin\beta/\beta)^2\approx(0.976/4.493)^2\approx0.047\): about 4.7 per cent of the central intensity.

Exercise 7.2Light of 589 nm passes a 0.1 mm slit. How far from the slit must a screen be for the Fraunhofer approximation to hold without a lens, taking \(N_F\le0.1\)? What is the width of the central maximum on that screen?

Show solution
\(L\ge a^2/(0.1\lambda)=10^{-8}/(5.89\times10^{-8})\approx0.17\) m. The full width of the central maximum is \(2\lambda L/a\approx2\times5.89\times10^{-7}\times0.17/10^{-4}\approx2\) mm.

Exercise 7.3Use the Fourier-transform form to find the Fraunhofer pattern of two narrow slits a distance \(d\) apart, each of width \(a\). Which factor is due to each slit and which to their spacing?

Show solution
The aperture is a single slit convolved with two delta functions at \(\pm d/2\). The transform of a convolution is a product, so \(U\propto a\,\frac{\sin\beta}{\beta}\cdot2\cos\big(\tfrac12kd\sin\theta\big)\) and \(I\propto\left(\frac{\sin\beta}{\beta}\right)^2\cos^2\!\left(\frac{\pi d\sin\theta}{\lambda}\right)\). The envelope comes from the single slit; the fringes come from the spacing. This is Young’s experiment, and the step from two slits to many is the grating.
Lesson 08

The diffraction grating

For the general reader. A prism spreads light into a spectrum, but how far it bends each colour depends on the glass. Fraunhofer wanted an absolute measure. He made a “grating” of many fine, evenly spaced wires, later of lines ruled on glass. Light passing through many slits interferes so that each wavelength leaves at a definite angle fixed only by the spacing. From the angle and the spacing he could compute the wavelength itself.

Goals
  • Derive the intensity pattern of an \(N\)-slit grating and the grating equation.
  • Derive the resolving power \(R=mN\).
  • Reproduce Fraunhofer’s measurement of a wavelength.

Fraunhofer’s gratings

In his 1821 memoir, Neue Modification des Lichtes durch gegenseitige Einwirkung und Beugung der Strahlen, und Gesetze derselben, Fraunhofer described gratings made of fine parallel wires wound on two screws, with spacings of order a tenth of a millimetre. Viewing a slit through such a grating with his theodolite, he saw sharp spectra on both sides, repeated at regular intervals, crossed by the same dark lines as the prism spectrum. He deduced the grating law, including oblique incidence, and measured the wavelengths of the main solar lines. He then ruled finer gratings on glass with a diamond, and on gold films, and studied gratings used in reflection. Thomas Young had found wavelengths from two-slit fringes in 1802; Fraunhofer was the first to measure the wavelengths of specific, sharp spectral lines.

The \(N\)-slit pattern

Take \(N\) slits of width \(a\) with spacing \(d\). By the convolution argument of Exercise 7.3, the amplitude is the single-slit factor times a geometric sum over the slits. With phase difference \(\varphi=kd\sin\theta\) between neighbours,

\[ \sum_{j=0}^{N-1}e^{ij\varphi}=e^{i(N-1)\varphi/2}\,\frac{\sin(N\varphi/2)}{\sin(\varphi/2)},\qquad I(\theta)=I_1\left(\frac{\sin\beta}{\beta}\right)^2\left(\frac{\sin(N\varphi/2)}{\sin(\varphi/2)}\right)^2. \]
Grating equation

Principal maxima, each of intensity \(N^2\) times that of one slit (before the envelope), occur where \(\varphi=2\pi m\). For light incident at angle \(\theta_i\) and diffracted at \(\theta_m\), measured on the same side of the normal,

\[ d\,(\sin\theta_m-\sin\theta_i)=m\lambda,\qquad m=0,\pm1,\pm2,\dots \]

For normal incidence this is \(d\sin\theta_m=m\lambda\).

Between neighbouring principal maxima there are \(N-1\) zeros. The first zero next to order \(m\) lies where \(N\varphi/2=\pi(mN+1)\), so the principal maxima have angular half-width \(\Delta\theta=\lambda/(Nd\cos\theta_m)\). They become sharper as \(N\) grows, and the angle does not depend on the material.

Resolving power of a grating \[ R=\frac{\lambda}{\Delta\lambda}=mN. \]

Derivation. Differentiating the grating equation, the angular dispersion is \(d\theta/d\lambda=m/(d\cos\theta_m)\). Two wavelengths are resolved when their maxima differ by at least the half-width: \(m\,\Delta\lambda/(d\cos\theta_m)\ge\lambda/(Nd\cos\theta_m)\), so \(\lambda/\Delta\lambda\le mN\).

Exercise 8.1A wire grating has a period of 0.1016 mm (wires of about 0.05 mm, as in Fraunhofer’s early gratings). At what angle does the first-order D line appear at normal incidence? What does this imply for his angular measurements?

Show solution
\(\sin\theta_1=589.3\times10^{-9}/1.016\times10^{-4}\approx5.80\times10^{-3}\), so \(\theta_1\approx0.33^\circ\approx20'\). To get the wavelength to three figures he had to measure angles of tens of minutes to a few seconds of arc. His theodolite, built for surveying, made this possible.

Exercise 8.2A modern grating has 600 lines per millimetre. Find the angles of the D line in each order at normal incidence. How many lines must be illuminated to resolve the D doublet in second order?

Show solution
\(d=1.667\ \mu\)m. \(\sin\theta_1=0.3535\), \(\theta_1\approx20.7^\circ\); \(\sin\theta_2=0.7071\), \(\theta_2=45.0^\circ\); \(\sin\theta_3>1\), so only two orders exist on each side. To resolve D we need \(mN\ge990\), so \(N\ge495\) lines in second order, under a millimetre of grating.

Exercise 8.3Light from 400 to 700 nm falls on a grating. Do the first and second orders overlap? Do the second and third? What ultraviolet wavelength would appear on top of first-order 700 nm?

Show solution
Overlap occurs where \(m\lambda=m'\lambda'\). Second-order 400 nm sits at the angle of first-order 800 nm, beyond 700 nm, so orders 1 and 2 do not overlap. Second-order 700 nm sits at the angle of third-order \(466.7\) nm, so orders 2 and 3 do overlap. Second-order 350 nm falls on first-order 700 nm; it is invisible to the eye but recorded by detectors sensitive to ultraviolet, which is why spectroscopists use order-sorting filters.
Lesson 09

From dark lines to atoms

For the general reader. Fraunhofer did not know what made the dark lines. Forty-five years later Gustav Kirchhoff and Robert Bunsen showed that each element absorbs exactly the colours it emits when hot. The dark lines are fingerprints of elements in the Sun’s atmosphere. A further half century later, Niels Bohr explained why the hydrogen lines that Fraunhofer had called C and F sit where they do.

Goals
  • State Kirchhoff’s laws of emission and absorption.
  • Identify Fraunhofer’s main lines with elements.
  • Compute the hydrogen lines C and F from the Balmer–Rydberg formula.

Kirchhoff and Bunsen, 1859

In 1859 Kirchhoff, working with Bunsen in Heidelberg, passed sunlight through a sodium flame. The dark D lines became darker. He concluded that a gas absorbs the same wavelengths it emits, and that the D lines are sodium in the solar atmosphere.

Kirchhoff’s law of thermal radiation (1859–60)

For a body in thermal equilibrium at temperature \(T\), the ratio of its spectral emissivity to its spectral absorptivity is the same for all bodies and equals the emission of a perfect absorber (a black body):

\[ \frac{\varepsilon_\lambda}{\alpha_\lambda}=B_\lambda(T). \]

Kirchhoff’s spectroscopic rules follow. A hot dense body gives a continuous spectrum. A hot thin gas gives bright lines. A cooler gas in front of a hotter continuous source absorbs at those same wavelengths and gives dark lines. The Sun’s deep layers act as the continuous source and its cooler outer layers as the absorbing gas.

Identifications

Fraunhofer’s main lines are now identified: A and B are absorption by oxygen in the Earth’s atmosphere (telluric lines); C and F are hydrogen Hα and Hβ; D is the sodium doublet; E and part of G are iron; the b group is mostly magnesium; H and K, at 396.8 and 393.4 nm, are ionized calcium.

A, B759.4, 686.7 nm: O2 in Earth’s atmosphere
C656.3 nm: hydrogen Hα
D1, D2589.6, 589.0 nm: sodium
E2527.0 nm: iron
F486.1 nm: hydrogen Hβ
H, K396.8, 393.4 nm: ionized calcium

The hydrogen lines

In 1885 Johann Balmer found an empirical formula for the visible hydrogen lines, generalized by Johannes Rydberg:

\[ \frac{1}{\lambda}=R_{\mathrm H}\left(\frac{1}{2^2}-\frac{1}{n^2}\right),\qquad n=3,4,5,\dots,\qquad R_{\mathrm H}\approx1.09678\times10^{7}\ \mathrm{m}^{-1}. \]

Bohr’s model of 1913 derived it: an electron falling from level \(n\) to level 2 emits a photon of energy \(E_n-E_2\), with \(E_n=-13.6\ \mathrm{eV}/n^2\) (corrected for the finite proton mass). Absorption runs the other way, so cooler hydrogen in the solar atmosphere removes exactly these wavelengths.

Exercise 9.1Compute the wavelengths for \(n=3\) and \(n=4\). Fraunhofer’s C and F are tabulated as 656.28 and 486.13 nm, measured in air. Explain the small discrepancy.

Show solution
\(n=3\): \(1/\lambda=R_{\mathrm H}\cdot5/36\), \(\lambda=656.47\) nm. \(n=4\): \(1/\lambda=R_{\mathrm H}\cdot3/16\), \(\lambda=486.27\) nm. These are vacuum wavelengths. In air the wavelength is shorter by the factor \(n_{\text{air}}\approx1.00028\), giving \(656.29\) and \(486.14\) nm, in agreement.

Exercise 9.2How could Fraunhofer, without knowing their origin, have distinguished the telluric lines A and B from lines formed in the Sun?

Show solution
Telluric lines are formed in the Earth’s air, so they grow stronger when the Sun is low and its light crosses more atmosphere, and they show no shift between the Sun’s approaching and receding limbs. Solar lines keep a fixed strength with altitude and show the small Doppler shifts of solar rotation. Both tests were used later in the nineteenth century.
Lesson 10

Telescopes, resolution and parallax

For the general reader. Fraunhofer’s glass and lens designs made refracting telescopes of unprecedented size and quality. Mounted so that a clock could follow the stars, they let astronomers measure tiny angles. With one of them Wilhelm Struve measured thousands of double stars, and with another Friedrich Bessel measured, in 1838, the first reliable distance to a star.

Goals
  • Derive the diffraction limit of a telescope and Rayleigh’s criterion.
  • Understand the equatorial mount and the heliometer.
  • Relate parallax to distance and see how positions can be measured more finely than the resolution.

Resolution

A star is effectively a point at infinity. A perfect objective of diameter \(D\) images it as the Airy pattern of Lesson 07.

Rayleigh criterion

Two point sources of equal brightness are just resolved when the centre of one Airy pattern falls on the first dark ring of the other. The minimum angular separation is

\[ \theta_R\approx1.22\,\frac{\lambda}{D}. \]

For a 24 cm objective in visible light (550 nm), \(\theta_R\approx2.8\times10^{-6}\) rad \(\approx0.58''\). Struve’s Dorpat refractor, delivered in 1824, had an objective of about 24 cm, the largest refractor in the world at the time. Fraunhofer mounted it on an equatorial mount with one axis parallel to the Earth’s axis, driven by clockwork, so that a star stayed in the field while the observer measured it. With it Struve measured 2,714 double and multiple stars between 1824 and 1837.

Parallax

As the Earth orbits the Sun, a nearby star shifts against distant ones. Its annual parallax \(p\), half the full shift, is related to its distance by

\[ d=\frac{1\ \mathrm{AU}}{\tan p}\approx\frac{1}{p\,[\text{arcsec}]}\ \text{parsecs},\qquad 1\ \mathrm{pc}\approx3.086\times10^{16}\ \mathrm m\approx3.26\ \text{light-years}. \]

Every known parallax is below one second of arc. Bessel, at Königsberg, used a heliometer of about 16 cm aperture built by Fraunhofer’s firm and delivered after his death. A heliometer’s objective is cut in two along a diameter, and the halves slide along the cut, each forming its own image. Sliding them until the image of one star from one half falls on another star from the other half measures their separation by a micrometer screw, with high precision. In 1838 Bessel announced a parallax of 0.314″ for 61 Cygni. Struve announced a parallax for Vega in 1837 and confirmed it in 1840, and Thomas Henderson measured Alpha Centauri at about the same time.

Precision beyond resolution

Bessel’s parallax was smaller than the resolution limit of his instrument. There is no contradiction. Resolution limits the ability to separate two images; position measurement locates the centre of a single image. With \(N\) independent measurements, or \(N\) detected photons, the centroid of an image of width \(\sigma\) is found to about \(\sigma/\sqrt N\).

Exercise 10.1Compute the Rayleigh limit of Bessel’s 16 cm heliometer at 550 nm, and the distance of 61 Cygni in parsecs and light-years from \(p=0.314''\).

Show solution
\(\theta_R=1.22\times5.5\times10^{-7}/0.16\approx4.2\times10^{-6}\) rad \(\approx0.86''\). Distance \(1/0.314\approx3.18\) pc \(\approx10.4\) light-years. The modern value is about 3.5 pc; Bessel’s error was under 10 per cent.

Exercise 10.2Each heliometer setting locates a separation with an error of about 0.2″. Roughly how many independent settings are needed to determine a parallax of 0.3″ to 10 per cent, assuming the parallax is half the difference between measurements six months apart, each the mean of \(n\) settings?

Show solution
Each mean has error \(0.2/\sqrt n\). The difference of two means has error \(0.2\sqrt{2/n}\), and half of it \(0.1\sqrt{2/n}\). Setting this equal to \(0.03''\) gives \(\sqrt{2/n}=0.3\), so \(n\approx22\) settings at each epoch. In practice Bessel used many comparison measurements over more than a year to fit the full parallactic ellipse.

Exercise 10.3Why did large refractors of Fraunhofer’s type typically have focal ratios around \(f/15\) or slower, rather than \(f/5\)? Use the secondary spectrum of Lesson 05.

Show solution
The secondary spectrum of a crown–flint achromat leaves a residual focal spread proportional to the focal length, about \(f/2000\). The depth of focus grows as \(N^2=(f/D)^2\). At fixed \(D\), making \(f\) longer increases the colour spread linearly but the tolerance quadratically, so slow focal ratios keep the residual colour within the depth of focus. The same holds for spherical aberration, which also shrinks with slower ratios.
Part III · Life and legacy
Lesson 11

Munich, fame and early death, 1819–1826

In 1819 the optical workshop returned from Benediktbeuern to Munich, while the glassworks stayed in the monastery. Fraunhofer, now a partner, ran the firm that became known as Utzschneider und Fraunhofer. Its telescopes, microscopes, heliometers and surveying instruments went to observatories across Europe, and its objective lenses were the best available. He kept his methods for making glass secret, and the firm’s reputation rested on this monopoly.

He also became a scientist in his own right. His 1821 memoir on diffraction appeared in the Academy’s Denkschriften, and a shorter report on further experiments, including gratings used in reflection, followed in 1823. The Bavarian Academy made him an extraordinary member in 1821. The University of Erlangen gave him an honorary doctorate in 1822. In 1823 he became conservator of the Academy’s physical cabinet, with a professor’s salary, and in the summer of that year lectured on mathematical and physical optics. In 1824 King Maximilian I Joseph made him a knight of the Order of Merit of the Bavarian Crown, which conferred personal nobility and the name von Fraunhofer. The same year he was elected to the Leopoldina, and the great refractor arrived at Dorpat.

Illness and death

His health had been poor for years. In 1825 he caught a severe chill on a raft trip on the Isar and did not recover. He died in Munich on 7 June 1826, aged 39, of a chest illness. It has been suggested that long exposure to heavy-metal vapours from the glass furnaces contributed. He never married. He was buried in Munich’s Old Southern Cemetery, and his memorial carries the Latin phrase Approximavit sidera, “he brought the stars closer”.

DiscussionFraunhofer published his physics openly but kept his glass-making methods secret. What were the commercial and scientific consequences? Compare with modern tensions between academic openness and industrial secrecy.

Lesson 12

The stars brought closer

After his death the firm continued under his successors, including Georg Merz, and kept supplying great refractors. A 9-inch refractor of Fraunhofer’s design at the new Berlin Observatory was the telescope with which Johann Galle found Neptune in 1846. Bessel’s heliometer measurement of 1838 gave the first reliable distance to a star.

The lines he mapped became the foundation of astrophysics. Kirchhoff and Bunsen’s explanation in 1859 turned them into a chemical analysis of the Sun and stars. Within a decade William Huggins and Angelo Secchi were classifying stellar spectra, and the Doppler shifts of the same lines soon gave stellar velocities. The grating, refined by Henry Rowland in the 1880s, became the standard tool of spectroscopy, from the laboratory to space telescopes.

Legacy

  • Optics: computed achromatic objectives, the use of spectral lines as wavelength standards, and the letters C, D, F still used to specify optical glass.
  • Physics: the diffraction grating, the measurement of wavelengths, and the far-field limit of diffraction, called Fraunhofer diffraction.
  • Astronomy: stellar spectroscopy, the clock-driven equatorial mount, and the instruments of the first parallax measurements.
  • Honours: Germany’s largest organization for applied research, the Fraunhofer-Gesellschaft, founded in 1949, bears his name, as does a lunar crater. The former glassworks at Benediktbeuern is preserved as a museum.

Final projectUsing the grating equation and the line wavelengths of Lesson 09, design a simple solar spectroscope that would let a student see the D doublet separated and measure the wavelength of the F line to 0.1 nm. Specify the grating, the order, the slit width and the focal length of the viewing optics, and justify each choice with the formulas of Part II.

Reference

Sources and further reading

Biography

  1. Joseph von Fraunhofer, Wikipedia.
  2. Fraunhofer, Joseph von, Neue Deutsche Biographie 5 (1961) and Allgemeine Deutsche Biographie, Deutsche Biographie.
  3. Joseph von Fraunhofer, New World Encyclopedia.
  4. M. W. Jackson, Spectrum of Belief: Joseph von Fraunhofer and the Craft of Precision Optics, MIT Press, 2000.
  5. Deutsches Museum Archive, Nachlass Fraunhofer (NL 014), finding aid.

Physics

  1. J. Fraunhofer, Bestimmung des Brechungs- und Farbenzerstreuungs-Vermögens verschiedener Glasarten, in Bezug auf die Vervollkommnung achromatischer Fernröhre, Denkschriften der Königlichen Akademie der Wissenschaften zu München 5 (1814–15).
  2. J. Fraunhofer, Neue Modification des Lichtes durch gegenseitige Einwirkung und Beugung der Strahlen, und Gesetze derselben, Denkschriften 8 (1821–22).
  3. E. Lommel (ed.), Joseph von Fraunhofer’s gesammelte Schriften, Munich, 1888.
  4. Fraunhofer lines, Wikipedia (modern wavelengths and identifications).
  5. M. Born and E. Wolf, Principles of Optics, Cambridge University Press (diffraction, gratings, resolving power).
  6. E. Hecht, Optics, Pearson (prisms, achromats, Fraunhofer diffraction).
  7. G. Kirchhoff, Über die Fraunhofer’schen Linien, Monatsberichte der Königlichen Preussischen Akademie der Wissenschaften zu Berlin (1859).
  8. M. Perryman, The history of astrometry, arXiv:1209.3563.