courseshub.world · Lives in Mathematics and Physics

Thomas Young

Thomas Young, M.D., F.R.S.

A course in two strands: the life of a Quaker prodigy and London physician who worked across optics, mechanics, physiology and ancient languages, and the physics he left behind, from the interference of light to the modulus of elasticity.

Born 13 June 1773, Milverton Died 10 May 1829, London Interference Bakerian Lecture, 1801 Level advanced undergraduate
Two coherent sources. Along the highlighted curves crests meet crests and the waves reinforce; on the screen the intensity follows \(\cos^2(\pi d\,y/\lambda D)\).
Lesson 00

How to use this course

Thomas Young is remembered for a handful of things that seem to belong to different people. Physicists know the double-slit experiment. Engineers know Young’s modulus. Chemists know Young’s equation for the contact angle of a drop. Vision scientists know the Young–Helmholtz theory of colour. Egyptologists know his work on the Rosetta Stone. All of these came from one London physician, mostly in his spare time, between 1793 and 1829.

Prerequisites for Part II
  • Trigonometry and the superposition of sinusoids.
  • Single-variable calculus and simple differential equations.
  • Newtonian mechanics: forces, pressure, Hooke’s law.
  • For Lesson 09, thin-lens optics. For Lesson 10, the one-dimensional wave equation.

Each technical lesson opens with a paragraph for the general reader, then gives precise statements, derivations and exercises with folded solutions. Young wrote almost entirely in words and avoided equations, which partly explains why his contemporaries found him hard to follow. The lessons state his results in modern notation and mark where later workers, Augustin-Jean Fresnel above all, made his ideas quantitative.

Reference

Timeline

1773Born 13 June at Milverton, Somerset, eldest of ten children of Thomas Young and Sarah Davis, Quakers.
1782–86School at Compton, Dorset. Learns classical and modern languages, Newtonian physics and optics.
1787–92Tutor to Hudson Gurney, near Ware, Hertfordshire, and in London.
1792Begins medical study in London.
179330 May: Observations on vision read to the Royal Society, on accommodation.
1794Medical study at Edinburgh. 19 June: elected Fellow of the Royal Society, aged 20.
1795–96Göttingen; doctorate examination passed 30 April 1796.
1797Inherits the estate of his great-uncle Richard Brocklesby. Enters Emmanuel College, Cambridge, leaving the Quakers.
1799Medical practice at 48 Welbeck Street, London.
180027 November: Bakerian Lecture On the mechanism of the eye.
180112 November: Bakerian Lecture On the theory of light and colours: interference, wavelengths, three-colour vision. Professor of natural philosophy at the Royal Institution.
1803Resigns from the Royal Institution. 24 November: Experiments and calculations relative to physical optics. Henry Brougham’s anonymous attacks in the Edinburgh Review (1803–04).
180414 June: marries Eliza Maxwell. Essay on the cohesion of fluids (published 1805).
1807A Course of Lectures on Natural Philosophy and the Mechanical Arts: the modulus of elasticity, the two-slit figure.
1808Croonian Lecture on the functions of the heart and arteries.
1811Physician to St George’s Hospital.
1814Begins work on the Rosetta Stone; translates its demotic text.
1817–18Letters to François Arago suggesting that light vibrates transversely.
1818Secretary to the Board of Longitude and superintendent of the Nautical Almanac. Article “Egypt” in the Encyclopædia Britannica supplement.
1827One of eight foreign associates of the Académie des sciences, Paris.
1829Dies 10 May in London, aged 55. Buried at Farnborough, Kent.
Part I · Formation
Lesson 01

Milverton, Minehead, Compton, 1773–1787

Thomas Young was born on 13 June 1773 at Milverton in Somerset, the first of ten children of Thomas Young, a Quaker cloth merchant and banker, and Sarah Davis. He spent much of his early childhood with his maternal grandfather, Robert Davis, at Minehead, and learned to read very young. His first schoolmasters had little to teach him. At a boarding school near Bristol he worked through the set books in half the expected time.

From 1782 to 1786 he attended a school at Compton in Dorset that let pupils advance at their own pace. He left with Greek, Latin, French, Italian and Hebrew, a working knowledge of Newton’s physics and optics, and practice in building optical instruments. Afterwards he added Arabic, Persian, Syriac, Chaldee and Samaritan. Languages and natural philosophy stayed side by side in his life for the next forty years.

At about fourteen he became tutor and companion to Hudson Gurney, grandson of the Quaker banker David Barclay, living at a house near Ware in Hertfordshire and in London. Until 1792 he used the post to read Euclid, Newton’s Principia and Opticks.

Lesson 02

Medicine in three countries, 1792–1799

His great-uncle, the physician Richard Brocklesby, encouraged him toward medicine. Young began study in London in 1792, at the hospitals and anatomy schools. In the course of dissecting an ox’s eye he formed a theory of how the eye focuses at different distances, by a change in the shape of the crystalline lens. The paper, Observations on vision, was read to the Royal Society on 30 May 1793. On 19 June 1794, still only twenty, he was elected a Fellow.

In 1794 he moved to Edinburgh, then the leading British medical school, and in October 1795 to Göttingen, where he passed his doctoral examination on 30 April 1796. His dissertation drew on anatomy, sound and language, and an appendix proposed a universal phonetic alphabet. He then toured German cities, including Berlin, Dresden and Weimar, and returned to England in February 1797.

A change in the rules for licensing physicians required study at an English university, so in 1797 Young entered Emmanuel College, Cambridge. He had to leave the Society of Friends to do so. The same year Brocklesby died and left him a fortune that made him independent. At Cambridge he studied physics on his own, especially sound, and thought about why the colours of soap films and the beats of two organ pipes might be the same phenomenon. In 1799 he set up as a physician at 48 Welbeck Street in London. His first papers on sound and light, published that year and the next, appeared under his name, but he later published some work anonymously to protect his medical practice.

Lesson 03

The Royal Institution, 1799–1807

In 1800 Young read Outlines of experiments and inquiries respecting sound and light to the Royal Society, arguing that light might be a wave like sound. On 27 November 1800 he gave the Bakerian Lecture, On the mechanism of the eye, with careful measurements on his own eyes. They showed that accommodation comes from the lens, and described the astigmatism of his own eye. On 12 November 1801 he gave a second Bakerian Lecture, On the theory of light and colours, which stated the principle of interference and gave the first table of wavelengths of the colours (Lesson 04).

In 1801 Count Rumford’s new Royal Institution appointed him professor of natural philosophy. Beginning in January 1802 he gave a course of fifty lectures on mechanics, hydrodynamics, physics and mathematics. Listeners found them dense and allusive. He resigned in the summer of 1803, fearing that the post would hurt his medical practice. On 24 November 1803 he read Experiments and calculations relative to physical optics, describing the experiment with a narrow card in a sunbeam (Lesson 05).

Brougham’s attack

Between 1803 and 1804 the Edinburgh Review published anonymous reviews of Young’s optical papers, written by Henry Brougham, later Lord Chancellor. They ridiculed the wave theory as unworthy of the Royal Society. Young replied in a pamphlet that sold very few copies. A publisher withdrew from printing his lectures, and Young turned more fully to medicine. On 14 June 1804 he married Eliza Maxwell. In 1807 the lectures appeared at last, in two volumes, as A Course of Lectures on Natural Philosophy and the Mechanical Arts, with the modulus of elasticity and the famous figure of two-source interference.

Part II · The physics
Lesson 04

The principle of interference

For the general reader. Two musical notes of nearly the same pitch produce beats: the loudness rises and falls as the waves fall into and out of step. Young saw that the coloured rings Newton had measured in thin films are the same effect for light. Light reflected from the top and bottom of a film travels slightly different distances, and the two waves add or cancel depending on that difference. From Newton’s own measurements Young extracted the wavelength of each colour.

Goals
  • State Young’s law of interference and express it with phases.
  • Derive the conditions for bright and dark thin-film fringes and for Newton’s rings.
  • Reproduce Young’s 1801 wavelengths from Newton’s data.
Young’s law of interference (1801, Proposition VIII)

When two undulations from different origins coincide in direction, their joint effect is the combination of the motions belonging to each. Two coherent waves of wavelength \(\lambda\) and equal amplitude, whose paths differ by \(\Delta\), give intensity

\[ I=4I_0\cos^2\!\Big(\frac{\pi\Delta}{\lambda}\Big), \]

maximal when \(\Delta=m\lambda\) and zero when \(\Delta=(m+\tfrac12)\lambda\), \(m\) an integer.

Derivation. Represent the waves by \(A\cos(\omega t)\) and \(A\cos(\omega t-k\Delta)\), \(k=2\pi/\lambda\). Their sum is \(2A\cos(k\Delta/2)\cos(\omega t-k\Delta/2)\). The intensity is proportional to the square of the amplitude: \(4A^2\cos^2(\pi\Delta/\lambda)\).

Thin films

A film of index \(n\) and thickness \(t\), viewed in reflection at near-normal incidence, produces two reflected waves whose optical path differs by \(2nt\). Young also saw that one of them suffers an extra half-period shift when the reflection is from a denser medium. He predicted that if the film were made of a substance intermediate in index between the two bounding glasses, the shift would disappear and the centre of Newton’s rings would turn bright. He confirmed it with oil of sassafras between a crown-glass lens and a flint-glass prism.

Newton’s rings

A lens of radius of curvature \(R\) rests on a flat plate, leaving an air gap of thickness \(t\approx r^2/(2R)\) at distance \(r\) from the contact point. In reflected light, with the half-period shift at the lower surface, the dark rings have radii

\[ r_m=\sqrt{m\lambda R},\qquad m=0,1,2,\dots \]

Derivation. The path difference is \(2t+\lambda/2\). Darkness requires \(2t+\lambda/2=(m+\tfrac12)\lambda\), i.e. \(2t=m\lambda\), and with \(t=r^2/(2R)\) this gives \(r^2=m\lambda R\). The central spot (\(m=0\)) is dark.

Exercise 4.1Newton’s measurements put the brightest part of the first ring, in yellow light, where the air gap is about \(1/178\,000\) inch thick. Use Young’s interference law, including the half-period shift, to deduce the wavelength. Compare with Young’s tabulated yellow, \(0.0000227\) inch, and convert to nanometres.

Show solution
The first bright ring needs \(2t+\lambda/2=\lambda\), so \(\lambda=4t=4/178\,000\approx2.25\times10^{-5}\) inch. Young gave \(2.27\times10^{-5}\) inch. In SI units, \(2.27\times10^{-5}\times25.4\) mm \(\approx577\) nm, close to the modern value for yellow light.

Exercise 4.2Young’s table gives the extreme red as \(0.0000266\) inch and the extreme violet as \(0.0000167\) inch. Convert both to nanometres and compute the ratio. How does it compare with the range usually quoted for visible light?

Show solution
Red: \(2.66\times10^{-5}\times2.54\times10^{7}\) nm \(\approx676\) nm. Violet: \(1.67\times10^{-5}\times2.54\times10^{7}\approx424\) nm. Ratio \(\approx1.59\). Modern figures run from about 380–400 nm to 700–750 nm, a ratio of roughly 1.8–1.9. Young’s values are good for the parts of the spectrum bright enough to see in Newton’s rings.

Exercise 4.3A soap film (\(n=1.33\)) in air looks green (\(\lambda=530\) nm) at normal incidence in reflection. Find the two smallest possible thicknesses.

Show solution
Only the front reflection (air to soap) has the half-period shift. Bright reflection needs \(2nt=(m+\tfrac12)\lambda\). For \(m=0\): \(t=\lambda/(4n)\approx99.6\) nm. For \(m=1\): \(t=3\lambda/(4n)\approx299\) nm.
Lesson 05

Two apertures and the edge of a shadow

For the general reader. Behind a thin object placed in a narrow beam of sunlight, the shadow is striped. Young found that the stripes inside the shadow vanish if he blocks the light passing one edge, even though the light passing the other edge is untouched. The stripes therefore need light from both sides together. The same reasoning applies to light passing two small openings, the arrangement now called Young’s double slit.

Goals
  • Derive the fringe spacing for two narrow apertures.
  • Add the effect of finite slit width.
  • Understand Young’s card experiment and the limits of his account of edges.

The card experiment (1803)

Young let sunlight through a small hole in a window shutter and held a slip of card about one-thirtieth of an inch wide in the beam. Fringes appeared inside the shadow. When he put a screen at one edge of the card, intercepting the light that passed that side, the internal fringes disappeared. He concluded that they came from the interference of light passing the two edges. He accounted for the external fringes by interference between the direct light and light “reflected” from the edge. Fresnel later showed that this edge account was not quite right and replaced it with the Huygens–Fresnel integral.

Two slits

Double-slit pattern

Two slits of width \(b\), centres separated by \(d\), are lit by a plane wave of wavelength \(\lambda\). On a distant screen at angle \(\theta\) the intensity is

\[ I(\theta)=I_{\max}\,\cos^2\!\Big(\frac{\pi d\sin\theta}{\lambda}\Big)\,\Big(\frac{\sin\beta}{\beta}\Big)^2,\qquad \beta=\frac{\pi b\sin\theta}{\lambda}. \]

For small angles on a screen at distance \(D\), the fringes are spaced by \(\lambda D/d\).

Derivation. In the far field the amplitude is the Fourier transform of the aperture. A single slit gives \(\int_{-b/2}^{b/2}e^{-ikx\sin\theta}dx=b\,\frac{\sin\beta}{\beta}\). Two slits centred at \(\pm d/2\) multiply this by \(e^{ikd\sin\theta/2}+e^{-ikd\sin\theta/2}=2\cos(\pi d\sin\theta/\lambda)\). Squaring gives the result. Young had only the \(\cos^2\) factor; the envelope is Fresnel’s and Fraunhofer’s.

Exercise 5.1Young’s card was about \(1/30\) inch wide. Treating its two edges as coherent sources a distance \(d\) apart, estimate the fringe spacing inside the shadow on a screen \(2\) m away, for \(\lambda=570\) nm.

Show solution
\(d\approx0.85\) mm. Spacing \(\lambda D/d=5.7\times10^{-7}\times2/8.5\times10^{-4}\approx1.3\) mm. Easily seen with the naked eye or a lens, which is why the experiment worked with sunlight and a card.

Exercise 5.2In a double slit with \(d=4b\), which interference maxima are missing?

Show solution
Interference maxima are at \(d\sin\theta=m\lambda\). The single-slit envelope vanishes at \(b\sin\theta=p\lambda\), \(p\ne0\), i.e. \(d\sin\theta=4p\lambda\). So orders \(m=\pm4,\pm8,\dots\) are missing.

Exercise 5.3A thin plate of glass (\(n=1.5\)) of thickness \(6\ \mu\)m covers one slit. By how many fringes does the pattern shift for \(\lambda=600\) nm, and in which direction?

Show solution
The plate adds optical path \((n-1)t=3\ \mu\)m \(=5\lambda\). The pattern shifts by 5 fringes toward the covered slit, since the zero of path difference moves to where the geometric path from the covered slit is shorter. Young used a similar argument to suggest that light travels more slowly in denser media, the opposite of the corpuscular prediction.
Lesson 06

Polarization and transverse waves

For the general reader. In 1808 Étienne-Louis Malus found that light reflected from glass at certain angles is polarized: it behaves differently when turned about its own direction. Young at first saw this as the strongest objection to his wave theory, since waves in a fluid vibrate along their direction of travel and have no sidedness. In 1817 he found a way out. Light might vibrate across its path, like a wave running along a shaken rope.

Goals
  • Show that transverse vibrations can be polarized and longitudinal ones cannot.
  • Derive Malus’s law.
  • See why transverse waves require a medium that resists shear.

In letters to Arago in 1817 and 1818 Young suggested that light might involve a transverse component of vibration, and compared it to the undulations of a cord agitated at one end. Arago showed the idea to Fresnel, who saw that it explained why beams polarized at right angles do not interfere, and in 1821 proposed that the vibration is wholly transverse. Fresnel credited Young with stating the idea first.

Malus’s law (1809)

Linearly polarized light of intensity \(I_0\) passes an ideal analyser whose transmission axis makes angle \(\varphi\) with the plane of vibration. The transmitted intensity is \(I=I_0\cos^2\varphi\).

Derivation (transverse model). The vibration is a vector \(\mathbf A\) perpendicular to the ray. An analyser passes only the component along its axis, \(A\cos\varphi\). Intensity goes as amplitude squared. A longitudinal vibration has no component across the ray and cannot depend on \(\varphi\), which is why polarization forces transversality.

The elastic aether

In an elastic solid of shear modulus \(G\), bulk modulus \(K\) and density \(\rho\), there are transverse waves at speed \(c_T=\sqrt{G/\rho}\) and longitudinal waves at \(c_L=\sqrt{(K+\tfrac43G)/\rho}\). A fluid has \(G=0\) and cannot carry transverse waves. Young therefore concluded that the luminiferous medium must behave like a solid, and he was troubled that the planets move through it without resistance. The difficulty lasted until Maxwell’s electromagnetic theory replaced the elastic aether.

Exercise 6.1Unpolarized light passes three ideal polarizers with axes at \(0^\circ\), \(45^\circ\) and \(90^\circ\). What fraction is transmitted? What if the middle one is removed?

Show solution
First polarizer: \(\tfrac12\). Then \(\cos^245^\circ=\tfrac12\) twice: total \(\tfrac18\). Without the middle polarizer the last one is crossed with the first, and nothing passes. Inserting a polarizer increases the transmission, a clear sign that the vibration is a transverse vector.

Exercise 6.2A taut string of tension \(T\) and mass per length \(\mu\) carries transverse waves. Show that the wave speed is \(\sqrt{T/\mu}\), and explain why the string can carry two independent polarizations.

Show solution
For small displacement \(y(x,t)\), the net transverse force on an element \(dx\) is \(T\,\partial^2y/\partial x^2\,dx\), so \(\mu\,y_{tt}=T\,y_{xx}\), the wave equation with speed \(\sqrt{T/\mu}\). The same equation holds for displacement \(z(x,t)\) in the perpendicular direction, so any transverse motion is a combination of two independent polarizations, as Young’s analogy required.
Lesson 07

Elasticity and Young’s modulus

For the general reader. Hooke’s law says that a spring stretches in proportion to the load. But the constant depends on the size and shape of the spring as well as on what it is made of. Young separated the material from the geometry. His modulus of elasticity is a single number for steel, another for oak, from which the stretch of any rod can be computed.

Goals
  • Define stress, strain and Young’s modulus, and Young’s “modulus height”.
  • Derive the speed of longitudinal waves in a rod.
  • Compute the stored energy and simple deflections.
Definition (Young, 1807, in modern form)

For a uniform rod of length \(L\) and cross-section \(A\) under axial force \(F\), with extension \(\delta L\), the stress is \(\sigma=F/A\) and the strain \(\varepsilon=\delta L/L\). In the linear regime \(\sigma=E\,\varepsilon\), and \(E\) is Young’s modulus, a property of the material alone.

Young expressed the modulus as a length. He defined it as the height of a column of the same substance whose weight, pressing on its base, would compress it by the full length of the column, if the linear law held that far. In modern terms this height \(M\) satisfies \(\rho gM=E\). The modulus is not Young’s alone: Leonhard Euler and Giordano Riccati had used similar quantities. Young’s formulation made it standard in engineering.

Longitudinal waves in a rod

Small longitudinal displacements \(u(x,t)\) in a thin rod of density \(\rho\) satisfy \(\rho\,u_{tt}=E\,u_{xx}\), so they travel at speed \(c=\sqrt{E/\rho}\).

Derivation. The strain at \(x\) is \(u_x\), so the force across a section is \(EAu_x\). The net force on a slice \(dx\) is \(EA\,u_{xx}\,dx\), and its mass is \(\rho A\,dx\). Newton’s second law gives the wave equation. Young noted that the speed of sound in a substance equals the speed acquired by falling through half its modulus height: since \(c^2=E/\rho=gM\), and a fall through height \(h\) gives \(v^2=2gh\), the height is \(M/2\).

Exercise 7.1Steel has \(E\approx200\) GPa and \(\rho\approx7850\) kg/m\(^3\). Find the modulus height and the speed of sound in a steel rod.

Show solution
\(M=E/(\rho g)=2\times10^{11}/(7850\times9.81)\approx2.6\times10^{6}\) m, about 2600 km. \(c=\sqrt{E/\rho}=\sqrt{2.55\times10^{7}}\approx5050\) m/s.

Exercise 7.2A steel wire 2 m long, 1 mm in diameter, carries 10 kg. Find its extension and the elastic energy stored.

Show solution
\(A=\pi(5\times10^{-4})^2\approx7.85\times10^{-7}\) m\(^2\). \(\sigma=98.1/7.85\times10^{-7}\approx1.25\times10^8\) Pa, \(\varepsilon=\sigma/E\approx6.2\times10^{-4}\), so \(\delta L\approx1.25\) mm. Energy \(\tfrac12F\,\delta L\approx\tfrac12\times98.1\times1.25\times10^{-3}\approx0.061\) J.

Exercise 7.3Show that the energy stored per unit volume in a stretched rod is \(\sigma^2/(2E)\). Which of two materials with the same breaking stress stores more energy before breaking?

Show solution
Work done is \(\int F\,d(\delta L)=\tfrac12F\,\delta L=\tfrac12\sigma A\,\varepsilon L\), so per unit volume \(\tfrac12\sigma\varepsilon=\sigma^2/(2E)\). For the same breaking stress, the material with the smaller modulus stores more energy: it stretches further before failing. This is why springs and bows favour materials with high strength and moderate stiffness.
Lesson 08

Capillarity and surface tension

For the general reader. Water climbs up a narrow glass tube; mercury sinks. A drop on a leaf beads up, on clean glass it spreads. In an essay published in 1805, Young explained these effects with two ideas: the surface of a liquid behaves as if under uniform tension, and where liquid meets solid it makes a definite angle set by the materials. He wrote it all in words. Pierre-Simon Laplace, working independently, gave the mathematical form of the first idea the same year.

Goals
  • State Young’s equation for the contact angle.
  • Derive the Young–Laplace pressure jump.
  • Derive Jurin’s law for the rise in a capillary tube.
Young’s equation

A liquid drop at rest on a flat solid meets it at a contact angle \(\theta\) determined by the three interfacial tensions:

\[ \gamma_{SV}=\gamma_{SL}+\gamma_{LV}\cos\theta. \]

Derivation. Balance the forces per unit length along the solid at the contact line: \(\gamma_{SV}\) pulls outward, \(\gamma_{SL}\) inward, and the liquid surface pulls with \(\gamma_{LV}\) at angle \(\theta\), contributing \(\gamma_{LV}\cos\theta\) inward. Equivalently, moving the contact line by \(dx\) changes the free energy per unit length by \((\gamma_{SL}-\gamma_{SV}+\gamma_{LV}\cos\theta)\,dx\), which must vanish at equilibrium. Athanase Dupré later combined it with the work of adhesion: \(W_{SL}=\gamma_{LV}(1+\cos\theta)\).

Young–Laplace equation

Across a curved interface of tension \(\gamma\) with principal radii of curvature \(R_1,R_2\), the pressure is higher on the concave side by

\[ \Delta p=\gamma\Big(\frac{1}{R_1}+\frac{1}{R_2}\Big). \]

Derivation for a sphere. Cut a spherical drop of radius \(R\) in half. The pressure excess pushes the halves apart with force \(\Delta p\,\pi R^2\); the tension holds them together along the circumference with \(2\pi R\gamma\). Equating, \(\Delta p=2\gamma/R\), the case \(R_1=R_2=R\).

Jurin’s law

In a vertical tube of radius \(r\), a liquid of density \(\rho\) and contact angle \(\theta\) rises to height \(h=\dfrac{2\gamma\cos\theta}{\rho g r}\).

The meniscus is approximately a spherical cap of radius \(r/\cos\theta\), so the pressure just below it is lower than atmospheric by \(2\gamma\cos\theta/r\). Hydrostatic balance gives \(\rho gh\) equal to this.

Exercise 8.1Water (\(\gamma=0.073\) N/m, \(\theta\approx0\)) in a glass tube of radius 0.2 mm. How high does it rise?

Show solution
\(h=2\times0.073/(1000\times9.81\times2\times10^{-4})\approx0.074\) m, about 7.4 cm.

Exercise 8.2Find the excess pressure inside a soap bubble of radius 2 cm made from a solution with \(\gamma=0.025\) N/m. Why does a smaller bubble connected to a larger one empty into it?

Show solution
A bubble has two surfaces, so \(\Delta p=4\gamma/R=4\times0.025/0.02=5\) Pa. Since \(\Delta p\propto1/R\), the smaller bubble has the higher pressure, so air flows from small to large, and the small one shrinks further.

Exercise 8.3Mercury on glass has \(\theta\approx140^\circ\). Use Young’s equation to say whether \(\gamma_{SV}\) or \(\gamma_{SL}\) is larger, and use Jurin’s law to explain why mercury is depressed in a capillary.

Show solution
\(\cos\theta<0\), so \(\gamma_{SV}-\gamma_{SL}=\gamma_{LV}\cos\theta<0\): the solid–liquid interface is more costly than the bare solid, and the liquid avoids wetting it. In Jurin’s law \(h\propto\cos\theta<0\), so the level falls below the outside surface.
Lesson 09

The eye: accommodation and three colours

For the general reader. Young’s first and last scientific interests were in the eye. He settled a long debate over how the eye focuses on near and far objects: the lens changes shape. He found that his own eye focused vertical and horizontal lines at different distances, the first description of astigmatism. He also proposed that colour vision needs only three kinds of receptor in the retina, an idea confirmed a century and a half later.

Goals
  • Compute the accommodation needed to see near objects.
  • Model astigmatism with a toric surface.
  • State the trichromatic hypothesis and its linear-algebra form.

Accommodation

In 1800 Young tested and excluded the alternatives. A change in the cornea was ruled out by viewing with the eye under water, which cancels the cornea’s power, and finding that accommodation persisted. A change in eye length was ruled out by pressing on the eye and finding no change. What remained was the lens.

Accommodation in diopters

Treat the eye as a thin lens of power \(P=1/f\) (in diopters, \(\mathrm m^{-1}\)) at distance \(L\) from the retina. To focus an object at distance \(s\), \(P=1/s+1/L\). The change of power between the far point \(s_F\) and near point \(s_N\) is the amplitude of accommodation \(A=1/s_N-1/s_F\).

Three colours

Trichromatic hypothesis (Young, 1801–1807)

The retina contains three kinds of receptor with different spectral sensitivities. Every colour sensation is determined by the three responses. In his 1801 lecture Young named the primaries red, yellow and blue; in the 1807 Lectures he changed them to red, green and violet.

In modern terms, if the receptors have sensitivities \(s_j(\lambda)\), \(j=1,2,3\), a light with spectrum \(P(\lambda)\) produces responses \(r_j=\int s_j(\lambda)P(\lambda)\,d\lambda\). Two lights that give the same triple \((r_1,r_2,r_3)\) look identical though their spectra differ: they are metamers. Colour sensations form a three-dimensional cone in which mixing of lights is vector addition. Hermann von Helmholtz revived and extended Young’s idea in the 1850s, and James Clerk Maxwell confirmed it by colour-matching experiments. Three types of cone were identified by microspectrophotometry in the 1960s.

Exercise 9.1A young eye has its far point at infinity and its near point at 10 cm. What is its amplitude of accommodation? At 45 the near point has moved to 40 cm; what reading lens restores a near point of 25 cm?

Show solution
\(A=1/0.10-0=10\) D. At 45 the amplitude is \(1/0.40=2.5\) D. To see at 25 cm needs 4 D, so a reading lens of \(+1.5\) D is required.

Exercise 9.2Show with the linear model that two lights of different spectra can match. Take three sensitivities on a coarse grid of four wavelengths, so \(r=S\,P\) with \(S\) a \(3\times4\) matrix. Why must a non-zero spectral difference with \(S\,\Delta P=0\) exist?

Show solution
\(S\) maps \(\mathbb R^4\) to \(\mathbb R^3\), so its kernel has dimension at least 1. Any \(\Delta P\) in the kernel changes the spectrum without changing the responses. If \(P\) has all components positive, \(P+\epsilon\,\Delta P\) is still a physical spectrum for small \(\epsilon\), and it is a metamer of \(P\). The real spectrum is infinite-dimensional, so the space of metamers is enormous.
Lesson 10

The pulse as a wave

For the general reader. When the heart beats, a pressure wave runs along the arteries faster than the blood itself moves. In his Croonian Lecture of 1808, Young treated the arteries as elastic tubes and the pulse as a wave in them, using the same reasoning as for sound in a rod. He also argued that the heart, not muscular action of the arteries, drives the circulation. The formula for the pulse speed is now a standard tool in cardiovascular medicine.

Goals
  • Derive the wave equation for pressure in an elastic tube.
  • Obtain the Moens–Korteweg speed and estimate it for the aorta.
  • Understand reflection of waves at a junction.
Pulse wave speed

An inviscid fluid of density \(\rho\) fills a long elastic tube whose cross-sectional area \(A\) depends on the pressure \(p\). Small disturbances travel at

\[ c^2=\frac{A}{\rho}\,\frac{dp}{dA}. \]

For a thin-walled tube of radius \(R\), wall thickness \(h\) and Young’s modulus \(E\), this gives \(c=\sqrt{\dfrac{Eh}{2\rho R}}\) (the Moens–Korteweg formula, 1878).

Derivation. With mean velocity \(u\), conservation of mass and momentum give, to linear order, \(A_t+A_0u_x=0\) and \(\rho u_t+p_x=0\). Write \(A_t=(dA/dp)\,p_t\). Eliminating \(u\): \(p_{tt}=\frac{A_0}{\rho\,dA/dp}\,p_{xx}\). For the thin wall, the hoop stress is \(pR/h\), the circumferential strain \(dR/R\), so \(dp=\frac{Eh}{R^2}dR\) and \(dA=2\pi R\,dR\). Then \(\frac{A}{dA/dp}=\frac{\pi R^2\,Eh}{2\pi R^3}=\frac{Eh}{2R}\). Young reached the equivalent result in 1808, in words and with his modulus height, seventy years before Moens and Korteweg.

Exercise 10.1Estimate the pulse wave speed in a young adult aorta with \(E=0.4\) MPa, \(h=2\) mm, \(R=12\) mm, \(\rho=1050\) kg/m\(^3\). How does stiffening of the artery with age change it?

Show solution
\(c=\sqrt{4\times10^5\times2\times10^{-3}/(2\times1050\times0.012)}=\sqrt{800/25.2}\approx5.6\) m/s. Since \(c\propto\sqrt E\), a stiffer artery carries a faster pulse. Measured pulse wave velocity is used clinically as an index of arterial stiffness.

Exercise 10.2A pressure wave in a tube of characteristic impedance \(Z_1=\rho c_1/A_1\) meets a tube of impedance \(Z_2\). Show that the pressure reflection coefficient is \(\dfrac{Z_2-Z_1}{Z_2+Z_1}\). What happens at a closed end?

Show solution
In a single tube, \(p=Z\,Q\) for a forward wave (\(Q=Au\) the flow) and \(p=-ZQ\) for a backward one, from \(\rho u_t=-p_x\) and \(p=f(x-ct)\). At the junction, pressure and flow are continuous: \(p_i+p_r=p_t\) and \((p_i-p_r)/Z_1=p_t/Z_2\). Solving, \(p_r/p_i=(Z_2-Z_1)/(Z_2+Z_1)\). A closed end has \(Z_2\to\infty\), so the wave reflects with the same sign and the pressure doubles. Young discussed such reflections at branchings of the arteries.
Part III · Life and legacy
Lesson 11

Physician, secretary, decipherer, 1807–1829

After 1807 Young concentrated on medicine. He became physician to St George’s Hospital in 1811 and published An Introduction to Medical Literature (1813) and A Practical and Historical Treatise on Consumptive Diseases (1815). His rule for children’s doses, the adult dose times the age divided by the age plus twelve, was long in use. He was never a popular doctor; patients found his manner too scientific. He served the Royal Society as foreign secretary for the rest of his life, sat on a committee on the dangers of London’s gas lighting in 1814, and in 1816 was secretary of a commission on the length of the seconds pendulum. In 1818 he became secretary of the Board of Longitude and superintendent of the Nautical Almanac. In his last years he also took up the mathematics of life insurance.

For the supplement to the Encyclopædia Britannica he wrote dozens of articles, on subjects from tides to bridges, and a long article on languages that compared the grammar and vocabulary of about four hundred tongues. In 1813 he used the term “Indo-European” for the family that links Sanskrit with most European languages.

The Rosetta Stone

The Rosetta Stone, carrying one decree in Greek, demotic and hieroglyphic script, reached London in 1802. Young began work on it in 1814, building on the demotic alphabet of Johan David Åkerblad. By the end of that year he had a word-by-word translation of the demotic text. He recognised that demotic mixed phonetic and ideographic signs, and he correctly assigned sound values to several hieroglyphic signs in the royal names, starting from the name of Ptolemy. His article “Egypt” in the 1818 Britannica supplement set out his results. Jean-François Champollion announced the full phonetic decipherment of hieroglyphs in 1822. Young answered in 1823 with An Account of Some Recent Discoveries in Hieroglyphical Literature, claiming that his work was the foundation. Relations between the two were strained, though after 1826 Champollion, then a curator at the Louvre, gave Young access to demotic manuscripts.

Exercise 11.1Young’s rule gives the child dose as \(D_c=D_a\,\dfrac{a}{a+12}\) for age \(a\) in years. Compute the fraction for ages 2, 6 and 12. A common alternative scales by body surface area. Discuss briefly why any single age-based rule must be approximate.

Show solution
Fractions: \(2/14\approx0.14\), \(6/18\approx0.33\), \(12/24=0.5\). Clearance of drugs depends on body size, organ maturity and metabolism, which vary between children of the same age. An age rule ignores weight entirely, so modern practice uses weight or surface area and drug-specific data.
Lesson 12

Death and legacy

Recognition of Young’s optics came from France first. After Fresnel’s prize memoir of 1818–19 and his work on polarization, French physicists acknowledged Young’s priority on interference, and Young corresponded with Fresnel and Arago. In 1827 the Académie des sciences elected Young one of its eight foreign associates. His health declined from 1828. He continued to work on an Egyptian dictionary until shortly before his death in London on 10 May 1829, at the age of 55. An autopsy found severe disease of the aorta. He was buried in the churchyard of St Giles at Farnborough in Kent. A memorial tablet in Westminster Abbey, with an inscription by his old pupil Hudson Gurney, credits him with first establishing the undulatory theory of light.

Legacy

  • Optics. The principle of interference, the first measured wavelengths, and the transverse-wave hypothesis. Combined with Fresnel’s mathematics they made the wave theory of light. The double-slit experiment became, in quantum mechanics, the standard illustration of wave–particle duality.
  • Mechanics and materials. Young’s modulus, the energy stored in elastic bodies, and in 1807 the use of the word “energy” for the quantity proportional to \(mv^2\).
  • Surfaces. Young’s equation and, with Laplace, the Young–Laplace equation: the basis of the science of wetting.
  • Physiology. Accommodation, astigmatism, trichromatic colour vision (the Young–Helmholtz theory), and arterial wave mechanics.
  • Languages. The term Indo-European, the comparative survey of languages, and the first real progress on demotic Egyptian.

John Herschel called him a truly original genius. Albert Einstein, in his 1931 foreword to Newton’s Opticks, named Young among those who carried optics forward. Andrew Robinson’s 2006 biography called him The Last Man Who Knew Everything.

Final projectYoung stated the interference principle in 1801, yet the wave theory was not accepted until after 1819. Write a two-page essay for a strong undergraduate on why. Consider Young’s style of exposition, Brougham’s reviews, the problem of polarization, and what Fresnel added that Young lacked.

Reference

Sources and further reading

Biography

  1. Thomas Young, MacTutor History of Mathematics, University of St Andrews.
  2. Thomas Young (scientist), Wikipedia.
  3. Thomas Young, Royal Society, Science in the Making archive.
  4. G. Peacock, Life of Thomas Young, M.D., F.R.S., John Murray, London, 1855.
  5. A. Wood and F. Oldham, Thomas Young, Natural Philosopher, 1773–1829, Cambridge University Press, 1954.
  6. A. Robinson, The Last Man Who Knew Everything, Pi Press, 2006.

Physics

  1. T. Young, The Bakerian Lecture: On the mechanism of the eye, Phil. Trans. R. Soc. 91 (1801), 23–88. Project Gutenberg text.
  2. T. Young, The Bakerian Lecture: On the theory of light and colours, Phil. Trans. R. Soc. 92 (1802), 12–48. Project Gutenberg text.
  3. T. Young, The Bakerian Lecture: Experiments and calculations relative to physical optics, Phil. Trans. R. Soc. 94 (1804), 1–16.
  4. T. Young, An essay on the cohesion of fluids, Phil. Trans. R. Soc. 95 (1805), 65–87.
  5. T. Young, A Course of Lectures on Natural Philosophy and the Mechanical Arts, 2 vols, London, 1807.
  6. T. Young, The Croonian Lecture: On the functions of the heart and arteries, Phil. Trans. R. Soc. 99 (1809), 1–31.
  7. Young’s interference experiment, Wikipedia.
  8. E. T. Whittaker, A History of the Theories of Aether and Electricity, vol. 1, 1910; revised 1951.
  9. J. Z. Buchwald, The Rise of the Wave Theory of Light, University of Chicago Press, 1989.