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Evangelista Torricelli

Evangelista Torricelli

A course in two strands: the short life of Galileo’s last disciple, from a poor family of Faenza to the post of mathematician to the Grand Duke of Tuscany, and the work that carried indivisibles, projectiles, fluids and the vacuum from Galileo toward Newton.

Born 15 October 1608, Faenza (or Rome) Died 25 October 1647, Florence Barometer letter to Ricci, 11 June 1644 Level advanced undergraduate
Two infinities. Left: the acute hyperbolic solid, infinitely long but of finite volume. Right: the mercury column, held up by the sea of air.
Lesson 00

How to use this course

Evangelista Torricelli is remembered for one experiment: a glass tube of mercury, inverted in a bowl, that showed the weight of the air and produced the first sustained vacuum in a laboratory. He was primarily a geometer. In his one published book he showed that an infinitely long solid can have a finite volume, measured the cycloid, and gave twenty proofs of an Archimedean theorem. He extended Galileo’s theory of projectiles and founded the quantitative study of jets of water. He did all this in about six productive years, and died at 39.

Prerequisites for Part II
  • First-year calculus: integrals of areas and volumes, parametric curves, polar coordinates.
  • Elementary mechanics: uniform acceleration, energy conservation, pressure in a fluid.
  • Euclidean geometry of triangles and circles.
  • Lesson 05 of the Archimedes course (exhaustion) is useful background for Lesson 04.

Each technical lesson opens with a paragraph for the general reader, then gives precise statements, derivations and exercises with folded solutions. Torricelli wrote in the geometric language of his day, in ratios and proportions. The course states his results in modern notation and marks where the modern form adds something he did not have.

Reference

Timeline

1608Born 15 October, eldest of three children of a textile worker named Gaspare. Most sources give Faenza as his birthplace; some recent accounts give Rome, with a family from Faenza.
c. 1624–26Studies mathematics and philosophy at a Jesuit college, most probably in Faenza, under the supervision of his uncle Jacopo, a Camaldolese monk.
1626Goes to Rome as pupil and then secretary of the Benedictine Benedetto Castelli, Galileo’s former student.
163211 September: writes to Galileo, describing himself as a convinced Copernican and admirer of the Dialogue.
1633Galileo’s trial. Torricelli turns away from cosmology.
c. 1632–41Secretary to Giovanni Ciampoli, a friend of Galileo, in towns of the Papal States. Works on geometry and on motion.
1641April: Castelli sends Torricelli’s treatise on motion to Galileo. 10 October: Torricelli arrives at Arcetri as Galileo’s assistant, alongside Vincenzo Viviani.
16428 January: Galileo dies. Torricelli is appointed mathematician to Grand Duke Ferdinando II de’ Medici. Inaugural lecture at the Accademia della Crusca.
1643October: letter to Gilles Personne de Roberval on the cycloid, which opens a priority dispute. Mercury-tube experiment devised in Florence (1643–44).
1644Opera geometrica. 11 and 28 June: letters to Michelangelo Ricci in Rome explaining the barometer. Marin Mersenne, visiting Italy, sees the experiment.
16467 April: letter to Ricci with a general theorem on centres of gravity.
1647Dies in Florence on 25 October after a few days’ illness, probably typhoid. Buried in San Lorenzo.
1648Puy de Dôme experiment, organized by Blaise Pascal, confirms that the mercury column falls with altitude.
1715Lezioni accademiche published in Florence.
1919–44Opere di Evangelista Torricelli, edited by Gino Loria and Giuseppe Vassura.
Part I · Formation
Lesson 01

Faenza and the Jesuits, 1608–1626

Evangelista Torricelli was born on 15 October 1608. His family came from Faenza in the Romagna, then part of the Papal States, and most biographies, including the Dictionary of Scientific Biography, place his birth there. Some recent accounts place it in Rome instead, and older and newer sources also disagree on his mother’s name. The undisputed facts are these: he was the eldest of three children, his father Gaspare was a textile worker of modest means, and the family identified with Faenza, which honours him as a native son with a statue raised in 1868.

The family was poor, and the boy’s education was entrusted to his father’s brother Jacopo, a monk of the Camaldolese order. Jacopo taught him humanities and saw him into a Jesuit college, where he studied mathematics and philosophy from about 1624 to 1626. Most historians place this school in Faenza. His progress was striking enough that the family decided he should continue in Rome, under the care of a Camaldolese connection of Jacopo’s.

Exercise 1.1Biographical sources for Torricelli disagree on birthplace and mother’s name, yet agree on the date. Suggest what kind of document would settle the question, and why a seventeenth-century family might be firmly associated with a town other than the place of birth.

Show solution
A baptismal register entry, normally made within days of birth, would settle both place and parents. Families of artisans often moved for work while remaining citizens of their home town; Faenza’s claim on Torricelli rests on this civic identity as much as on any record of birth.
Lesson 02

Rome with Castelli, 1626–1632

In Rome, Torricelli became the pupil of Benedetto Castelli, a Benedictine monk who had studied with Galileo Galilei at Padua and now taught mathematics at the Sapienza, the papal university. Castelli was a pioneer of the science of flowing water: his Della misura dell’acque correnti (1628) dealt with the flow in rivers and canals. There is no record that Torricelli enrolled at the university. He studied privately with Castelli and in return served as his secretary, deputizing for him in teaching when Castelli was away.

Through Castelli, Torricelli entered the circle of Galileo’s followers. Bonaventura Cavalieri, another of Castelli’s pupils, was then developing the method of indivisibles, and Torricelli became his ally and correspondent. Michelangelo Ricci, a younger Roman mathematician who later became a cardinal, became his closest friend.

The letter of 1632

On 11 September 1632, Torricelli answered a letter from Galileo to Castelli. It is his earliest surviving letter. He described himself as the first in Rome to have studied Galileo’s works minutely, and as a Copernican by conviction, having read the newly published Dialogue Concerning the Two Chief World Systems. Within a year Galileo had been condemned by the Inquisition, and Torricelli never again wrote openly on cosmology.

Exercise 2.1Castelli’s main result on rivers states that, in steady flow, the cross-sectional area times the mean speed is the same at every section. Use it to find how the speed changes when a river 40 m wide and 2 m deep enters a gorge 10 m wide and 4 m deep.

Show solution
Sections are \(80\) m² and \(40\) m². Since \(Av\) is constant, the speed doubles in the gorge. This continuity law is the background for the efflux problem of Lesson 08.
Lesson 03

The Ciampoli years and Arcetri, 1632–1642

The next decade is poorly documented. Torricelli appears to have served as secretary to Giovanni Ciampoli, a prelate and friend of Galileo who had fallen from papal favour and was sent to govern small towns of the Papal States. The places suggested include Montalto, Norcia, San Severino and Fabriano. In these years he wrote most of what became Opera geometrica, mastering Archimedes and the new indivisibles, and composed a treatise on motion that extended Galileo’s Two New Sciences (1638).

Galileo’s last assistant

In April 1641 Castelli, passing through Florence, showed Torricelli’s treatise on motion to Galileo, then old, blind and under house arrest at his villa in Arcetri. Galileo was impressed and invited the author to come and help him prepare further dialogues for the Two New Sciences. Torricelli arrived on 10 October 1641. He joined Vincenzo Viviani, who had lived with Galileo since 1639. For three months the two young men took Galileo’s dictation and discussed geometry with him. Galileo died on 8 January 1642.

Torricelli was preparing to return to Rome when Grand Duke Ferdinando II de’ Medici asked him to stay in Florence as court mathematician, with lodging in the ducal palace. He did not receive Galileo’s second title of philosopher. A Latin anagram of his name, published in 1715, read “En virescit Galileus alter”: here flourishes another Galileo.

Exercise 3.1Torricelli was with Galileo for about three months. List two ways in which this short contact plausibly shaped his later work, and one way in which his work departs from Galileo’s.

Show solution
Shaping: the problem of why suction pumps cannot lift water above about 18 braccia, raised in the Two New Sciences, led to the barometer; and Galileo’s theory of projectiles became the starting point of De motu gravium. Departure: Galileo was wary of indivisibles and explained the pump limit by the strength of a column of water; Torricelli embraced indivisibles and replaced the “force of the vacuum” by the weight of the air.
Part II · The mathematics and physics
Lesson 04

Indivisibles, straight and curved

For the general reader. To compare two shapes, slice both into infinitely thin strips. If corresponding strips are always equal, the shapes have equal area. Cavalieri made this rule the basis of a method; Torricelli used it with more freedom, slicing along curves as well as straight lines, and he often checked his results with Archimedes’ older, rigorous method.

Goals
  • State Cavalieri’s principle for areas and volumes.
  • Use curved indivisibles to compare a circle with a triangle.
  • See why the method can mislead, and how Torricelli guarded against it.
Cavalieri’s principle

If two plane figures lie between the same two parallel lines, and every line parallel to these cuts them in segments of equal length, the figures have equal area. If two solids lie between the same two parallel planes, and every parallel plane cuts them in sections of equal area, the solids have equal volume. More generally, if the sections are always in a fixed ratio, so are the areas or volumes.

In modern terms the principle is the statement that \(\int\ell_1(t)\,dt=\int\ell_2(t)\,dt\) when \(\ell_1=\ell_2\). It is a theorem of integration, but Cavalieri treated it as a principle about the “collection of all lines” of a figure.

Curved indivisibles

Torricelli allowed the indivisibles to be curves. A disc of radius \(r\) is the union of concentric circles of radius \(\rho\), \(0\le\rho\le r\). A right triangle with legs \(r\) and \(2\pi r\) is the union of segments parallel to the long leg, of length \(2\pi\rho\) at distance \(\rho\) from the apex. Each circle equals the corresponding segment in length, so the disc equals the triangle: Archimedes’ Proposition 1 of Measurement of a Circle in one line.

A warning

Torricelli knew that careless use of indivisibles gives contradictions, and he collected examples. Draw the diagonal of a rectangle that is not a square. Match each horizontal line in one triangle with the vertical line in the other triangle that meets it on the diagonal. The matched lines always have lengths in a fixed ratio different from 1, yet the two triangles are plainly equal. The paradox arises because the “spacing” of the indivisibles differs on the two sides. Torricelli concluded that indivisibles must be compared with equal thickness, an insight later made precise by the Jacobian factor in a change of variables.

Exercise 4.1Use Cavalieri’s principle to show that a hemisphere of radius \(r\) has the same volume as a cylinder of radius and height \(r\) minus a cone of the same base and height. Deduce \(V=\tfrac23\pi r^3\).

Show solution
At height \(z\) the hemisphere’s section is a disc of area \(\pi(r^2-z^2)\). The cylinder minus the inverted cone (vertex at the bottom) has an annular section of area \(\pi r^2-\pi z^2\). The sections agree, so the volumes agree: \(\pi r^3-\tfrac13\pi r^3=\tfrac23\pi r^3\).

Exercise 4.2In a rectangle of width \(a\) and height \(b\) with \(a\ne b\), pair each horizontal segment from the left side to the diagonal with the vertical segment from the bottom to the diagonal through the same point. Show that their lengths are always in ratio \(a:b\), and explain why this does not prove the two triangles have areas in ratio \(a:b\).

Show solution
The diagonal is \(y=\tfrac bax\). At the point \((x,\tfrac bax)\) the horizontal segment has length \(x\) and the vertical one length \(\tfrac bax\): ratio \(a:b\). But as the point moves along the diagonal, the horizontal segments sweep with spacing \(dy=\tfrac ba\,dx\) and the vertical ones with spacing \(dx\). Areas are \(\int x\,dy\) and \(\int\tfrac bax\,dx\), which are equal. Cavalieri’s principle needs the same spacing on both sides.
Lesson 05

The acute hyperbolic solid

For the general reader. Spin the curve \(y=1/x\) about the \(x\)-axis. The result is a trumpet that goes on forever, yet Torricelli proved that it holds only a finite amount of space. Contemporaries found this astonishing. It was the first clear case of an unbounded figure with a finite measure, and it fed a long philosophical argument about the infinite.

Goals
  • State Torricelli’s theorem on the acute hyperbolic solid.
  • Prove it with cylindrical indivisibles, as he did.
  • Contrast finite volume with infinite surface area.
Theorem (Torricelli, published 1644)

Let the branch of the rectangular hyperbola \(xy=1\), \(x>0\), be rotated about its asymptote \(y=0\). Cut the resulting infinite solid by the plane \(x=a\), and add to the part with \(x\ge a\) the cylinder \(0\le x\le a\) of radius \(1/a\). The combined solid has finite volume, equal to that of the cylinder of radius \(\sqrt2\) and height \(1/a\), namely \(2\pi/a\).

Proof by cylindrical shells

Torricelli sliced the solid into coaxial cylindrical surfaces. The surface at radius \(y\), \(0<y\le 1/a\), runs from \(x=0\) to the hyperbola at \(x=1/y\), so its area is

\[ 2\pi y\cdot\frac1y=2\pi, \]

the same for every \(y\). Each such surface equals a disc of radius \(\sqrt2\). Stacking the discs at heights \(y\in(0,1/a]\) gives a cylinder of radius \(\sqrt2\) and height \(1/a\). By the principle of indivisibles, the two solids are equal. Torricelli also supplied a proof in the style of Archimedes, by inscribed and circumscribed figures, to satisfy readers who distrusted indivisibles.

In calculus, the tail alone has volume \(\int_a^\infty\pi x^{-2}\,dx=\pi/a\), and the added cylinder \(\pi(1/a)^2a=\pi/a\), total \(2\pi/a\).

The surface

The lateral surface area of the tail is

\[ \int_a^\infty 2\pi\frac1x\sqrt{1+x^{-4}}\,dx\ \ge\ \int_a^\infty\frac{2\pi}{x}\,dx=\infty. \]

The paradox of a trumpet that can be filled with paint but not painted belongs to later commentators; Torricelli’s own emphasis was on the finite volume. The solid is now often called Gabriel’s horn.

Exercise 5.1For which exponents \(p>0\) does rotating \(y=x^{-p}\), \(x\ge1\), about the \(x\)-axis give a finite volume? A finite surface area?

Show solution
Volume \(\pi\int_1^\infty x^{-2p}dx\) is finite iff \(2p>1\), i.e. \(p>\tfrac12\). The surface \(2\pi\int_1^\infty x^{-p}\sqrt{1+p^2x^{-2p-2}}\,dx\) behaves like \(2\pi\int x^{-p}dx\), finite iff \(p>1\). For \(\tfrac12<p\le1\) the volume is finite and the surface infinite; \(p=1\) is Torricelli’s case.

Exercise 5.2Use the shell method, as Torricelli did, to find the volume of the solid obtained by rotating the region \(0\le y\le 1-x^2\), \(0\le x\le 1\), about the \(y\)-axis.

Show solution
The shell at radius \(x\) has height \(1-x^2\) and area \(2\pi x(1-x^2)\). Volume \(=\int_0^1 2\pi x(1-x^2)\,dx=2\pi(\tfrac12-\tfrac14)=\tfrac\pi2\). This is a paraboloid segment, half its cylinder, as Archimedes knew.
Lesson 06

The cycloid

For the general reader. A point on the rim of a rolling wheel traces an arch called the cycloid. Galileo had tried to find its area by cutting shapes out of sheet metal and weighing them. Torricelli computed it exactly: three times the area of the wheel. He also found its centre of gravity and its tangents. The French mathematician Roberval had found the area first, and the resulting quarrel outlived Torricelli.

Goals
  • Prove that the area under one arch is three times the generating circle.
  • Find the tangent by composing motions.
  • Compute the centre of gravity of the arch.

The cycloid generated by a circle of radius \(r\) rolling on the \(x\)-axis is

\[ x=r(t-\sin t),\qquad y=r(1-\cos t),\qquad 0\le t\le2\pi. \]
Theorem (Roberval c. 1634; Torricelli, published 1644)

The area between one arch of the cycloid and its base is three times the area of the generating circle, \(3\pi r^2\).

Proof with indivisibles

Consider half an arch, from \(t=0\) to \(t=\pi\), inside the rectangle \([0,\pi r]\times[0,2r]\) of area \(2\pi r^2\). Introduce the companion curve \(x=rt\), \(y=r(1-\cos t)\). At each height \(y\), the horizontal distance between the cycloid and the companion is \(r\sin t\), which is the half-chord of the generating circle at that height. By Cavalieri’s principle the region between the two curves equals a semicircle, area \(\tfrac12\pi r^2\). The companion curve, a sine curve, cuts the rectangle into two congruent halves by central symmetry, each of area \(\pi r^2\). So the region above the half-arch has area \(\pi r^2-\tfrac12\pi r^2=\tfrac12\pi r^2\), and the region under it \(2\pi r^2-\tfrac12\pi r^2=\tfrac32\pi r^2\). Doubling gives \(3\pi r^2\).

Tangents by composition of motions

Torricelli, like Roberval, found tangents by treating the curve as the path of a point with two simultaneous motions. The tracing point moves with the centre of the wheel (velocity \(r\omega\) horizontally) and turns about it (velocity \(r\omega\) tangent to the wheel). The tangent to the cycloid is the diagonal of the parallelogram of these two velocities. Since both have the same magnitude, the tangent bisects the angle between them, and one finds that it passes through the top of the rolling circle.

Exercise 6.1Verify the area by integration: compute \(\int_0^{2\pi}y\,\frac{dx}{dt}\,dt\).

Show solution
\(\int_0^{2\pi}r(1-\cos t)\cdot r(1-\cos t)\,dt=r^2\int_0^{2\pi}(1-2\cos t+\cos^2t)\,dt=r^2(2\pi+\pi)=3\pi r^2\).

Exercise 6.2Show that the centre of gravity of the region under one arch lies at height \(\tfrac56r\) above the base.

Show solution
The moment about the base is \(\int\tfrac12y^2\,dx=\tfrac{r^3}2\int_0^{2\pi}(1-\cos t)^3dt\). Expanding, \((1-\cos t)^3=1-3\cos t+3\cos^2t-\cos^3t\), with integral \(2\pi+3\pi=5\pi\). So the moment is \(\tfrac52\pi r^3\), and \(\bar y=\tfrac{5\pi r^3/2}{3\pi r^2}=\tfrac56r\).

Exercise 6.3Show directly from the parametrization that the tangent at the point with parameter \(t\) passes through the top of the rolling circle, \((rt,2r)\).

Show solution
The velocity is \((r(1-\cos t),\,r\sin t)\). The vector from the point to \((rt,2r)\) is \((r\sin t,\,r(1+\cos t))\). Their cross product is \(r^2[(1-\cos t)(1+\cos t)-\sin^2t]=0\), so they are parallel.
Lesson 07

Projectiles and Torricelli’s principle

For the general reader. Galileo showed that a cannonball follows a parabola. Torricelli asked what happens when the gun is fired at every possible angle with the same charge. The trajectories fill a region bounded by another parabola, which he called the parabola of safety: outside it, no shot can reach you. He also stated a principle about centres of gravity that later became a pillar of statics.

Goals
  • Derive the range formula and the envelope of trajectories.
  • State Torricelli’s principle and use it to solve an equilibrium problem.

De motu gravium (1644)

The second part of Opera geometrica, De motu gravium naturaliter descendentium et proiectorum, rebuilt Galileo’s theory of falling bodies and projectiles. Torricelli extended Galileo’s results to launches at any angle, noted that the motion of a projectile is reversible, and gave tables for gunners. For speed \(v\) at angle \(\theta\), with \(g\) the acceleration of gravity,

\[ y=x\tan\theta-\frac{g\,x^2}{2v^2\cos^2\theta},\qquad R=\frac{v^2\sin2\theta}{g}. \]
Parabola of safety

For fixed launch speed \(v\) and all angles \(\theta\), the trajectories are tangent to the parabola

\[ y=\frac{v^2}{2g}-\frac{g\,x^2}{2v^2}, \]

and a point can be reached if and only if it lies on or below this curve.

Torricelli’s principle

Principle (Torricelli, 1644)

Two heavy bodies joined together cannot move of themselves unless their common centre of gravity descends. Consequently, a system of connected weights is in equilibrium when no small motion allowed by the connection lowers the common centre of gravity.

Galileo had used a related idea. Torricelli made it an explicit axiom and derived from it the law of the inclined plane. Christiaan Huygens adopted it in his work on the pendulum, and it is a special case of the principle of virtual work: at equilibrium, the potential energy is stationary.

Exercise 7.1Derive the parabola of safety. (Hint: write the trajectory in terms of \(u=\tan\theta\) and ask for which \((x,y)\) the quadratic in \(u\) has a real root.)

Show solution
With \(1/\cos^2\theta=1+u^2\): \(\frac{gx^2}{2v^2}u^2-xu+\left(y+\frac{gx^2}{2v^2}\right)=0\). A real root exists iff \(x^2\ge4\cdot\frac{gx^2}{2v^2}\left(y+\frac{gx^2}{2v^2}\right)\), i.e. \(y\le\frac{v^2}{2g}-\frac{gx^2}{2v^2}\). Equality gives the double root: the curve touched by exactly one trajectory.

Exercise 7.2Two weights \(P\) and \(Q\) rest on two inclined planes back to back, of inclinations \(\alpha\) and \(\beta\), joined by a string over the summit. Use Torricelli’s principle to find the condition for equilibrium.

Show solution
If \(P\) moves a distance \(s\) down its plane, it falls \(s\sin\alpha\) and \(Q\) rises \(s\sin\beta\). The centre of gravity does not descend, for either direction of motion, iff \(P\sin\alpha=Q\sin\beta\). This is Stevin’s law of the inclined plane.
Lesson 08

The law of efflux

For the general reader. Punch a hole near the bottom of a full bucket. How fast does the water come out? Torricelli’s answer: as fast as a drop would be moving if it had fallen freely from the water’s surface down to the hole. Ernst Mach later called him the founder of hydrodynamics for this result.

Goals
  • State Torricelli’s theorem and see its experimental basis.
  • Derive it from energy conservation (Bernoulli).
  • Solve the draining-tank problem.
Torricelli’s theorem (De motu gravium, 1644)

Water issuing from a small opening at depth \(h\) below the free surface leaves with the speed it would acquire by falling freely through the height \(h\):

\[ v=\sqrt{2gh}. \]

Torricelli argued from observation: a jet directed upward rises nearly to the level of the water in the vessel, falling short only because of friction and air. By the reversibility of motion (Lesson 07), the jet must leave with the speed of fall from that height. Consequences: the speed varies as the square root of the depth, and the discharge through a hole of area \(a\) is \(a\sqrt{2gh}\) (reduced in practice by the contraction of the jet).

A century later, Daniel Bernoulli’s equation \(p+\tfrac12\rho v^2+\rho gz=\text{const}\) along a streamline gives the theorem at once: at the free surface and at the jet, the pressure is atmospheric and the speed at the surface is negligible, so \(\tfrac12\rho v^2=\rho gh\).

Draining a tank

For a vessel of horizontal cross-section \(A(h)\) at height \(h\) above a hole of area \(a\), continuity gives

\[ A(h)\frac{dh}{dt}=-a\sqrt{2gh}. \]

Exercise 8.1A cylindrical tank of cross-section \(A\) is filled to height \(H\) and drains through a hole of area \(a\) in the bottom. Find the time to empty it, and show that the first half of the water takes less time than the second half.

Show solution
\(\frac{dh}{\sqrt h}=-\frac aA\sqrt{2g}\,dt\) gives \(2\sqrt H=\frac aA\sqrt{2g}\,T\), so \(T=\frac Aa\sqrt{\frac{2H}g}\). Draining from \(H\) to \(H/2\) takes time proportional to \(\sqrt H-\sqrt{H/2}\approx0.29\sqrt H\), and from \(H/2\) to 0 time proportional to \(\sqrt{H/2}\approx0.71\sqrt H\).

Exercise 8.2Design a water clock: find the shape of a vessel of revolution, \(r=r(h)\), whose level falls at a constant rate.

Show solution
Need \(\pi r^2\,\frac{dh}{dt}=-a\sqrt{2gh}\) with \(dh/dt\) constant, so \(r^2\propto\sqrt h\), that is \(r\propto h^{1/4}\), or \(h\propto r^4\). The vessel is the surface obtained by rotating a quartic curve.

Exercise 8.3A tall vessel has holes in its side at heights \(z\) above the ground, with water surface at height \(H\). Show that the horizontal jet from the hole at \(z\) lands at distance \(2\sqrt{z(H-z)}\), and find which hole sends water farthest.

Show solution
Exit speed \(\sqrt{2g(H-z)}\), fall time \(\sqrt{2z/g}\), range \(\sqrt{2g(H-z)}\sqrt{2z/g}=2\sqrt{z(H-z)}\). It is maximal at \(z=H/2\), with range \(H\). Holes at \(z\) and \(H-z\) reach the same point.
Lesson 09

The barometer and the sea of air

For the general reader. Pump makers knew that a suction pump cannot raise water more than about ten metres. Galileo blamed a limited “force of the vacuum”. Torricelli realized that the air itself has weight and presses on the water outside the pipe. Mercury, about fourteen times heavier than water, should then stand about fourteen times lower. He tested this with a tube of mercury and so invented the barometer.

Goals
  • Describe the experiment and Torricelli’s two arguments for air pressure.
  • Compute heights of liquid columns supported by the atmosphere.
  • Follow the confirmation by Pascal and the Puy de Dôme.

The experiment

In 1643 or early 1644, in Florence, a glass tube about two braccia long, closed at one end, was filled with mercury, stoppered, inverted, and opened under the surface of mercury in a basin. The mercury fell until the column stood about one and a quarter braccia (roughly 76 cm) above the basin, leaving an apparently empty space at the top. Viviani is often named as the one who first carried out the experiment, at Torricelli’s suggestion.

Torricelli explained the result in a letter to Michelangelo Ricci of 11 June 1644, and answered Ricci’s objections in a second letter of 28 June. The first letter contains his most famous sentence: we live submerged at the bottom of an ocean of air. Two arguments stand out.

  • Shape does not matter. Tubes ending in a large bulb at the top, with much more “vacuum” above the mercury, held the column at the same height. A force of the vacuum should be stronger when there is more vacuum.
  • Weight explains everything. The column of mercury balances the weight of a column of air of the same base reaching to the top of the atmosphere. A column of water should therefore stand about 18 braccia, the pump makers’ limit.

He added that his aim had been to build an instrument showing changes in the air, sometimes heavier and sometimes lighter. He also tried, without success, to observe whether sound passed and insects survived in the vacuum.

Hydrostatic balance

A liquid of density \(\rho\) supported in a closed tube by atmospheric pressure \(p_0\), with (nearly) zero pressure above it, stands at height

\[ h=\frac{p_0}{\rho g}. \]

Confirmation

Marin Mersenne saw the experiment in Italy in 1644 and spread news of it in France. Blaise Pascal repeated it with water and wine in long tubes at Rouen and reasoned that if the air’s weight was the cause, the column must be shorter on a mountain. On 19 September 1648 his brother-in-law Florin Périer carried a barometer up the Puy de Dôme and found the mercury several centimetres lower at the summit than at Clermont. In 1654 Otto von Guericke’s Magdeburg hemispheres made the force of the atmosphere spectacular. The unit of pressure torr, \(\tfrac1{760}\) of a standard atmosphere, honours Torricelli.

Exercise 9.1With \(p_0=101\,325\) Pa, \(g=9.81\) m/s², and densities 13 595 kg/m³ (mercury) and 1000 kg/m³ (water), compute the heights of the two columns. Compare with the pump makers’ 18 braccia (one Florentine braccio is about 0.58 m).

Show solution
Mercury: \(101325/(13595\cdot9.81)\approx0.760\) m. Water: \(101325/(1000\cdot9.81)\approx10.3\) m. Eighteen braccia are about 10.5 m, close to the theoretical limit.

Exercise 9.2Model the atmosphere as isothermal, with pressure falling as \(p=p_0e^{-z/H}\), scale height \(H\approx8\) km. Estimate the drop of the mercury column over the roughly 1000 m climb of the Puy de Dôme experiment.

Show solution
\(\Delta h\approx760\,(1-e^{-1/8})\approx760\cdot0.118\approx89\) mm, about 9 cm. Périer reported a difference of a little over 3 French inches (about 8.5 cm), in good agreement.

Exercise 9.3Ricci objected that if the air pressed on the basin, a lid on the basin should stop the effect. How could Torricelli answer, using the fact that air is compressible?

Show solution
A lid placed over air at atmospheric pressure traps air that is still compressed by the weight above it when the lid was closed; its pressure, like that of a compressed spring, stays the same and still supports the column. Only pumping air out (as Boyle and Guericke later did) lowers the column.
Lesson 10

Minimum distances and spirals

For the general reader. Where should three villages build a shared well so that the total length of the paths to it is as short as possible? Pierre de Fermat posed the problem; Torricelli solved it. The answer is the point from which each side of the triangle is seen at 120°. Torricelli also measured the length of the logarithmic spiral, one of the first curves to be rectified exactly.

Goals
  • State and prove the characterization of the Fermat–Torricelli point.
  • Construct it with equilateral triangles.
  • Rectify the logarithmic spiral.
Fermat–Torricelli point

Let \(ABC\) be a triangle with all angles less than \(120^\circ\). The point \(F\) minimizing \(FA+FB+FC\) is the unique interior point with \(\angle AFB=\angle BFC=\angle CFA=120^\circ\). If one angle is \(120^\circ\) or more, the minimum is at that vertex.

Proof by rotation

Rotate the plane by \(60^\circ\) about \(B\), sending \(A\) to \(A'\) and an arbitrary point \(P\) to \(P'\), with \(A'\) outside the triangle. Triangle \(BPP'\) is equilateral, so \(PB=PP'\), and \(PA=P'A'\). Hence \(PA+PB+PC=A'P'+P'P+PC\ge A'C\), a length that does not depend on \(P\). Equality holds when \(A',P',P,C\) are collinear, which forces \(\angle BPC=120^\circ\) and \(\angle APB=120^\circ\). The construction shows \(F\) lies on the line \(CA'\) joining \(C\) to the apex of the equilateral triangle erected outward on \(AB\). Torricelli’s construction uses the circumcircles of these equilateral triangles, which pass through \(F\).

The logarithmic spiral

In work left unpublished at his death, Torricelli showed how to rectify the spiral \(r=ae^{b\theta}\) (which he described as cutting all radii at a constant angle), and noted that the arc from any point inward to the pole, though it winds round infinitely often, has finite length.

Exercise 10.1For an equilateral triangle of side 1, find the minimal sum of distances, and compare it with the sum at a vertex.

Show solution
\(F\) is the centre; each distance is the circumradius \(1/\sqrt3\), so the sum is \(\sqrt3\approx1.732\). At a vertex the sum is \(0+1+1=2\).

Exercise 10.2Show that the arc length of \(r=ae^{b\theta}\) (\(b>0\)) from \(\theta=-\infty\) to \(\theta\) is \(r\sqrt{1+b^2}/b\), and that this equals the length of the tangent segment from the point to where it meets the line through the pole perpendicular to the radius.

Show solution
\(ds=\sqrt{r^2+r'^2}\,d\theta=ae^{b\theta}\sqrt{1+b^2}\,d\theta\); integrating from \(-\infty\) gives \(\frac{\sqrt{1+b^2}}{b}ae^{b\theta}\). The tangent makes a constant angle \(\psi\) with the radius, \(\tan\psi=r/r'=1/b\). The tangent segment to the perpendicular line through the pole has length \(r/\cos\psi=r\sqrt{1+b^2}/b\). The two agree.
Part III · Life and legacy
Lesson 11

Mathematician to the Grand Duke, 1642–1647

Torricelli’s Florentine years were short and productive. He lived in the ducal palace with a salary from Ferdinando II, who, with his brother Leopoldo de’ Medici, was a keen patron of experiment. In 1642 he gave an inaugural lecture to the Accademia della Crusca, the Florentine academy of language, and his later lectures on the force of impact, on wind, and on lightness and heaviness were published posthumously as Lezioni accademiche (1715). In them he explained winds by differences in the temperature and density of air between regions.

Opera geometrica

In 1644 he published his only book, Opera geometrica. It had three parts: De sphaera et solidis sphaeralibus, on solids generated by rotating regular polygons, in the manner of Archimedes; De motu gravium, on falling bodies, projectiles and efflux; and De dimensione parabolae, which gives twenty proofs of Archimedes’ quadrature of the parabola, some classical and some by indivisibles, as a showcase of the two methods side by side. The volume also contained the acute hyperbolic solid and the cycloid. It made his reputation across Europe.

Lenses

Torricelli was also a skilled lens grinder. He kept his technique secret, made telescope objectives judged superior to those of the professional makers, and built simple microscopes. The lenses brought him income and gifts from the Grand Duke. He is often credited with improving Galileo’s air thermoscope into a sealed liquid thermometer, which the Medici circle developed further.

DiscussionDe dimensione parabolae proves the same theorem twenty ways. What did Torricelli gain by presenting classical and indivisible proofs side by side, at a time when the second were controversial?

Lesson 12

Disputes, death and legacy

Torricelli’s publication of the cycloid area in 1644 provoked Gilles Personne de Roberval, who had found it around 1634 without publishing, and who held his results back to defend his chair at the Collège Royal. Roberval accused Torricelli of taking the proof from French papers seen in Galileo’s circle. The evidence suggests Torricelli found the results independently. The quarrel was unresolved at his death and was revived in 1658 by Pascal, whose history of the cycloid sided with Roberval.

In October 1647 Torricelli fell suddenly ill, probably with typhoid fever, while writing a defence of his priority against the French. He died in Florence on 25 October 1647, aged 39, and was buried in the church of San Lorenzo; the exact place of his tomb is not known. He left his manuscripts in the care of his friend Lodovico Serenai. Ricci declined to edit them, and Viviani, who took up the task, did not finish it. The papers were published in full only in the Opere of 1919–1944.

Legacy

  • Physics: the barometer and the first sustained laboratory vacuum; the weight of the air; the law of efflux and the founding of hydrodynamics; Torricelli’s principle, which Huygens used and which leads to virtual work.
  • Mathematics: the first unbounded solid of finite volume; the cycloid; kinematic tangents; the Fermat–Torricelli point; a free and productive use of indivisibles, which, with the work of Cavalieri, Fermat, Roberval and Wallis, prepared the calculus of Newton and Leibniz.
  • Scientific style: Torricelli joined the geometric rigour of Archimedes to Galileo’s use of experiment, and his letter to Ricci is a model of an argument from experiment.
  • Honours: the unit torr, the asteroid 7437 Torricelli, a lunar crater, the Torricelli Mountains in New Guinea, and a statue in Faenza (1868).

Final projectChoose one result from Part II. Write two pages for a strong undergraduate that present Torricelli’s argument in its original style (indivisibles, proportions or experiment), give the modern derivation, and explain what the modern version adds or removes.

Reference

Sources and further reading

Biography

  1. J. J. O’Connor and E. F. Robertson, Evangelista Torricelli, MacTutor History of Mathematics.
  2. M. Gliozzi, Torricelli, Evangelista, Dictionary of Scientific Biography.
  3. Evangelista Torricelli, Wikipedia.
  4. G. Loria and G. Vassura (eds.), Opere di Evangelista Torricelli, 4 vols., Faenza, 1919–1944.
  5. W. E. Knowles Middleton, The History of the Barometer, Johns Hopkins Press, 1964.

Mathematics and physics

  1. E. Torricelli, Opera geometrica, Florence, 1644.
  2. E. Torricelli, Lezioni accademiche, Florence, 1715.
  3. P. Mancosu and E. Vailati, Torricelli’s infinitely long solid and its philosophical reception in the seventeenth century, Isis 82 (1991).
  4. P. Mancosu, Philosophy of Mathematics and Mathematical Practice in the Seventeenth Century, Oxford University Press, 1996.
  5. K. Andersen, Cavalieri’s method of indivisibles, Archive for History of Exact Sciences 31 (1985).
  6. E. Torricelli, letters to M. Ricci, 11 and 28 June 1644, in Opere, vol. 3.