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James Watt

James Watt FRS FRSE

A course in two strands: the life of the Glasgow instrument maker who turned the atmospheric engine into the steam engine of the Industrial Revolution, and the physics and engineering inside it, from latent heat and the separate condenser to expansive working, linkages, feedback and the indicator diagram.

Born 19 January 1736, Greenock Died 25 August 1819, Handsworth Separate condenser patented 1769 Level advanced undergraduate
Watt’s straight-line linkage. Two arms swing on fixed pivots; the midpoint of the coupler joining them traces a figure-of-eight whose middle stretch is straight to within the width of a line. Computed exactly.
Lesson 00

How to use this course

James Watt did not invent the steam engine. Thomas Newcomen’s atmospheric engine had pumped water from mines since 1712. What Watt did, starting in 1765, was to find out by measurement why that engine wasted most of its fuel, and to redesign it from the physics up. His separate condenser cut fuel consumption by roughly three quarters. In the next twenty years he made the engine turn wheels, push on both strokes, use steam expansively, guide its piston with a linkage and regulate its own speed. With his partner Matthew Boulton he sold it across Britain, and his name became the unit of power.

Prerequisites for Part II
  • First-year mechanics: work, power, torque, circular motion.
  • Heat capacity, latent heat and the ideal gas law.
  • Basic calculus, including \(\int dV/V=\ln V\) and Taylor series.
  • For Lesson 08, linear differential equations with constant coefficients.

Each technical lesson opens with a paragraph for the general reader, then gives precise statements, derivations and exercises with folded solutions. Part II follows Watt’s inventions in roughly the order he made them. The last lesson connects his engine to the theory of Sadi Carnot, who set out in 1824 to explain the machine Watt had built. For the physics of latent heat see also the course on Joseph Black.

Reference

Timeline

1736Born 19 January in Greenock, on the Firth of Clyde, son of James Watt, shipwright, merchant and town official, and Agnes Muirhead.
1755–56A year in London learning the trade of mathematical instrument maker.
1757Workshop in the University of Glasgow as mathematical instrument maker to the university. Friendship with Joseph Black and John Robison.
1763–64Repairs the university’s model Newcomen engine and investigates its waste of steam.
1764Marries his cousin Margaret Miller.
1765May: conceives the separate condenser while walking on Glasgow Green. A working model follows.
1766–74Works as a land and canal surveyor in Scotland. Supported in engine development by John Roebuck.
17695 January: patent for a method of lessening the consumption of steam and fuel in fire engines.
1773Death of Margaret Watt. Roebuck’s bankruptcy; his share in the patent passes to Matthew Boulton.
1774Moves to Birmingham.
1775Act of Parliament extends the patent to 1800. Partnership with Boulton.
1776First Boulton & Watt engines at work: Bloomfield Colliery, Tipton, and John Wilkinson’s ironworks at Broseley. Marries Ann MacGregor about this time.
1777First engines ordered for Cornwall. William Murdoch joins the firm.
1780Patent for copying letters.
1781Sun-and-planet gearing for rotary motion.
1782Patent for expansive working and the double-acting engine. Horse-power trials.
1783Proposes that water is a compound, in letters to Joseph Priestley.
1784Patents the parallel motion. Fellow of the Royal Society of Edinburgh.
1785Fellow of the Royal Society of London.
1786In Paris sees Claude Louis Berthollet’s chlorine bleaching; introduces it in Britain.
1788Centrifugal governor fitted to rotative engines.
1795–96Soho Foundry built. Watt and John Southern devise the indicator.
1799Patent upheld against Hornblower and Maberly.
1800Patent expires; retires, leaving the firm to his son James and Boulton’s son.
1806Honorary LLD, University of Glasgow.
1814Foreign associate of the French Academy of Sciences.
1819Dies 25 August at Heathfield Hall, Handsworth, aged 83. Buried at St Mary’s Church, Handsworth.
Part I · Formation
Lesson 01

Greenock and London, 1736–1756

James Watt was born in Greenock, a port on the Firth of Clyde, on 19 January 1736. His father, also James Watt, was a shipwright, shipowner and contractor, and served as a magistrate of the town. His mother, Agnes Muirhead, came from a well-connected family. Several of the couple’s children died young, and James himself was often ill as a child, so much of his early teaching was done at home. He later attended Greenock grammar school, where he showed an aptitude for mathematics.

The boy spent much of his time in his father’s workshop, where ships’ instruments, cranes and fittings were made and repaired. He learned to work wood and metal and to make models. When his father’s business declined, an instrument maker’s trade seemed a sound choice. In 1754 he went to Glasgow, and in 1755, after his mother’s death, to London.

The London instrument makers were organized in guilds and expected a seven-year apprenticeship. Watt found a master willing to teach him for a fee and spent a year learning to make quadrants, compasses, scales and other mathematical instruments, working long hours and avoiding the press gangs that took young men for the navy. In 1756, his health strained, he returned to Scotland with a set of tools and the skills of a trained maker.

Lesson 02

Instrument maker to the university, 1757–1765

Watt wanted to set up in Glasgow, but the Glasgow guild of hammermen refused to admit him because he had not served a full apprenticeship. The University of Glasgow, outside the guild’s jurisdiction, solved the problem. A consignment of astronomical instruments had arrived for the university and needed cleaning and repair, and in 1757 Watt was given a workshop within its walls and the title of mathematical instrument maker to the university. From 1759 he also ran a shop in the town in partnership with John Craig, making instruments and even musical instruments.

The workshop placed him among the professors. Joseph Black, then lecturer in chemistry, was working out his doctrine of latent heat and became Watt’s friend and adviser. John Robison, a student who later held the chair of natural philosophy at Edinburgh, introduced him to the idea of a steam carriage. Watt read widely in mechanics and chemistry and taught himself enough German and Italian to follow the technical literature.

In 1763–64 the university asked him to repair its working model of a Newcomen engine, used in the natural philosophy class. The model ran for only a few strokes before it exhausted its boiler, although the boiler was proportioned like those of full-sized engines. Watt treated this as a scientific problem. He measured how much steam the engine used, how much water a given weight of steam could heat, and how the pressure of steam rose with temperature. In July 1764 he married his cousin Margaret Miller. In May 1765, walking across Glasgow Green on a Sunday afternoon, he saw the solution (Lesson 05).

DiscussionWatt later said that his discovery of the separate condenser owed nothing directly to Black’s theory of latent heat, while crediting Black with teaching him to reason and experiment. Using Lessons 04 and 05, decide what Watt needed to know about heat in order to reach his idea.

Lesson 03

Roebuck, surveying and Boulton, 1765–1775

An idea is not an engine. To build a full-sized machine Watt needed money, skilled workmen and cylinders bored more accurately than any foundry could manage. Black introduced him to John Roebuck, a physician and industrialist who had founded the Carron ironworks. Roebuck paid Watt’s debts and the costs of a patent in return for a two-thirds share. Watt built a trial engine at Roebuck’s house at Kinneil, near Bo’ness, but its cylinder leaked badly and the work went slowly. The patent, for a method of lessening the consumption of steam and fuel in fire engines, was granted on 5 January 1769.

Meanwhile Watt had to earn a living. From 1766 to 1774 he worked as a land surveyor and civil engineer, surveying canal routes, harbours and river improvements in Scotland. Among other projects he surveyed a route between Fort William and Inverness that anticipated the Caledonian Canal, and he worked on the Monkland Canal near Glasgow. He disliked the work, the haggling with contractors and the travel, and suffered from headaches and low spirits for much of his life.

In 1773 two blows fell. Margaret died in childbirth while Watt was away surveying, leaving two young children. Roebuck went bankrupt, and his share in the patent passed to one of his creditors, Matthew Boulton, owner of the Soho Manufactory near Birmingham. Boulton had the capital, the workforce and the business instinct that Watt lacked. In 1774 Watt moved to Birmingham, and in 1775 Boulton secured an Act of Parliament extending the patent to 1800. The partnership of Boulton & Watt began. John Wilkinson’s new method of boring cannon gave them cylinders true to a fraction of an inch, and in March 1776 the first engine began pumping at Bloomfield Colliery, Tipton.

Part II · The physics and engineering
Lesson 04

The Newcomen engine and latent heat

For the general reader. Newcomen’s engine worked by making a vacuum. Steam filled a cylinder under a piston; a jet of cold water condensed it; the air outside then pushed the piston down, and a beam pulled up a pump rod in the mine. The trouble was that the cold jet chilled the cylinder itself, so the next charge of steam had to reheat the metal before it could fill the space. Watt measured this loss and found it enormous.

Goals
  • Compute the work of an atmospheric stroke.
  • Draw up the heat budget of a Newcomen cylinder.
  • See why the cylinder had to be cold and hot at the same time.

The atmospheric stroke

A piston of area \(A\) moves a distance \(L\) with atmospheric pressure \(p_0\) above it and residual pressure \(p_r\) below. The work per stroke is

\[ W=(p_0-p_r)\,A\,L. \]

The pressure \(p_r\) is the vapour pressure of water at the temperature of the cylinder after injection. To get a good vacuum the cylinder must be cold: at 60 °C the vapour pressure is about 0.2 atm, at 40 °C about 0.07 atm.

The heat budget

At each stroke the injection water cools the cylinder walls, the piston and the condensate. The next charge of steam condenses on them until they return to 100 °C, and only then does steam fill the cylinder. Watt found that his model consumed several times its own cylinder volume of steam at each stroke. He also measured that steam, when condensed, could heat about six times its own weight of water from cold to boiling. Black explained this as latent heat: about 540 calories per gram are released when steam condenses, against 100 calories to heat water from 0 °C to boiling.

The Newcomen dilemma

Let a cylinder of heat capacity \(C\) be cooled from \(T_s\) (steam temperature) to \(T_r\) at each stroke. The steam lost to reheating it is approximately

\[ m_\text{lost}=\frac{C\,(T_s-T_r)}{L_v}, \]

where \(L_v\) is the latent heat. Lowering \(T_r\) improves the vacuum and the work per stroke, but increases \(m_\text{lost}\). Economy of steam and power per stroke pull in opposite directions so long as condensation happens in the working cylinder.

Exercise 4.1A Newcomen engine has a cylinder 1.0 m in diameter with a stroke of 2.0 m. After injection the cylinder is at 60 °C (vapour pressure 20 kPa). Find the work per stroke, and the mass of steam (at 100 °C, 1 atm, specific volume 1.67 m\(^3\)/kg) that just fills the cylinder.

Show solution
\(A=\pi(0.5)^2=0.785\) m\(^2\), \(V=1.57\) m\(^3\). \(W=(101.3-20)\times10^3\times1.57=1.28\times10^5\) J per stroke. The steam that fills the cylinder is \(1.57/1.67=0.94\) kg.

Exercise 4.2The cylinder and piston of the engine in 4.1 have a heat capacity of 1.0 MJ/K (about 2 tonnes of iron). How much steam is condensed per stroke reheating them from 60 °C to 100 °C? Take \(L_v=2.26\) MJ/kg. What fraction of the steam does useful work?

Show solution
Heat needed \(=1.0\times10^6\times40=4.0\times10^7\) J, so \(m_\text{lost}=4.0\times10^7/2.26\times10^6=17.7\) kg. Only \(0.94/(0.94+17.7)\approx5\%\) of the steam fills the cylinder. Watt’s model, with its small cylinder and large surface, was even worse.
Lesson 05

The separate condenser

For the general reader. Watt’s solution was to stop condensing steam in the cylinder. Connect the cylinder to a separate vessel kept permanently cold. Steam rushes into the cold vessel and condenses there, leaving a vacuum behind it, while the cylinder stays as hot as the steam. A pump removes the water and air that collect in the condenser. With a jacket of steam around the cylinder and the top closed, Watt kept the cylinder hot all the time.

Goals
  • Explain why steam flows into a cold vessel and condenses there.
  • Compute the saving of the separate condenser.
  • Understand the roles of the air pump and steam jacket.

Why it works

The pressure of saturated steam depends only on temperature. If two connected vessels contain water vapour and one is colder, the vapour pressure in the cold one is lower, so vapour flows from the warm vessel into the cold one and condenses there until the pressure everywhere equals the vapour pressure of the coldest surface. The cylinder is therefore exhausted to the condenser pressure without being cooled.

Watt’s patent of 1769, in summary

(1) Keep the cylinder as hot as the steam that enters it, by a casing and a jacket of steam. (2) Condense the steam in vessels separate from the cylinder, kept as cold as the surrounding air. (3) Remove the condensed water and the air from these vessels by pumps worked by the engine. (4) Where convenient, use the expansive force of steam to press on the piston instead of the atmosphere.

The new budget

With the cylinder held at \(T_s\), the reheating loss of Lesson 04 disappears. Each stroke consumes the steam that fills the cylinder, plus small losses by conduction and leakage. The condenser can be kept cold, say at 40 °C, giving a better vacuum than the Newcomen engine could afford. The cost is the injection water, about seven times the weight of the steam, and the work of the air pump.

Watt’s law of steam

Watt also measured the total heat needed to raise water from cold and turn it into steam at different pressures. He concluded that it was nearly the same at all pressures, the latent heat falling as the boiling temperature rose. This rule, known as Watt’s law, was believed until the 1840s, when Henri Victor Regnault showed that the total heat increases slowly with temperature.

Exercise 5.1Fit the engine of Exercise 4.1 with a separate condenser at 40 °C (7.4 kPa) and keep the cylinder at 100 °C. Find the new work per stroke and the steam used, neglecting leakage. Compare the work per kilogram of steam with that of Exercises 4.1–4.2.

Show solution
\(W=(101.3-7.4)\times10^3\times1.57=1.47\times10^5\) J, with 0.94 kg of steam: \(1.57\times10^5\) J/kg. Before, \(1.28\times10^5\) J for 18.6 kg: \(6.9\times10^3\) J/kg. The ideal gain is a factor of about 20. Real engines, with leakage and imperfect jackets, gained a factor of about 3 to 4 over the best Newcomen engines.

Exercise 5.2How much cooling water at 10 °C is needed per kilogram of steam, if the condensate and cooling water leave together at 40 °C? (\(L_v=2.26\) MJ/kg, \(c=4.18\) kJ kg\(^{-1}\) K\(^{-1}\).)

Show solution
Heat to remove per kg of steam: \(2.26\times10^6+4180\times60=2.51\times10^6\) J. Each kg of cooling water absorbs \(4180\times30=1.25\times10^5\) J. So about 20 kg of water per kg of steam. With a colder outlet temperature the ratio rises; with a warmer one, the vacuum worsens.

Exercise 5.3Regnault’s formula for the total heat of saturated steam, from water at 0 °C, is \(\lambda=606.5+0.305\,t\) kcal/kg, with \(t\) in °C. Compare \(\lambda\) at 100 °C and 150 °C, and find the latent heats, taking the sensible heat of water as \(t\) kcal/kg. Was Watt’s law a good approximation?

Show solution
\(\lambda(100)=637.0\), \(\lambda(150)=652.3\) kcal/kg, a rise of 2.4%. Latent heats: \(537\) and \(502\) kcal/kg. The latent heat falls by 35 kcal/kg while the sensible heat rises by 50. Watt’s law was within a few percent over the range of his engines.
Lesson 06

Expansive working and double action

For the general reader. If steam is let into the cylinder for only part of the stroke and then shut off, it continues to push the piston as it expands, with falling pressure. The engine does a little less work per stroke but much more work per pound of steam. Watt understood this by 1769 and patented it in 1782, together with the double-acting engine, in which steam pushes the piston both down and up.

Goals
  • Compute the work of a stroke with early cut-off.
  • Show the gain factor \(1+\ln r\).
  • Understand double action and its consequences for the mechanism.

Work with cut-off

Let steam at pressure \(p_1\) enter a cylinder of volume \(V\) during the first fraction \(1/r\) of the stroke, so the admitted volume is \(V_1=V/r\). Then the valve closes and the steam expands to \(V\). Watt assumed the expanding steam obeys Boyle’s law, \(pV=\text{const}\). Against a back pressure \(p_b\),

\[ W=p_1V_1+\int_{V_1}^{rV_1}\frac{p_1V_1}{V}\,dV-p_b\,rV_1=p_1V_1\,(1+\ln r)-p_b\,rV_1. \]
Expansive gain

For a fixed mass of steam (fixed \(p_1V_1\)) and negligible back pressure, expanding it \(r\)-fold multiplies the work by \(1+\ln r\) compared with admission for the full stroke. The pressure at the end of the stroke falls to \(p_1/r\).

The gain grows without limit in theory, but slowly, and the back pressure, the larger cylinder required, and the cooling of the cylinder by expanding steam set a practical optimum. Watt’s engines usually worked at only a little above atmospheric pressure, and he distrusted high-pressure steam for reasons of safety. In practice the cylinder was jacketed, and the expansion was roughly isothermal, which is why Boyle’s law served.

Double action

In the double-acting engine, steam is admitted alternately above and below the piston, each side being opened to the condenser in turn. The engine produces power on both strokes, doubling the output of a cylinder of given size and making the motion far more uniform. But the piston now pushes as well as pulls, so the chain that connected the piston rod to the arc-headed beam of the pumping engine had to be replaced by a rigid connection. That problem led to the parallel motion of Lesson 07.

Exercise 6.1Steam at 2.0 bar is admitted for one quarter of the stroke of a cylinder of volume 0.80 m\(^3\), and the condenser holds 0.10 bar. Using Boyle’s law, find the work per stroke, and compare with full admission of the same mass of steam (at 2.0 bar for 0.20 m\(^3\)) with no expansion.

Show solution
\(p_1V_1=2.0\times10^5\times0.20=4.0\times10^4\) J. With \(r=4\): \(W=4.0\times10^4(1+\ln4)-10^4\times0.80=9.55\times10^4-0.80\times10^4=8.75\times10^4\) J. Same steam in a 0.20 m\(^3\) cylinder without expansion: \(4.0\times10^4-10^4\times0.20=3.8\times10^4\) J. Expansion more than doubles the work per unit of steam.

Exercise 6.2If the expansion were adiabatic with \(pV^{\gamma}=\text{const}\), \(\gamma=1.13\) (a common figure for wet steam), find the work of expansion from \(V_1\) to \(rV_1\), and evaluate it for \(r=4\) as a fraction of \(p_1V_1\).

Show solution
\(\int_{V_1}^{rV_1}p_1V_1^\gamma V^{-\gamma}dV=\frac{p_1V_1}{\gamma-1}\big(1-r^{1-\gamma}\big)\). With \(r=4\), \(4^{-0.13}=0.835\), so the expansion work is \(0.165/0.13=1.27\,p_1V_1\), slightly less than the isothermal \(\ln4=1.39\,p_1V_1\). The jacket supplies heat during the stroke and moves the process toward the isothermal curve.
Lesson 07

Rotary motion and parallel motion

For the general reader. Mines needed pumps, but mills needed shafts that turn. In 1781 Watt converted the beam’s rocking into rotation with a pair of gears, the sun and planet. In 1784 he found a way to guide the top of the piston rod in a nearly straight line using only hinged bars, so that it could push as well as pull. He later wrote that he was prouder of the parallel motion than of any other mechanical invention he had made.

Goals
  • Find the speed ratio of the sun-and-planet gear.
  • Analyse Watt’s straight-line linkage and its error.
  • See how the parallel motion led to the mathematics of linkages.

Sun and planet

A crank was the obvious way to make rotation, but a patent on the use of a crank with a steam engine was held by James Pickard. Watt’s alternative, worked out with William Murdoch, fixed a gear (the planet) rigidly to the connecting rod and meshed it with a gear (the sun) on the output shaft. The planet’s centre is held on a circular path by a link.

Sun-and-planet ratio

If the planet gear does not rotate relative to the connecting rod, and the rod’s orientation returns to its original value after each revolution of the planet around the sun, then the shaft makes \(1+N_p/N_s\) revolutions per double stroke, where \(N_p,N_s\) are the numbers of teeth. With equal gears, the shaft turns twice per double stroke.

Derivation. Let the planet centre move through angle \(\phi\) about the shaft. The rolling contact requires the arc rolled to match on both gears: \(R_s(\theta_s-\phi)=-R_p(\theta_p-\phi)\), where \(\theta\) are absolute rotation angles. The planet barely rotates (\(\theta_p\approx0\) on average), so over a full circuit \(\theta_s=\phi(1+R_p/R_s)\), and \(R_p/R_s=N_p/N_s\).

The straight-line linkage

Take two arms of length \(r\), pivoted at fixed points \((-r,\tfrac b2)\) and \((r,-\tfrac b2)\), so that in the middle position they are horizontal and point toward each other. Join their free ends by a coupler of length \(b\), vertical in the middle position. As the arms swing, each end of the coupler deviates from the vertical by about \(y^2/2r\), in opposite directions. At the midpoint of the coupler these errors cancel.

Proposition (Watt’s linkage, equal arms)

The midpoint \(P\) of the coupler moves on a curve symmetric under rotation by \(180^\circ\) about the centre. Writing its position as \((x,y)\) with \(y\) the displacement along the line of the stroke, the deviation from the straight line \(x=0\) satisfies

\[ x=\pm\frac{y^5}{4\,b\,r^3}+O(y^7). \]

Why fifth order. The half-turn symmetry makes \(x\) an odd function of \(y\). The quadratic deviations of the two ends cancel at the midpoint, and a careful expansion shows that the cubic terms cancel too, leaving a fifth-order error. The coefficient can be checked numerically, and the hero figure is computed from the exact geometry. With unequal arms \(r_1,r_2\), the straight-line point divides the coupler in the ratio \(r_2:r_1\), lying nearer the end of the longer arm.

Watt combined this linkage with a pantograph so that the straight-line point could be placed over the piston rod while the arms fitted within the beam. Watt chose his proportions by trial. The question of how to choose them optimally led Pafnuty Chebyshev in the 1850s to the theory of best uniform approximation, and later geometers to ask whether any linkage could draw an exact straight line, which Charles-Nicolas Peaucellier answered in 1864.

Exercise 7.1A parallel motion has arms \(r=2.0\) m and coupler \(b=0.50\) m. Estimate the deviation from straightness at \(y=\pm0.40\) m, and the length of stroke over which the deviation stays below 0.1 mm.

Show solution
\(x=0.40^5/(4\times0.50\times8)=0.01024/16=6.4\times10^{-4}\) m \(=0.64\) mm. For \(x=10^{-4}\) m, \(y^5=10^{-4}\times16=1.6\times10^{-3}\), \(y=0.276\) m, so a stroke of about 0.55 m.

Exercise 7.2Show that each end of the coupler deviates from the vertical by approximately \(y^2/2r\) when it has risen by \(y\), and explain why the midpoint is a natural place to look for cancellation.

Show solution
The end of an arm of length \(r\) pivoted on the horizontal moves on a circle: when it has risen by \(y\), it has moved horizontally toward the pivot by \(r-\sqrt{r^2-y^2}\approx y^2/2r\). The left arm’s end moves left and the right arm’s end moves right by the same amount to leading order, so their average, the midpoint, does not move sideways at second order.

Exercise 7.3An engine with equal sun and planet gears makes 20 double strokes per minute. At what speed does the shaft turn? What would it be with a simple crank?

Show solution
Ratio \(1+1=2\), so 40 revolutions per minute. A crank gives one revolution per double stroke, 20 rpm. The doubling was a useful bonus for driving mills.
Lesson 08

The governor and feedback

For the general reader. A mill engine must turn at a steady speed while the load changes. Millwrights already used spinning weights to regulate windmills. In 1788 Watt adapted the idea: two heavy balls on hinged arms spin with the engine; if it speeds up, the balls fly outward and rise, and a linkage partly closes the steam valve. The engine controls itself. The device became the emblem of feedback control.

Goals
  • Find the equilibrium of a conical pendulum.
  • Model an engine with a proportional governor and find its steady-state error.
  • See why governors can hunt.

The conical pendulum

A ball of mass \(m\) on a light arm of length \(l\), hinged on a vertical shaft rotating at angular speed \(\omega\), settles at angle \(\theta\) from the vertical. In the rotating frame the centrifugal force \(m\omega^2l\sin\theta\) balances the horizontal component of tension, and gravity the vertical component:

\[ \cos\theta=\frac{g}{l\,\omega^2}\quad(\omega^2>g/l),\qquad h=l\cos\theta=\frac{g}{\omega^2}, \]

where \(h\) is the depth of the balls below the hinge. The height of the balls is a measure of speed, and a linkage converts it into a valve setting.

Engine and governor

Let the shaft have moment of inertia \(J\), and let the steam torque be \(\tau_s=k\,u\) for valve opening \(u\), against a load torque \(\tau_L\). The governor sets \(u=u_0-K(\omega-\omega_0)\). Then

\[ J\dot\omega=k\,u_0-kK(\omega-\omega_0)-\tau_L. \]
Proportional regulation

If the load changes by \(\Delta\tau\), the speed settles exponentially, with time constant \(J/(kK)\), to a new value displaced by \(\Delta\omega=-\Delta\tau/(kK)\). The governor reduces but does not remove the speed error.

This permanent offset, called droop, is a property of all proportional controllers. James Clerk Maxwell, in On governors (1868), distinguished such moderators from true governors with integral action, and showed that when the inertia of the governor itself and the valve linkage are included, the equations become third order and the engine can oscillate, or hunt, if the gain is too high.

Exercise 8.1Governor arms are 0.25 m long. Find the angle of the arms and the depth of the balls below the hinge at 70 rpm and at 80 rpm of the governor spindle. By how much do the balls rise?

Show solution
70 rpm: \(\omega=7.33\) rad/s, \(h=9.81/53.7=0.183\) m, \(\cos\theta=0.731\), \(\theta=43^\circ\). 80 rpm: \(\omega=8.38\) rad/s, \(h=9.81/70.2=0.140\) m, \(\theta=56^\circ\). The balls rise 4.3 cm for a 14% change of speed. Since \(dh/d\omega=-2h/\omega\), the sensitivity falls at higher speeds, which is why governors were geared to run fast.

Exercise 8.2An engine runs at 30 rpm. With the governor, a 20% increase in load torque lowers the steady speed by 1.5 rpm. What would a 50% load increase do? What gain would be needed to keep the drop below 0.5 rpm for the 20% increase?

Show solution
The offset is proportional to the load change, so a 50% increase lowers the speed by \(1.5\times50/20=3.75\) rpm. To reduce the 20% droop to 0.5 rpm the gain \(K\) must be tripled. Higher gain also shortens the time constant, but in a real engine with valve and governor inertia it brings the risk of hunting.
Lesson 09

Horsepower, duty and the indicator diagram

For the general reader. To sell engines Watt needed to say how much work they did. He defined a horsepower to compare engines with the horses they replaced, measured fuel economy by the duty, and in 1796, with his assistant John Southern, built an instrument that drew the pressure in the cylinder against the motion of the piston. The area of that drawing is the work of a stroke. The firm kept the indicator a trade secret for decades; later it became the founding diagram of thermodynamics.

Goals
  • Reconstruct Watt’s horsepower.
  • Use duty to compare engines.
  • Compute work and power from an indicator diagram.

Horsepower

Around 1782–83 Watt estimated the work of a mill horse walking a circle of radius 12 ft, about 144 turns an hour, against a pull of 180 lbf, and rounded the result to 33,000 ft·lbf per minute.

Definitions

Horsepower: 1 hp \(=33\,000\) ft·lbf/min \(=550\) ft·lbf/s \(\approx745.7\) W.

Duty: the work done, in ft·lbf, by burning one bushel (later 94 lb, or 112 lb) of coal.

Indicated work: for a cycle traced in the pressure–volume plane, \(W=\oint p\,dV\), the enclosed area. Indicated power is \(P=\bar p\,A\,L\,n\), with \(\bar p\) the mean effective pressure, \(A\) the piston area, \(L\) the stroke and \(n\) the number of working strokes per second.

Boulton & Watt charged for their pumping engines a premium of one third of the value of the coal saved compared with a Newcomen engine of equal work, which required accurate duty measurement. Watt engines of the late 1770s typically gave several times the duty of ordinary atmospheric engines.

The indicator

The indicator was a small cylinder connected to the engine cylinder, with a piston held by a spring, so that its rise measured the steam pressure. A pencil on the indicator piston drew on a board moved back and forth by the engine’s beam, in step with the main piston. The closed curve showed admission, cut-off, expansion and exhaust, and revealed leaky valves or poor vacuum at a glance. Émile Clapeyron’s 1834 use of the pressure–volume diagram for Carnot’s cycle put the same picture at the centre of thermodynamics.

Exercise 9.1Reconstruct Watt’s number: a horse pulls with 180 lbf while walking a circle of radius 12 ft at 144 turns per hour. Find the work per minute in ft·lbf and in watts.

Show solution
Distance per minute: \(2\pi\times12\times2.4=181\) ft. Work: \(180\times181=32\,600\) ft·lbf/min, close to the 32,400 often quoted, rounded up to 33,000. In SI: \(32\,600\times1.356/60=737\) W.

Exercise 9.2An indicator diagram from a double-acting engine with a 0.60 m bore and 1.5 m stroke shows a mean effective pressure of 0.70 bar. The engine makes 20 double strokes per minute. Find the indicated power in kilowatts and horsepower.

Show solution
\(A=\pi(0.30)^2=0.283\) m\(^2\). Working strokes per second: \(2\times20/60=0.667\). \(P=0.70\times10^5\times0.283\times1.5\times0.667=1.98\times10^4\) W, about 20 kW or 27 hp.

Exercise 9.3An engine has a duty of 20 million ft·lbf per bushel of 94 lb. Taking the heat of combustion of coal as 30 MJ/kg, find its thermal efficiency.

Show solution
Work: \(2.0\times10^7\times1.356=2.71\times10^7\) J. Heat: \(94\times0.4536\times3.0\times10^7=1.28\times10^9\) J. Efficiency about 2.1%. Even a good Watt engine converted only a few percent of the fuel’s heat into work.
Lesson 10

From Watt’s engine to thermodynamics

For the general reader. Watt improved the engine by eliminating wasteful flows of heat, keeping the hot parts hot and the cold parts cold, and by letting steam expand. In 1824 Sadi Carnot explained why these were the right moves: an engine wastes motive power whenever heat passes between bodies at different temperatures without doing work, and its best possible efficiency is set by the temperatures of its hot and cold sides. Watt’s condenser had created the cold side.

Goals
  • Apply the Carnot limit to Watt’s operating temperatures.
  • Identify the irreversibilities that Watt removed.
  • Understand why higher pressures came after Watt.
Carnot limit

An engine taking heat at absolute temperature \(T_h\) and rejecting it at \(T_c\) has efficiency \(\eta\le1-T_c/T_h\), with equality only for reversible operation.

Reading Watt through Carnot

In the Newcomen engine the same metal is heated by steam at 100 °C and cooled by water at perhaps 20 °C at every stroke. Heat flows across a large temperature difference without doing work: a large irreversibility. Watt’s separate condenser places this flow in a vessel whose temperature never changes, and the jacket keeps the cylinder at the steam temperature. Expansive working lets the steam cool while doing work instead of being dumped hot into the condenser. Each of Watt’s improvements reduces the entropy produced per cycle.

Watt’s steam rarely exceeded about 100–120 °C. With a condenser near 40 °C the Carnot limit is only about 16–20%. To go further, the upper temperature had to rise, and that meant higher pressures, which Watt resisted. Richard Trevithick in Cornwall and Oliver Evans in America built high-pressure engines from about 1800, after the Watt patent expired, and Cornish engines combining high pressure, expansion and Watt’s condenser reached far higher duties in the 1830s.

Exercise 10.1Compute the Carnot limit for steam at 100 °C and a condenser at 40 °C, and for steam at 120 °C with the same condenser. Compare with the efficiency of Exercise 9.3.

Show solution
\(1-313/373=0.161\) and \(1-313/393=0.204\). The real engine at about 2% achieved roughly one eighth of the ideal, the rest being lost in the boiler, the furnace gases, leakage, friction and imperfect expansion.

Exercise 10.2In Exercise 4.2, 17.7 kg of steam condensed on cylinder walls at each stroke, releasing \(4.0\times10^7\) J into metal at an average of about 80 °C, which then gave the same heat to injection water at about 20 °C. Estimate the entropy produced per stroke in the transfer from metal to water, and the work lost, taking \(T_c=293\) K.

Show solution
\(\Delta S\approx Q\,(1/293-1/353)=4.0\times10^7\times5.8\times10^{-4}=2.3\times10^4\) J/K. Lost work \(\approx T_c\Delta S=293\times2.3\times10^4=6.8\times10^6\) J per stroke, about 50 times the useful work of \(1.3\times10^5\) J. This is the waste that Watt’s condenser removed.
Part III · Life and legacy
Lesson 11

Soho, patents and the Lunar Society, 1775–1800

Boulton & Watt did not at first manufacture whole engines. They supplied drawings, supervised erection and provided precision parts, notably valves; cylinders came from John Wilkinson and the rest was built by the purchaser. The first two engines worked in 1776, at Bloomfield Colliery and at Wilkinson’s blast furnace at Broseley. From 1777 the Cornish copper and tin mines, where coal was expensive, became the main market. Watt spent long periods in Cornwall, where William Murdoch was the firm’s resident engineer, and where mine owners resented paying the premium.

Around 1776 Watt married Ann MacGregor, daughter of a Glasgow dyer. The rotative engines of the 1780s opened the market of mills: the Albion Flour Mills in London, cotton mills, breweries and ironworks. Watt also patented a letter-copying process in 1780 that remained in office use for over a century, and in 1786, after visiting Claude Louis Berthollet in Paris, introduced chlorine bleaching to Britain through his father-in-law’s business.

In Birmingham Watt joined the Lunar Society, an informal club that met monthly near the full moon, so that members could ride home by moonlight. Its members included Boulton, Erasmus Darwin, Joseph Priestley, Josiah Wedgwood and William Withering. In 1783, in letters to Priestley, Watt argued that water is not an element but a compound of the gases now called hydrogen and oxygen. Henry Cavendish reached the same conclusion from his experiments, and a priority dispute was argued long after both men had died. Watt became a fellow of the Royal Society of Edinburgh in 1784 and of the Royal Society of London in 1785.

Defending the patent occupied the 1790s. The firm sued engine builders who used separate condensers without licence, among them Edward Bull and later Jabez Carter Hornblower, and in 1799 the courts upheld Watt’s patent. Meanwhile in 1795–96 the partners built the Soho Foundry and began making complete engines, and there Watt and John Southern devised the indicator. By 1800 the firm had built several hundred engines. When the patent expired in 1800, Watt retired, leaving the business to his son James and Boulton’s son Matthew Robinson Boulton.

Lesson 12

Heathfield, death and legacy, 1800–1819

Watt’s retirement at Heathfield Hall, Handsworth, near Birmingham, was more contented than his working life. He travelled, kept up a wide correspondence, and filled a garret workshop with tools and experiments, including machines for copying sculpture. His son Gregory, a promising geologist, died in 1804. Glasgow gave him an honorary doctorate of laws in 1806, and the French Academy of Sciences made him a foreign associate in 1814. In 1816 he gave money to Greenock for a collection of scientific books, the origin of the town’s Watt library. He died at Heathfield on 25 August 1819, aged 83, and was buried at St Mary’s Church, Handsworth, near Boulton.

His garret workshop was left nearly untouched after his death and is now preserved at the Science Museum in London.

Legacy

  • Engineering: the separate condenser, the double-acting rotative engine, expansive working, the parallel motion and the indicator made the steam engine a general source of power for factories, and later for ships and railways. The firm’s methods of measurement, testing and drawing helped create mechanical engineering as a profession.
  • Physics: his measurements on steam, the indicator diagram and the engine itself were the raw material from which Carnot, Clapeyron and later Clausius and Kelvin built thermodynamics.
  • Control and mechanism: the governor led to Maxwell’s theory of feedback; the parallel motion led to Chebyshev’s approximation theory and the study of linkages.
  • Honours: the watt, proposed as a unit of power in 1882, was adopted by the British Association in 1889 and by the International System of Units in 1960. Heriot-Watt University in Edinburgh bears his name, and his portrait appeared on the Bank of England £50 note from 2011, alongside Boulton.

Final projectChoose one of Watt’s improvements from Part II. Write a two-page account for a strong undergraduate that states the problem it solved, works one numerical example in full, and explains the improvement in terms of Carnot’s principle or Newtonian mechanics.

Reference

Connections

People linked to James Watt across this collection. A name without a link has no page here yet. See James Watt in the network of all 337 lives →

Influenced by

  • Thomas Newcomen

Influenced

Colleagues and collaborators

  • Joseph Priestley
  • Claude Louis Berthollet 1786
  • John Roebuck 1765-1773
  • John Southern 1796
  • John Wilkinson
  • Matthew Boulton 1775-1800
  • William Murdoch 1777-1800

Rivals

Friends

Family

  • Gregory Watt

Also mentioned in this life

Fields

Reference

Sources and further reading

Biography

  1. James Watt, Wikipedia (with extensive references).
  2. Science Museum Group, James Watt, 1736–1819.
  3. J. P. Muirhead, The Life of James Watt, John Murray, 1858.
  4. H. W. Dickinson and R. Jenkins, James Watt and the Steam Engine, Clarendon Press, 1927.
  5. R. L. Hills, James Watt, 3 vols., Landmark, 2002–2006.
  6. J. Uglow, The Lunar Men, Faber, 2002.

Physics and engineering

  1. Watt steam engine, Wikipedia.
  2. Horsepower, Wikipedia.
  3. John Southern, Wikipedia; Science Museum Group, Watt’s steam engine indicator.
  4. Institution of Civil Engineers, Smeaton vs Watt: the race to improve the steam engine.
  5. D. S. L. Cardwell, From Watt to Clausius: The Rise of Thermodynamics in the Early Industrial Age, Heinemann, 1971.
  6. J. C. Maxwell, On governors, Proc. R. Soc. London 16 (1868).
  7. O. Mayr, The Origins of Feedback Control, MIT Press, 1970.
  8. E. S. Ferguson, Kinematics of mechanisms from the time of Watt, United States National Museum Bulletin 228 (1962).
  9. S. Carnot, Reflections on the Motive Power of Heat, trans. R. H. Thurston, 1890.