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Johann Bernoulli

Johann I Bernoulli · Jean Bernoulli

A course in two strands: the life of the combative Basel professor who taught the calculus to Europe, from the Marquis de l’Hôpital to Leonhard Euler, and the problems he posed and solved with it, from the hanging chain to the curve of fastest descent.

Born 6 August 1667, Basel Died 1 January 1748, Basel Brachistochrone challenge June 1696 Level advanced undergraduate
Bernoulli’s optical solution of the brachistochrone. In each layer the speed is \(\sqrt{2gy}\); refracting by Snell’s law at every boundary, the ray traces a cycloid (solid), beating the straight chord (dashed).
Lesson 00

How to use this course

Johann Bernoulli did more than anyone except Gottfried Wilhelm Leibniz himself to turn the calculus from a few short papers into a working method. He solved the catenary, posed the brachistochrone, wrote the first lectures on the differential and integral calculus, built the exponential calculus, and helped found the calculus of variations. He also taught Leonhard Euler. He was quarrelsome and jealous, fought publicly with his brother and his son, and has been accused, with reason, of taking credit that was not his. This course presents the mathematics and the man together.

Prerequisites for Part II
  • Single-variable calculus, including integration techniques and Taylor series.
  • First-order differential equations.
  • Newtonian mechanics: energy conservation and statics.
  • For Lesson 09, the Euler–Lagrange equation is helpful but is derived there.

Each technical lesson starts with a paragraph for the general reader, then gives precise statements in modern notation, derivations, and exercises with folded solutions. Bernoulli wrote in Leibniz’s notation, so his formulas look much more modern than those of his English contemporaries.

Reference

Timeline

1667Born 6 August (27 July, Old Style) in Basel, the tenth child of Nicolaus Bernoulli, a spice merchant, and his wife Margaretha.
1683Enters the University of Basel to study medicine; learns mathematics from his brother Jacob.
1690Publishes a dissertation on fermentation.
1691Solves the catenary problem. Lectures in Geneva, then goes to Paris and teaches the calculus to the Marquis de l’Hôpital.
1692Meets Pierre Varignon. Lessons continue at l’Hôpital’s estate at Oucques.
1694Medical doctorate with a dissertation on the motion of muscles. Marries Dorothea Falkner. 22 July: sends l’Hôpital the rule for \(0/0\).
1695Professor of mathematics at Groningen, on the recommendation of Christiaan Huygens.
1696June: poses the brachistochrone problem in Acta Eruditorum. L’Hôpital publishes Analyse des infiniment petits.
1697May: publishes his optical solution. Jacob replies with the isoperimetric problem. Exponential calculus.
1700Son Daniel born 8 February in Groningen.
1705Returns to Basel; succeeds Jacob, who died in August, in the chair of mathematics.
1712Fellow of the Royal Society of London.
1713Enters the Newton–Leibniz priority dispute on Leibniz’s side.
1717States the principle of virtual work in a letter to Varignon.
1718Publishes his mature solution of the isoperimetric problem.
1720sGuides the young Leonhard Euler at Basel.
1734Shares the Grand Prize of the Paris Academy with Daniel.
1742Opera omnia published in four volumes.
1748Dies 1 January in Basel, aged 80.
Part I · Formation
Lesson 01

A Basel family, 1667–1690

Johann Bernoulli was born in Basel on 6 August 1667 (27 July in the Julian calendar then still used there). His family were Protestant refugees from Antwerp who had settled in Basel and prospered in the spice trade. His father, Nicolaus, was a merchant and town official who intended his sons for useful careers. Johann was the tenth child. His brother Jacob, twelve years older, had been told to study theology.

Johann was first put to work in the family business, briefly, in 1682. He did not take to it. In 1683 he entered the University of Basel. His father wanted him to become a physician, and medicine remained his official subject for the next eleven years. His real education took place elsewhere. Jacob had defied their father and taught himself mathematics, and in 1687 he became professor of mathematics at Basel. Johann began to study with him.

Johann’s first publications were medical. A dissertation on fermentation appeared in 1690. His doctoral dissertation of 1694, on the motion of muscles, treated muscle contraction mathematically, with the new calculus. Leibniz reviewed it.

Lesson 02

Two brothers and Leibniz’s calculus

In 1684 Leibniz published a six-page paper in Acta Eruditorum, the Leipzig journal, setting out the rules of his differential calculus. Two years later he published the integral calculus. The papers were terse and full of misprints. Few readers understood them. Jacob and Johann did. Working together through the late 1680s, the brothers mastered Leibniz’s methods and began to extend them.

At first the brothers were partners. They worked on caustics, the envelopes of reflected and refracted rays, in 1692 and 1693. Yet they never published a joint paper, and the partnership turned to rivalry. Johann resented being treated as a pupil. Jacob resented his younger brother’s boasting. In 1691 Jacob posed the problem of the hanging chain in Acta Eruditorum. Johann solved it, and Jacob did not, an outcome Johann recalled with pleasure for the rest of his life (Lesson 04).

By the mid-1690s the quarrel was conducted in public, in the pages of the same journals, with challenge problems and insults. It shaped Johann’s best work, because each brother set problems designed to defeat the other.

Lesson 03

Paris and the Marquis, 1691–1695

In 1691 Johann lectured on the calculus in Geneva and then went to Paris. There he joined the circle of Nicolas Malebranche, where he was one of the very few people in France who understood Leibniz’s methods. He met Pierre Varignon in 1692, beginning a lifelong correspondence. Most importantly, he met Guillaume François Antoine, Marquis de l’Hôpital, a capable mathematician who wanted to learn the new analysis.

Bernoulli gave l’Hôpital lessons in Paris and at his country estate at Oucques, and continued them by letter after returning to Basel. From 1694 the arrangement was formal: l’Hôpital paid him a regular sum, and in return Bernoulli sent him his mathematical discoveries and agreed not to share them with others. One letter, dated 22 July 1694, contained the rule for evaluating \(0/0\) (Lesson 05).

In 1696 l’Hôpital published Analyse des infiniment petits pour l’intelligence des lignes courbes, the first textbook of the differential calculus. Its preface thanked Leibniz and the Bernoullis, but the book drew mostly on Johann’s lessons. Bernoulli said nothing in public until after l’Hôpital’s death in 1704, when he claimed much of the book as his. Many readers dismissed the claim as typical Bernoulli boasting. In 1922 a copy of his differential calculus lectures was found in Basel, and their close agreement with the Analyse showed that he had largely been right.

Meanwhile he married Dorothea Falkner, daughter of a Basel family, in 1694. In 1695, on the recommendation of Christiaan Huygens, he was offered the chair of mathematics at Groningen in the Netherlands. He arrived there with his wife and infant son in October 1695.

Part II · The mathematics
Lesson 04

The catenary

For the general reader. A chain hanging between two hooks looks like a parabola, and Galileo suggested that it was. It is not. In 1691 Jacob Bernoulli challenged mathematicians to find the true curve. Johann, Leibniz and Huygens all solved it. For Johann, just 24, it was the first major success, and a demonstration of what the new calculus could do.

Goals
  • Derive the differential equation of a hanging chain from statics.
  • Solve it and recognize the hyperbolic cosine.
  • Compute arc length, tension and sag.

The equation

Let a uniform chain of weight \(w\) per unit length hang in a vertical plane, with its lowest point on the \(y\)-axis. Consider the piece from the lowest point to a point \(P\) at arc length \(s\). Three forces hold it in equilibrium: the horizontal tension \(H\) at the bottom, the weight \(ws\), and the tension at \(P\), which acts along the tangent. Balancing horizontal and vertical components, the tangent at \(P\) satisfies \(\tan\theta=ws/H\). Writing \(a=H/w\),

\[ \frac{dy}{dx}=\frac{s}{a},\qquad\text{so}\qquad \frac{d^2y}{dx^2}=\frac1a\frac{ds}{dx}=\frac1a\sqrt{1+\Big(\frac{dy}{dx}\Big)^2}. \]
Theorem (Johann Bernoulli, Leibniz, Huygens, 1691)

With the lowest point at \((0,a)\), the hanging chain is the curve

\[ y=a\cosh\frac{x}{a}=\frac a2\big(e^{x/a}+e^{-x/a}\big), \]

whose arc length from the lowest point is \(s=a\sinh(x/a)\). The tension at height \(y\) is \(T=wy\).

Derivation. Put \(p=dy/dx\). Then \(dp/\sqrt{1+p^2}=dx/a\), so \(\operatorname{arsinh}p=x/a\) (using \(p=0\) at \(x=0\)), and \(p=\sinh(x/a)\). Integrating again gives \(y=a\cosh(x/a)\). Bernoulli had no hyperbolic functions. He constructed the curve geometrically from the area under a hyperbola, that is, from logarithms, which is the same thing. For the tension, \(T=H\sec\theta=H\sqrt{1+p^2}=H\cosh(x/a)=wy\).

Exercise 4.1A chain hangs between two points at the same height, \(2L\) apart, with \(a=L\). Find its length and the sag.

Show solution
Length \(=2a\sinh(L/a)=2L\sinh1\approx2.350L\). Sag \(=a\cosh(L/a)-a=L(\cosh1-1)\approx0.543L\).

Exercise 4.2Show that a parabola cannot be the catenary: for which hanging object is the parabola the equilibrium shape?

Show solution
For \(y=x^2/(2a)\), \(y''=1/a\) is constant, but the catenary needs \(y''=\sqrt{1+y'^2}/a\), which grows with \(|x|\). The parabola arises when the load is uniform per unit horizontal length, as for a suspension bridge deck: then \(\tan\theta=wx/H\) and \(y''=w/H\).

Exercise 4.3Show that the catenary’s tension equals the weight of a vertical piece of chain reaching from the point down to the line \(y=0\). (This line is called the directrix.)

Show solution
From the theorem, \(T=wy\), and a vertical piece of length \(y\) weighs \(wy\). Equivalently, a chain draped over a frictionless peg at \(P\) with its free end hanging down to the directrix is in equilibrium.
Lesson 05

The rule for 0/0

For the general reader. What is the value of a fraction when both top and bottom become zero? Bernoulli’s answer, sent to l’Hôpital in July 1694, is to compare how fast each vanishes, using their derivatives. The rule bears l’Hôpital’s name because it first appeared in his 1696 textbook.

Goals
  • State the rule precisely and prove it by Cauchy’s mean value theorem.
  • Understand the original geometric formulation.
  • Recognize when the rule fails.

The original statement

The Analyse considers a curve whose ordinate is \(y=f(x)/g(x)\) with \(f(a)=g(a)=0\). At \(x=a\) both numerator and denominator are “zero”, but their differentials \(df\) and \(dg\) are not. Replacing \(x=a\) by the infinitely near point \(a+dx\), the ordinate becomes \(\frac{f(a)+df}{g(a)+dg}=\frac{df}{dg}\). The book applies this to

\[ y=\frac{\sqrt{2a^3x-x^4}-a\sqrt[3]{a^2x}}{a-\sqrt[4]{ax^3}}\quad\text{at } x=a, \]

finding \(y=\tfrac{16}{9}a\).

Theorem (Bernoulli–l’Hôpital rule, modern form)

Let \(f,g\) be differentiable on an open interval \(I\) containing \(a\), except possibly at \(a\), with \(g'(x)\neq0\) for \(x\neq a\). Suppose \(\lim_{x\to a}f(x)=\lim_{x\to a}g(x)=0\). If \(\lim_{x\to a}f'(x)/g'(x)=L\) exists (finite or infinite), then \(\lim_{x\to a}f(x)/g(x)=L\).

Proof. Extend \(f,g\) by \(f(a)=g(a)=0\). For \(x\neq a\), Cauchy’s mean value theorem gives \(\xi\) strictly between \(a\) and \(x\) with \(\big(f(x)-f(a)\big)g'(\xi)=\big(g(x)-g(a)\big)f'(\xi)\), that is \(f(x)/g(x)=f'(\xi)/g'(\xi)\). (Note \(g(x)\neq0\), else Rolle’s theorem would give a zero of \(g'\).) As \(x\to a\), \(\xi\to a\), and the right side tends to \(L\).

Exercise 5.1Verify the Analyse example: show the limit at \(x=a\) is \(\tfrac{16}{9}a\).

Show solution
Numerator derivative at \(a\): \(\frac{2a^3-4x^3}{2\sqrt{2a^3x-x^4}}-\frac{a\cdot a^{2/3}}{3x^{2/3}}\) at \(x=a\) equals \(\frac{-2a^3}{2a^2}-\frac a3=-a-\frac a3=-\frac{4a}{3}\). Denominator derivative: \(-\frac34a^{1/4}x^{-1/4}\) at \(a\) equals \(-\frac34\). Ratio \(=\frac{4a/3}{3/4}=\frac{16a}{9}\).

Exercise 5.2Let \(f(x)=x^2\sin(1/x)\) and \(g(x)=x\) near 0. Show \(f/g\to0\) but \(f'/g'\) has no limit. Does this contradict the theorem?

Show solution
\(f/g=x\sin(1/x)\to0\). But \(f'(x)/g'(x)=2x\sin(1/x)-\cos(1/x)\) oscillates. No contradiction: the theorem says that if \(f'/g'\) has a limit, so does \(f/g\); the converse is false.

Exercise 5.3Compute \(\lim_{x\to0}\dfrac{x-\sin x}{x^3}\).

Show solution
Apply the rule three times: \(\frac{1-\cos x}{3x^2}\), \(\frac{\sin x}{6x}\), \(\frac{\cos x}{6}\to\frac16\).
Lesson 06

Series and the exponential calculus

For the general reader. Leibniz’s rules handle powers like \(x^3\). Bernoulli extended them to expressions where the variable sits in the exponent, such as \(x^x\). He also found a general series for integrals by repeated integration by parts, and an astonishing identity relating an integral of \(x^{-x}\) to a sum of \(n^{-n}\).

Goals
  • Differentiate exponential expressions by logarithmic differentiation.
  • Derive Bernoulli’s series for an integral.
  • Prove the “sophomore’s dream” identities.

Bernoulli’s series (1694)

Bernoulli’s series

If \(y\) is a smooth function of \(x\), then, formally,

\[ \int_0^x y\,dt = xy-\frac{x^2}{2!}\frac{dy}{dx}+\frac{x^3}{3!}\frac{d^2y}{dx^2}-\frac{x^4}{4!}\frac{d^3y}{dx^3}+\cdots, \]

with all derivatives evaluated at \(x\). For a polynomial \(y\) the series terminates and the identity is exact.

Derivation. Integrate by parts repeatedly: \(\int_0^x y(t)\,dt=\big[(t-x)y(t)\big]_0^x-\int_0^x(t-x)y'(t)\,dt=xy(0)+\cdots\). Bernoulli arranged the steps so the derivatives are taken at the upper limit, which amounts to expanding around \(x\): \(y(t)=\sum_k y^{(k)}(x)(t-x)^k/k!\), integrated term by term. The series is a close relative of the one Brook Taylor published in 1715, and Bernoulli later claimed that Taylor’s series was a consequence of his.

The exponential calculus (1697)

Bernoulli called \(x^x\), \(a^x\) and similar expressions “percurrent” and showed how to differentiate them by taking logarithms: if \(y=x^x\), then \(\ln y=x\ln x\), so \(dy=x^x(1+\ln x)\,dx\).

Theorem (Johann Bernoulli, 1697) \[ \int_0^1 x^{-x}\,dx=\sum_{n=1}^{\infty}\frac1{n^n},\qquad \int_0^1 x^{x}\,dx=\sum_{n=1}^{\infty}\frac{(-1)^{n+1}}{n^n}. \]

Proof. Expand \(x^{-x}=e^{-x\ln x}=\sum_{k\ge0}\frac{(-x\ln x)^k}{k!}\), which converges uniformly on \([0,1]\) since \(|x\ln x|\le 1/e\). Substituting \(x=e^{-u}\) gives \(\int_0^1 x^k(-\ln x)^k\,dx=\int_0^\infty u^ke^{-(k+1)u}\,du=\frac{k!}{(k+1)^{k+1}}\). Summing, \(\int_0^1x^{-x}dx=\sum_{k\ge0}(k+1)^{-(k+1)}\). The second identity is the same with alternating signs.

Exercise 6.1Differentiate \(y=x^{\sin x}\) and \(y=(\ln x)^x\).

Show solution
\(\ln y=\sin x\ln x\), so \(y'=x^{\sin x}\big(\cos x\ln x+\frac{\sin x}{x}\big)\). For the second, \(\ln y=x\ln\ln x\), so \(y'=(\ln x)^x\big(\ln\ln x+\frac1{\ln x}\big)\).

Exercise 6.2Check Bernoulli’s series for \(y=t^2\) on \([0,x]\).

Show solution
\(xy-\frac{x^2}{2}y'+\frac{x^3}{6}y''=x^3-\frac{x^2}{2}(2x)+\frac{x^3}{6}(2)=x^3-x^3+\frac{x^3}{3}=\frac{x^3}{3}\). Correct.

Exercise 6.3Estimate \(\int_0^1x^{-x}\,dx\) to three decimals.

Show solution
\(1+\frac14+\frac1{27}+\frac1{256}+\frac1{3125}+\frac1{46656}+\cdots\approx1+0.25+0.03704+0.00391+0.00032+0.00002\approx1.291\).
Lesson 07

The brachistochrone

For the general reader. Which slide gets a ball from one point to a lower one fastest? Not the straight ramp. In June 1696 Bernoulli challenged the mathematicians of Europe to find the curve. His own solution treated the falling ball as a ray of light passing through layers of glass, each faster than the last. The answer is a cycloid, the curve traced by a point on a rolling wheel.

Goals
  • Know the history of the 1696–97 challenge.
  • Follow Bernoulli’s optical derivation.
  • Verify that the cycloid satisfies the resulting equation.

The challenge

Bernoulli posed the problem in Acta Eruditorum in June 1696. At Leibniz’s suggestion he extended the six-month deadline to Easter 1697, with a printed announcement dated 1 January 1697, which he sent to scholars across Europe. Besides his own, five solutions came in: from Jacob Bernoulli, Leibniz, Ehrenfried Walther von Tschirnhaus, l’Hôpital, and an anonymous solution from England. Isaac Newton had received the problem on 29 January 1697 and solved it overnight. Bernoulli recognized the author, he said, as one knows the lion by its claw. The solutions appeared in the Acta in May 1697.

Bernoulli’s solution

Let the curve start at the origin with \(y\) measured downward. A body falling from rest has speed \(v=\sqrt{2gy}\) by energy conservation. Fermat’s principle says light travels the path of least time, and Snell’s law expresses that principle: at each interface \(\sin\theta/v\) is unchanged, where \(\theta\) is the angle from the vertical. Bernoulli sliced the plane into thin horizontal layers, each with speed \(\sqrt{2gy}\), and concluded that along the fastest path

\[ \frac{\sin\theta}{\sqrt{2gy}}=\text{const}. \]
Theorem (brachistochrone, 1697)

The curve of fastest descent between two points, not on one vertical, under uniform gravity and without friction, is an arc of an inverted cycloid with a cusp at the starting point:

\[ x=r(\varphi-\sin\varphi),\qquad y=r(1-\cos\varphi), \]

where \(r\) is fixed by the end point. Equivalently \(y\big(1+(dy/dx)^2\big)=2r\).

Derivation. Since \(\sin\theta=dx/ds=1/\sqrt{1+y'^2}\), the constant condition reads \(y(1+y'^2)=D\) for a constant \(D\). Solving, \(dx=\sqrt{y/(D-y)}\,dy\). Substitute \(y=D\sin^2(\varphi/2)=\tfrac D2(1-\cos\varphi)\). Then \(dy=D\sin(\varphi/2)\cos(\varphi/2)\,d\varphi\) and \(\sqrt{y/(D-y)}=\tan(\varphi/2)\), so \(dx=D\sin^2(\varphi/2)\,d\varphi=\tfrac D2(1-\cos\varphi)\,d\varphi\). Integrating, \(x=\tfrac D2(\varphi-\sin\varphi)\): a cycloid with \(r=D/2\).

Exercise 7.1Show that the descent time along the cycloid from the cusp to the lowest point is \(\pi\sqrt{r/g}\).

Show solution
\(ds=\sqrt{dx^2+dy^2}=r\sqrt{(1-\cos\varphi)^2+\sin^2\varphi}\,d\varphi=2r\sin(\varphi/2)\,d\varphi\), and \(v=\sqrt{2gr(1-\cos\varphi)}=2\sqrt{gr}\sin(\varphi/2)\). So \(dt=ds/v=\sqrt{r/g}\,d\varphi\), and from \(\varphi=0\) to \(\pi\), \(T=\pi\sqrt{r/g}\).

Exercise 7.2Compare: a straight ramp from the cusp \((0,0)\) to the lowest point \((\pi r,2r)\). Find the descent time and the ratio to the cycloid time.

Show solution
Length \(L=r\sqrt{\pi^2+4}\), constant acceleration \(g\cdot 2r/L\). From \(L=\tfrac12(2gr/L)T^2\), \(T=L/\sqrt{gr}=\sqrt{\pi^2+4}\,\sqrt{r/g}\approx3.724\sqrt{r/g}\). Ratio \(\approx3.724/3.142\approx1.19\): the straight ramp is about 19% slower.

Exercise 7.3From Exercise 7.1, deduce Huygens’ tautochrone property: the time to reach the bottom of the cycloid, starting from rest at any point, is the same.

Show solution
Measure arc length \(\sigma\) from the bottom. For the cycloid, \(\sigma=4r\cos(\varphi/2)\) and the height above the bottom is \(h=2r-y=2r\cos^2(\varphi/2)=\sigma^2/(8r)\). The tangential acceleration is \(-g\,dh/d\sigma=-\frac{g}{4r}\sigma\): simple harmonic motion with period \(4\pi\sqrt{r/g}\), so a quarter period, \(\pi\sqrt{r/g}\), from any starting point.
Lesson 08

Integration and differential equations

For the general reader. Differentiating is mechanical; integrating is an art. Bernoulli’s lectures on the integral calculus, written for l’Hôpital in 1691–92, were the first systematic attempt to teach it. He and Leibniz showed how to integrate every rational function by splitting it into simple fractions, and Johann developed methods for whole families of differential equations.

Goals
  • Integrate rational functions by partial fractions.
  • Solve Bernoulli’s equation by substitution.
  • See Bernoulli’s side of the debate on logarithms of negative numbers.

Rational functions

Theorem (Leibniz, Johann Bernoulli, 1702–03)

Every rational function \(P(x)/Q(x)\) with real coefficients has an antiderivative that is a combination of rational functions, logarithms and arctangents.

The proof factors \(Q\) into real linear and quadratic factors and decomposes into partial fractions. Bernoulli relied on the assertion, then unproved, that every real polynomial so factors; Leibniz doubted it, citing \(x^4+a^4\), until it was shown that \(x^4+a^4=(x^2+\sqrt2ax+a^2)(x^2-\sqrt2ax+a^2)\). The general fact is the fundamental theorem of algebra, proved only in the nineteenth century.

Bernoulli’s equation

In 1695 Jacob Bernoulli proposed the equation below. Leibniz and Johann solved it, Johann by writing the unknown as a product of two functions.

Bernoulli’s equation

For \(n\neq0,1\), the equation \(y'+P(x)y=Q(x)y^n\) becomes linear under \(z=y^{1-n}\):

\[ z'+(1-n)P(x)\,z=(1-n)Q(x). \]

Logarithms of negative numbers

In correspondence of 1712–13 Leibniz argued that \(\log(-1)\) is imaginary. Bernoulli argued that \(\log(-x)=\log x\), since \(d(-x)/(-x)=dx/x\). Both had part of the truth. Euler, Bernoulli’s student, resolved the question in the late 1740s: the logarithm of \(-1\) has infinitely many values \((2k+1)\pi i\).

Exercise 8.1Integrate \(\dfrac{1}{x^4+1}\) by Bernoulli’s method, at least to the partial-fraction stage.

Show solution
\(x^4+1=(x^2+\sqrt2x+1)(x^2-\sqrt2x+1)\). One finds \(\frac1{x^4+1}=\frac{1}{2\sqrt2}\Big(\frac{x+\sqrt2}{x^2+\sqrt2x+1}-\frac{x-\sqrt2}{x^2-\sqrt2x+1}\Big)\). Each term integrates to a logarithm plus an arctangent: \(\int\frac{dx}{x^4+1}=\frac1{4\sqrt2}\ln\frac{x^2+\sqrt2x+1}{x^2-\sqrt2x+1}+\frac1{2\sqrt2}\big(\arctan(\sqrt2x+1)+\arctan(\sqrt2x-1)\big)+C\).

Exercise 8.2Solve \(y'+y=xy^2\).

Show solution
\(n=2\), \(z=1/y\): \(z'-z=-x\). Integrating factor \(e^{-x}\): \((ze^{-x})'=-xe^{-x}\), so \(ze^{-x}=(x+1)e^{-x}+C\), \(z=x+1+Ce^x\), and \(y=1/(x+1+Ce^x)\).

Exercise 8.3Use Bernoulli’s substitution \(y=uv\) on the linear equation \(y'+Py=Q\).

Show solution
\(u'v+uv'+Puv=Q\). Choose \(v\) with \(v'+Pv=0\), i.e. \(v=e^{-\int P}\). Then \(u'v=Q\), so \(u=\int Qe^{\int P}dx\) and \(y=e^{-\int P}\int Qe^{\int P}dx\), the standard formula.
Lesson 09

Isoperimetric problems and geodesics

For the general reader. The brachistochrone asks for the best curve, not the best number. Problems of that kind make up the calculus of variations. Jacob answered his brother’s challenge with a harder one, about curves of fixed length, and the quarrel that followed produced methods that Euler and Lagrange turned into a general theory.

Goals
  • Derive the Euler–Lagrange equation and its first integral.
  • Treat a constraint with a multiplier.
  • Understand Bernoulli’s characterization of geodesics.

The general equation

For a functional \(J[y]=\int_a^b F(x,y,y')\,dx\) with fixed end values, varying \(y\) to \(y+\varepsilon\eta\) with \(\eta(a)=\eta(b)=0\) and integrating by parts gives the condition below. Euler derived it in 1744, building on the Bernoullis’ special methods; Lagrange gave the modern variational derivation in 1755.

Euler–Lagrange equation

If \(y\) is a smooth extremal of \(J\), then \(\dfrac{\partial F}{\partial y}-\dfrac{d}{dx}\dfrac{\partial F}{\partial y'}=0\). If \(F\) does not depend on \(x\), then \(F-y'\,\partial F/\partial y'\) is constant along \(y\).

For the brachistochrone, \(F=\sqrt{(1+y'^2)/y}\), and the first integral gives \(y(1+y'^2)=\text{const}\), Bernoulli’s equation from Lesson 07.

The isoperimetric problem

Jacob’s 1697 problem asked, among curves of given length, for those maximizing an area of a certain type. Johann’s first answer was flawed, and Jacob pointed this out. Johann’s mature solution of 1718 introduced ideas that Euler later systematized. In modern form, to make \(\int F\) stationary subject to \(\int G=\text{const}\), one applies the Euler–Lagrange equation to \(F-\lambda G\) for a constant multiplier \(\lambda\).

Geodesics

In 1697 Johann posed the problem of the shortest path between two points on a convex surface. He showed in 1698 that along such a path the osculating plane always contains the normal to the surface. Equivalently, the acceleration of a point moving along the geodesic at unit speed is normal to the surface. Euler, in one of his early papers, derived the differential equation of geodesics.

Exercise 9.1Use the first integral to show that the shortest curve between two points of the plane is a straight line.

Show solution
\(F=\sqrt{1+y'^2}\), so \(F-y'F_{y'}=\sqrt{1+y'^2}-\frac{y'^2}{\sqrt{1+y'^2}}=\frac{1}{\sqrt{1+y'^2}}\) is constant. Hence \(y'\) is constant and \(y\) is linear.

Exercise 9.2Among curves \(y\ge0\) of fixed length from \((-a,0)\) to \((a,0)\), find those enclosing maximal area with the axis.

Show solution
Make \(\int y\,dx\) stationary with \(\int\sqrt{1+y'^2}dx\) fixed. With \(H=y-\lambda\sqrt{1+y'^2}\), the first integral gives \(y-\lambda/\sqrt{1+y'^2}=c\). Writing \(y'=\tan\theta\), \(y-c=\lambda\cos\theta\), and \(dx=dy/\tan\theta=-\lambda\cos\theta\,d\theta\), so \(x-x_0=-\lambda\sin\theta\). Hence \((x-x_0)^2+(y-c)^2=\lambda^2\): a circular arc.

Exercise 9.3Check Bernoulli’s geodesic property for great circles on a sphere.

Show solution
A great circle lies in a plane through the centre, so its osculating plane is that plane. The surface normal at each point is the radius, which lies in the plane. A unit-speed point on the great circle accelerates toward the centre, along the normal.
Lesson 10

Virtual work and living force

For the general reader. When is a machine in balance? Bernoulli gave a single rule: imagine every possible small motion consistent with the machine’s constraints; it is balanced if the forces do no net work in any of them. He also defended Leibniz’s “living force”, \(mv^2\), the ancestor of kinetic energy, in a long debate about what is conserved in collisions.

Goals
  • State and apply the principle of virtual work.
  • Understand the vis viva controversy and its resolution.

Virtual work (1717)

In a letter to Varignon dated 26 January 1717, Bernoulli stated what he called the principle of virtual velocities. Varignon published it in his Nouvelle mécanique (1725). Lagrange made it the starting point of the Mécanique analytique (1788).

Principle of virtual work

A system with ideal (workless) constraints is in equilibrium under applied forces \(F_i\) if and only if \(\sum_i F_i\cdot\delta r_i=0\) for every virtual displacement \(\{\delta r_i\}\) compatible with the constraints.

Living force

René Descartes had held that the quantity of motion, \(mv\), is conserved; Leibniz argued for \(mv^2\), which he called vis viva. Bernoulli took Leibniz’s side in his Discours sur les loix de la communication du mouvement, written for the Paris Academy prize competition of 1724 and published in 1727. He treated vis viva as conserved, with the apparent losses in inelastic collisions absorbed by the compression of the bodies. The dispute was largely about words. In modern terms momentum \(mv\) and energy \(\tfrac12mv^2\) are both conserved in elastic collisions, and only momentum in inelastic ones, the lost kinetic energy going into heat and deformation.

Exercise 10.1A lever has arms \(a\) and \(b\) with weights \(W_1\) and \(W_2\). Use virtual work to derive the law of the lever.

Show solution
Rotate by \(\delta\phi\): one weight rises \(a\,\delta\phi\), the other falls \(b\,\delta\phi\). Work \(-W_1a\,\delta\phi+W_2b\,\delta\phi=0\) for all \(\delta\phi\) gives \(W_1a=W_2b\).

Exercise 10.2Two equal masses \(m\) collide head-on with speeds \(v\) and \(-v\) and stick together. Which of \(\sum mv\) and \(\sum mv^2\) is conserved? Where did the other go?

Show solution
Before: \(\sum mv=0\), \(\sum mv^2=2mv^2\). After: both zero. Momentum is conserved; the living force is not, being converted into deformation and heat, as Bernoulli’s compression argument partly anticipated.

Exercise 10.3A bead of weight \(W\) rests on a smooth inclined plane of angle \(\alpha\), held by a horizontal force \(P\). Use virtual work to find \(P\).

Show solution
Displace by \(\delta s\) up the plane: the bead rises \(\delta s\sin\alpha\) and moves \(\delta s\cos\alpha\) horizontally. \(P\cos\alpha\,\delta s-W\sin\alpha\,\delta s=0\), so \(P=W\tan\alpha\).
Part III · Life and legacy
Lesson 11

Groningen and Basel, 1695–1748

Bernoulli spent ten years at Groningen. He lectured on mathematics and experimental physics and became involved in theological quarrels with the Calvinist clergy, who suspected his views. His son Daniel was born there in 1700. His nephew Nicolaus Bernoulli, later known as Nicolaus I, came to study with him. Through these years the public conflict with Jacob over the isoperimetric problem continued in print.

In 1705 his wife’s family pressed him to return to Basel, and he set out. On the way he learned that Jacob had died in August. He was appointed to his brother’s chair of mathematics at Basel and held it for the remaining 42 years of his life, declining offers from Utrecht, Leiden and Groningen. He was elected a Fellow of the Royal Society in 1712 and was a member of the academies of Paris, Berlin, St Petersburg and Bologna.

From 1713 Bernoulli was Leibniz’s chief champion in the priority dispute with Newton’s followers. He set problems meant to show the superiority of Leibniz’s methods and wrote anonymous attacks. He also defended Descartes’ theory of vortices against Newtonian gravitation, which slowed the acceptance of Newton’s physics on the Continent.

In the 1720s a young student named Leonhard Euler came to the university. Bernoulli declined to give him private lessons but invited him to bring his difficulties on Sunday afternoons. He soon recognized Euler’s talent and persuaded Euler’s father, an old acquaintance, to let his son study mathematics rather than theology. Bernoulli’s sons Nicolaus II and Daniel went to the new St Petersburg Academy in 1725; when Nicolaus died there in 1726, Euler was invited in his place.

Lesson 12

Quarrels, students and legacy

Bernoulli’s quarrels outlived Jacob. In 1734 he and his son Daniel shared the Grand Prize of the Paris Academy. Johann was so angry at being rated his son’s equal that he barred Daniel from his house. Worse followed. In 1738 Daniel published Hydrodynamica. Johann’s Hydraulica, which drew heavily on his son’s work, bore the date 1732, making it appear to come first. Historians regard the dating as a deliberate attempt to take credit for Daniel’s ideas.

In 1742 his collected works, Opera omnia, appeared in four volumes, including the integral calculus lectures written for l’Hôpital half a century earlier. He died in Basel on 1 January 1748, aged 80. His epitaph calls him the Archimedes of his age.

Legacy

  • Teaching: through l’Hôpital’s Analyse, his own lectures and his students, especially Euler, Daniel Bernoulli, Pierre Louis Maupertuis and Johann Samuel König, he spread Leibniz’s calculus across Europe.
  • Analysis: the catenary, the rule for indeterminate forms, the exponential calculus, partial fractions, and methods for differential equations.
  • Variational calculus: the brachistochrone, the isoperimetric quarrel and geodesics led directly to Euler’s and Lagrange’s general theory.
  • Mechanics: the principle of virtual work, the basis of analytical mechanics.

DiscussionBernoulli sold his discoveries to l’Hôpital, later claimed them back, and predated his own book to take priority from his son. How should historians weigh his priority claims, given that the 1922 discovery showed one of them to be justified?

Final projectChoose one of the challenge problems in Part II. Write a two-page account that states the problem as posed, gives the solution in modern notation, and explains how the competition between the Bernoulli brothers shaped the methods used.

Reference

Sources and further reading

Biography

  1. J. J. O’Connor and E. F. Robertson, Johann Bernoulli, MacTutor History of Mathematics.
  2. Johann Bernoulli, Wikipedia.
  3. J. J. O’Connor and E. F. Robertson, Daniel Bernoulli and Leonhard Euler, MacTutor.
  4. O. Spiess (ed.), Der Briefwechsel von Johann Bernoulli, vol. 1, Birkhäuser, 1955.

Mathematics

  1. Johann Bernoulli, Opera omnia, 4 vols., Lausanne and Geneva, 1742.
  2. G. F. A. de l’Hôpital, Analyse des infiniment petits pour l’intelligence des lignes courbes, Paris, 1696.
  3. Brachistochrone curve, Wikipedia (history and Bernoulli’s optical method).
  4. L’Hôpital’s rule, Wikipedia (history of the 1694 letter).
  5. Sophomore’s dream, Wikipedia.
  6. H. H. Goldstine, A History of the Calculus of Variations from the 17th through the 19th Century, Springer, 1980.
  7. C. Truesdell, The rational mechanics of flexible or elastic bodies 1638–1788, in Euler, Opera omnia ser. II vol. 11, 1960.