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Pierre-Louis Moreau de Maupertuis

Pierre Louis Moreau de Maupertuis

A course in two strands: the life of the Breton soldier turned academician who measured the flattening of the Earth in Lapland and ruled Frederick the Great’s Academy, and the science he left behind: the figure of the Earth, the principle of least action, and an early statistical theory of heredity.

Born 1698, Saint-Malo (baptised 28 September) Died 27 July 1759, Basel Lapland expedition 1736–37 Level advanced undergraduate
The question of the 1730s, with flattening exaggerated. On an oblate Earth (bold) the surface is flatter near the poles, so the same change in latitude covers a longer arc there. On the prolate figure of the Cassinis (dashed) the reverse holds.
Lesson 00

How to use this course

Pierre-Louis Moreau de Maupertuis was not a great calculator. His gift was for choosing questions and for organising people and arguments around them. He brought Newtonian gravitation into the Paris Academy, led the expedition that showed the Earth is flattened at the poles, proposed the principle of least action, and gave one of the first quantitative arguments for biological inheritance. His later years were consumed by a priority dispute and by Voltaire’s ridicule, which long overshadowed his work.

Prerequisites for Part II
  • Calculus of one and several variables; Taylor expansion to first order.
  • Newtonian mechanics: gravitation, centripetal acceleration, momentum and energy.
  • Plane trigonometry (law of sines) for Lesson 05.
  • For Lesson 08, the Euler–Lagrange equation is helpful; the lesson reviews it.
  • For Lesson 09, elementary probability.
  • For Lesson 10, central forces and Kepler orbits.

Each technical lesson opens with a paragraph for the general reader, then gives precise statements in modern notation, derivations and exercises with folded solutions. Maupertuis’s own statements were often loose; the lessons say clearly where his versions differ from the modern ones.

Reference

Timeline

1698Born in Saint-Malo, Brittany; baptised 28 September. His father René Moreau de Maupertuis came from a family of merchant-corsairs.
1714Studies philosophy at the Collège de la Marche in Paris; later tutored in mathematics by Nicolas Guisnée.
1718Commission in a cavalry regiment at Lille; leaves military service by 1722.
1723Elected adjoint of the Académie des Sciences in Paris.
1728Visits London; elected Fellow of the Royal Society.
1729–30Studies with Johann Bernoulli in Basel.
1732Discours sur les différentes figures des astres: the first open defence of Newtonian attraction in the Academy.
1736–37Leads the expedition to the Torne valley in Lapland to measure a degree of the meridian.
173713 November: reports to the Academy that the Earth is flattened at the poles.
1738La Figure de la Terre.
1741Captured by the Austrians at the battle of Mollwitz while with Frederick II; released.
1742Director of the Paris Academy.
174327 June: received into the Académie française.
1744Accord de différentes lois de la nature: least action for light.
1745Vénus physique. Moves to Berlin; marries Eleonore von Borck on 25 August.
1746President of the Berlin Academy. Les lois du mouvement et du repos: least action in mechanics.
1750Essai de cosmologie.
1751Système de la nature: heredity of polydactyly. Samuel König disputes his priority.
1752The Academy declares König’s Leibniz letter unauthentic. Voltaire’s Diatribe du docteur Akakia.
1753–56Long stays in France; final departure from Berlin in 1756.
1758Arrives in Basel in October.
1759Dies 27 July in Basel, in the house of the Bernoulli family. Buried at Dornach.
Part I · Formation
Lesson 01

Saint-Malo and the army, 1698–1722

Maupertuis was born in Saint-Malo, the walled Breton port, in 1698 and baptised on 28 September. His family had grown rich through trade and privateering; his father, René Moreau de Maupertuis, sat on the royal Council of Commerce as a representative of Brittany. He was educated at home by tutors before being sent in 1714 to the Collège de la Marche in Paris, where he studied philosophy under a teacher named Le Blond. After two years he returned to Saint-Malo.

He was drawn to mathematics and music, and in Paris and Saint-Malo he took lessons in mathematics from Nicolas Guisnée, a member of the Academy and author of a textbook applying algebra to geometry. His father thought a military career more suitable. In 1718 he joined a cavalry regiment stationed at Lille. Garrison life left time for study, and he read widely in mathematics and natural philosophy. By 1722 he had left the army and settled in Paris.

In the cafés and salons of the Regency he quickly made a name as a clever, witty and ambitious young man. He would keep a soldier’s manner all his life, and some of the vanity that his enemies later mocked.

Lesson 02

Academician, London, Basel, 1723–1731

In 1723, aged about 25, Maupertuis was elected adjoint of the Académie des Sciences, the junior rank. His first papers, from 1724, dealt with mechanics and the shape of curves in the analytical style of Pierre Varignon. They were respectable, but they did not yet show the direction he would take.

Discovering Newton

In 1728 he spent some months in London and was elected a Fellow of the Royal Society. There he met Newton’s followers and absorbed the Principia. The Paris Academy of the 1720s was firmly Cartesian: gravity was explained by vortices of subtle matter, and Newton’s attraction at a distance was regarded as a return to occult qualities. Maupertuis came back convinced that the Newtonian theory was the better physics.

Basel

He knew that his mathematics was not strong enough to argue the case. In September 1729 he enrolled at the University of Basel and lived in the house of Johann Bernoulli, the greatest living master of the Leibnizian calculus and himself a Cartesian in physics. He worked with Bernoulli for most of a year, returning to Paris by July 1730 with far better technique and a lifelong friendship with the Bernoulli family. He was promoted within the Academy, and began writing the work that would announce his Newtonianism.

Lesson 03

Newton in Paris and the Lapland expedition, 1732–1740

His Discours sur les différentes figures des astres (1732) was the first work by a member of the Paris Academy to defend Newtonian attraction openly. Maupertuis argued cautiously: attraction may be no more mysterious than impulsion, and its mathematical consequences can be tested. He compared the figures that rotating bodies should take under different laws of attraction. The book won the attention of Voltaire and of Émilie du Châtelet, whom Maupertuis taught mathematics and who became a friend.

The shape of the Earth

The figure of the Earth had become a test case. Newton and Christiaan Huygens had predicted an Earth flattened at the poles (oblate). The geodetic surveys of the Cassini family along the meridian of France, finished by Jacques Cassini, suggested the opposite: a degree of latitude seemed to shrink toward the north, implying an Earth elongated at the poles (prolate). The Academy decided to settle the matter by measuring degrees as far apart as possible: one expedition went to Peru in 1735, another, under Maupertuis, to Lapland.

Lapland

The Lapland party left Dunkirk on 2 May 1736: Maupertuis, Alexis Clairaut, Charles Étienne Louis Camus, Pierre Charles Le Monnier, the Abbé Réginald Outhier, and the Swedish astronomer Anders Celsius. They based themselves at Tornio at the head of the Gulf of Bothnia, reached on 19 June 1736. Through the summer they built a chain of triangles up the Torne valley to the hill of Kittisvaara, fighting mosquitoes, forest and rapids. In midwinter they measured a baseline of about 13.5 km on the frozen river and made astronomical observations of latitude at both ends with a zenith sector made by George Graham in London.

The degree came out about 57,400 toises, several hundred toises longer than the degree near Paris. A longer degree at high latitude means the Earth is flatter there: it is oblate. Maupertuis reported to the Academy on 13 November 1737 and published La Figure de la Terre in 1738. Jacques Cassini and his allies contested the result for several years, but a re-measurement of the French arc by César-François Cassini de Thury and Nicolas-Louis de Lacaille confirmed the flattening by 1740. Voltaire hailed Maupertuis as the man who had flattened the Earth and the Cassinis. He became a celebrity, and was painted in Lapland fur pressing down on a globe.

Part II · The science
Lesson 04

The figure of a rotating Earth

For the general reader. A spinning ball of fluid bulges at its equator, because the rotation partly offsets gravity there. How large is the bulge? It depends on how the mass is distributed inside. Huygens and Newton gave two different answers in the 1680s and 1690s, and Maupertuis made the question the centre of French science in the 1730s.

Goals
  • Define the flattening and the rotational parameter \(m\).
  • Derive Huygens’s value \(f=m/2\) for a central mass.
  • State Newton’s value \(f=5m/4\) for a homogeneous fluid and Clairaut’s theorem.

Two small parameters

Let the Earth have equatorial radius \(a\), polar radius \(c\), mass \(M\) and angular velocity \(\omega\). Its flattening is \(f=(a-c)/a\). The ratio of centrifugal to gravitational acceleration at the equator is

\[ m=\frac{\omega^2a^3}{GM}\approx\frac{1}{289}. \]

Both \(f\) and \(m\) are small, and to first order the shape depends only on \(m\) and on the internal structure. The surface of a fluid in equilibrium is a level surface of the combined gravitational and centrifugal potential.

Huygens (1690): all attraction from the centre

If gravity is directed to the centre with magnitude \(GM/r^2\), as for a point mass, the equilibrium surface has flattening \(f=\tfrac12 m\) to first order. For the Earth this gives \(f\approx1/578\).

Derivation. The effective potential is \(U=-\frac{GM}{r}-\tfrac12\omega^2r^2\cos^2\varphi\), with \(\varphi\) the latitude. The surface is a level set, so \(U(a,0)=U(c,\tfrac\pi2)\): \(\frac{GM}{a}+\tfrac12\omega^2a^2=\frac{GM}{c}\). Hence \(\frac ac-1=\frac{\omega^2a^3}{2GM}=\frac m2\), and \(f\approx m/2\).

Newton (1687) and Maclaurin (1742): homogeneous fluid

A homogeneous, self-gravitating fluid in slow uniform rotation takes the form of an oblate spheroid with \(f=\tfrac54m\) to first order. For the Earth Newton obtained \(f\approx1/230\).

The flattening is larger because the bulge itself attracts: the extra matter at the equator adds to the deformation. Newton’s argument balanced the weights of two fluid columns, one from the centre to the pole and one from the centre to the equator. Colin Maclaurin proved in 1742 that the oblate spheroid is an exact equilibrium figure for any rotation rate below a critical value.

Clairaut’s theorem (1743)

For a rotating body made of nearly spherical layers of fluid in equilibrium, with any density increasing toward the centre, gravity at latitude \(\varphi\) is \(g(\varphi)=g_e\big(1+\beta\sin^2\varphi\big)\) to first order, with

\[ \beta=\frac{g_p-g_e}{g_e}=\frac52\,m-f. \]

The flattening lies between Huygens’s and Newton’s values: \(\tfrac12m\le f\le\tfrac54m\).

Clairaut proved this after returning from Lapland, in Théorie de la figure de la terre. It linked the shape of the Earth to measurements of gravity by pendulums, which Maupertuis’s party also made in the north. The modern value is \(f\approx1/298.26\), which lies between the two extremes, as Clairaut’s theorem requires for an Earth denser at the centre.

Exercise 4.1Compute \(m\) for the Earth from \(\omega=7.292\times10^{-5}\ \text{s}^{-1}\), \(a=6.378\times10^6\) m and \(GM=3.986\times10^{14}\ \text{m}^3\text{s}^{-2}\). Then compute the Huygens and Newton flattenings.

Show solution
\(\omega^2a^3=5.317\times10^{-9}\times2.594\times10^{20}\approx1.380\times10^{12}\), so \(m\approx1.380\times10^{12}/3.986\times10^{14}\approx3.46\times10^{-3}\approx1/289\). Huygens: \(f=m/2\approx1/578\). Newton: \(f=5m/4\approx1/231\).

Exercise 4.2Use Clairaut’s theorem with \(m=1/289\) and \(f=1/298.3\) to predict the fractional excess of polar over equatorial gravity, and compare with the measured values \(g_e=9.780\), \(g_p=9.832\ \text{m s}^{-2}\).

Show solution
\(\beta=\tfrac52\cdot0.003460-0.003352\approx0.00865-0.00335=0.00530\). Measured: \((9.832-9.780)/9.780\approx0.00532\). The agreement is excellent.

Exercise 4.3Jupiter rotates in about 9.93 hours, has \(GM=1.267\times10^{17}\ \text{m}^3\text{s}^{-2}\) and equatorial radius \(7.15\times10^7\) m. Compute \(m\) and the Huygens and Newton bounds. Its observed flattening is about 0.065. What does this suggest?

Show solution
\(\omega=2\pi/35\,750\approx1.758\times10^{-4}\ \text{s}^{-1}\), \(\omega^2a^3\approx3.09\times10^{-8}\times3.655\times10^{23}\approx1.13\times10^{16}\), so \(m\approx0.089\). Bounds: \(0.045\le f\le0.11\). The observed 0.065 lies between, closer to the lower end: Jupiter is strongly concentrated toward its centre.
Lesson 05

Measuring a degree

For the general reader. To find the shape of the Earth without leaving it, measure how far you must travel north for the stars overhead to shift by one degree. On a sphere this distance is the same everywhere. On a flattened Earth it is longer near the poles. The Lapland expedition did this measurement close to the Arctic Circle, using a chain of triangles over the forest and a baseline measured on the frozen river.

Goals
  • Derive the length of a degree of latitude on a spheroid to first order in \(f\).
  • Extract the flattening from two measured degrees.
  • Understand triangulation and astronomical latitude.

Geodetic latitude and the meridian degree

Latitude, as measured with a zenith sector, is the angle between the local vertical and the equatorial plane. On an ellipsoid with semi-axes \(a\) and \(c\) and eccentricity \(e^2=1-c^2/a^2\approx2f\), the radius of curvature of the meridian at latitude \(\varphi\) is

\[ M(\varphi)=\frac{a(1-e^2)}{(1-e^2\sin^2\varphi)^{3/2}}. \]
Proposition (first-order degree formula)

The length of one degree of latitude centred at \(\varphi\) is \(D(\varphi)=\frac{\pi}{180}M(\varphi)\). To first order in \(f\),

\[ D(\varphi)\approx D_0\big(1+3f\sin^2\varphi\big),\qquad D_0=\frac{\pi a}{180}(1-2f). \]

Consequently, if degrees \(D_1,D_2\) are measured at latitudes \(\varphi_1,\varphi_2\),

\[ f\approx\frac{D_2/D_1-1}{3\,(\sin^2\varphi_2-\sin^2\varphi_1)}. \]

Derivation. Expand with \(e^2\approx2f\): \((1-e^2\sin^2\varphi)^{-3/2}\approx1+3f\sin^2\varphi\) and \(1-e^2\approx1-2f\). The ratio formula follows by dividing and keeping first-order terms. For \(f>0\) the degree grows toward the pole: this is what the Lapland measurement showed.

Triangulation

Distances over tens of kilometres cannot be measured with rods. The surveyors measured one baseline directly and then only angles. In a triangle with a known side \(b\) and angles \(A,B,C\), the law of sines \(\frac{a}{\sin A}=\frac{b}{\sin B}=\frac{c}{\sin C}\) gives the other sides, and each new triangle shares a side with the last. The chain carries the scale from the baseline to the ends of the arc, and the projected north–south distance between the ends gives the length of the arc. The latitude difference comes from the zenith distances \(z_S,z_N\) of the same star crossing the meridian at the two ends: \(\Delta\varphi=z_S-z_N\) for a star north of both zeniths, with corrections for refraction, aberration and precession.

The numbers

Jean Picard’s degree between Paris and Amiens (1669–70) was 57,060 toises; the Lapland degree came out at about 57,400 toises. With the later corrected values used by historians, a degree at latitude 66°10′ in Lapland was 57,395 toises and a degree at 0°30′ in Peru was 56,768 toises. The modern value at the Lapland latitude is about 57,210 toises, so the Lapland degree was too long by roughly 200 toises, exaggerating the flattening. The direction of the effect was nevertheless right, and decisive.

Exercise 5.1Use the Lapland degree 57,395 toises at \(66^\circ10'\) and the Peru degree 56,768 toises at \(0^\circ30'\) to estimate the flattening.

Show solution
\(D_2/D_1-1=627/56\,768\approx0.01105\). \(\sin^2(66.17^\circ)\approx0.8364\), \(\sin^2(0.5^\circ)\approx0.0001\). So \(f\approx0.01105/(3\times0.8363)\approx0.00440\approx1/227\), close to Newton’s 1/230 and well above the modern 1/298, reflecting the error in the Lapland arc.

Exercise 5.2Show that if the Earth were prolate (\(f<0\)), as Jacques Cassini believed, the degree in Lapland would be shorter than the degree in France. How much shorter for \(f=-1/100\), comparing \(66^\circ\) with \(49^\circ\)?

Show solution
\(D\propto1+3f\sin^2\varphi\), which decreases with \(\varphi\) when \(f<0\). With \(f=-0.01\): \(3f(\sin^266^\circ-\sin^249^\circ)=-0.03\,(0.8346-0.5696)\approx-0.0080\), so about 0.8% shorter, roughly 460 toises on a 57,000-toise degree. The measurement showed the opposite sign.

Exercise 5.3In a triangle, the measured base is \(AB=10.00\) km and the angles at \(A\) and \(B\) are \(62^\circ\) and \(71^\circ\). Find \(AC\) and \(BC\).

Show solution
\(C=180^\circ-62^\circ-71^\circ=47^\circ\). By the law of sines, \(AC=AB\sin B/\sin C=10\times0.9455/0.7314\approx12.93\) km and \(BC=AB\sin A/\sin C=10\times0.8829/0.7314\approx12.07\) km.
Lesson 06

Least action and refraction (1744)

For the general reader. When light passes from air into water it bends. Pierre de Fermat had explained this in the 1660s by saying light takes the path of least time. Maupertuis disliked the idea that light should “know” about time, and proposed instead that nature spends the least of a quantity he called action. Strangely, his rule gives the same law of refraction from the opposite assumption about the speed of light.

Goals
  • State Maupertuis’s 1744 principle for light.
  • Derive the law of refraction from it and compare with Fermat.
  • Understand why the two principles agree on the law and disagree on the speeds.

The 1744 memoir

In 1744 Maupertuis read to the Paris Academy his Accord de différentes lois de la nature qui avaient jusqu’ici paru incompatibles. He defined the action along a path as the sum of the products of each distance travelled and the speed along it, and asserted that light follows the path for which the total action is least. He took the Newtonian view that light is a stream of particles moving faster in a denser medium.

Principle (Maupertuis, 1744)

A ray going from \(P\) in a medium where light has speed \(v_1\) to \(Q\) in a medium where it has speed \(v_2\), crossing a plane interface, follows the path that minimises \(A=v_1\ell_1+v_2\ell_2\), where \(\ell_1,\ell_2\) are the lengths of the two straight segments.

Consequence

If \(\theta_1,\theta_2\) are the angles of the ray to the normal, the minimum satisfies

\[ v_1\sin\theta_1=v_2\sin\theta_2,\qquad\text{i.e.}\qquad\frac{\sin\theta_1}{\sin\theta_2}=\frac{v_2}{v_1}. \]

Fermat’s principle, minimising \(\ell_1/v_1+\ell_2/v_2\), gives instead \(\dfrac{\sin\theta_1}{\sin\theta_2}=\dfrac{v_1}{v_2}\).

Derivation. Put \(P=(0,h_1)\), \(Q=(d,-h_2)\), and let the ray cross the interface \(y=0\) at \((x,0)\). Then \(A(x)=v_1\sqrt{x^2+h_1^2}+v_2\sqrt{(d-x)^2+h_2^2}\) and

\[ A'(x)=v_1\frac{x}{\sqrt{x^2+h_1^2}}-v_2\frac{d-x}{\sqrt{(d-x)^2+h_2^2}}=v_1\sin\theta_1-v_2\sin\theta_2. \]

Setting \(A'(x)=0\) gives the law. \(A\) is a sum of convex functions, so the critical point is the unique minimum.

Two theories, one law

Both principles give Snell’s law \(\sin\theta_1/\sin\theta_2=\text{const}\). They disagree about what the constant means. For light entering water, \(\theta_2<\theta_1\). Maupertuis’s version then needs \(v_2>v_1\), faster in water, as in Newton’s corpuscular theory; Fermat’s needs \(v_2<v_1\), as in Huygens’s wave theory. Léon Foucault’s measurement of 1850 showed light is slower in water. In modern terms Maupertuis’s “speed” is better read as the momentum of the light corpuscle, and his principle is the mechanical counterpart of Fermat’s optical one (Lesson 08).

Exercise 6.1Show that for reflection from a plane mirror (one medium, \(v_1=v_2\)), both principles give equal angles of incidence and reflection.

Show solution
With equal speeds both functionals are proportional to total length \(\ell_1+\ell_2\). Reflect \(Q\) in the mirror to \(Q'\); the length equals \(|PX|+|XQ'|\), least when \(X\) lies on segment \(PQ'\), which makes the angles equal (Hero of Alexandria’s argument).

Exercise 6.2Light enters water from air at \(\theta_1=40^\circ\), and the refractive index of water is \(1.333\). Find \(\theta_2\). What speed ratio \(v_{\text{water}}/v_{\text{air}}\) does each principle require?

Show solution
\(\sin\theta_2=\sin40^\circ/1.333\approx0.4822\), so \(\theta_2\approx28.8^\circ\). Maupertuis: \(v_2/v_1=\sin\theta_1/\sin\theta_2=1.333\). Fermat: \(v_2/v_1=1/1.333\approx0.75\). Experiment favours Fermat.

Exercise 6.3Show that a Newtonian corpuscle crossing an interface, where a force normal to the interface changes its speed from \(v_1\) to \(v_2\), obeys \(v_1\sin\theta_1=v_2\sin\theta_2\).

Show solution
The force is normal to the interface, so the tangential component of velocity is conserved: \(v_1\sin\theta_1=v_2\sin\theta_2\). Maupertuis’s minimum principle reproduces this mechanical law, which is why it agreed with Newton’s optics.
Lesson 07

Least action in collisions and statics (1746)

For the general reader. Two years later, as president of the Berlin Academy, Maupertuis raised his principle into a universal law: whenever any change occurs in nature, the quantity of action used is the least possible. He derived the rules of collision and of the lever from it, and claimed that such economy was evidence of a wise Creator.

Goals
  • Reproduce Maupertuis’s derivations of the laws of inelastic and elastic impact.
  • Derive the law of the lever from his “law of rest”.
  • See what is right and what is arbitrary in these derivations.

The rule of 1746

In Les lois du mouvement et du repos déduites d’un principe métaphysique, read to the Berlin Academy in 1746, Maupertuis defined the quantity of action as mass times speed times distance, \(mvs\). For a change of velocity occurring over a fixed time, distance is proportional to speed, so the action of a change from speed \(u\) to speed \(w\) is proportional to \(m(u-w)^2\). He asserted that the change that actually occurs makes the total of these quantities a minimum.

Inelastic impact

Bodies of masses \(A,B\) with velocities \(a,b\) collide and move together with common velocity \(x\). Minimising \(A(a-x)^2+B(b-x)^2\) gives

\[ x=\frac{Aa+Bb}{A+B}, \]

which is conservation of momentum.

Elastic impact

For perfectly elastic bodies Maupertuis imposed that the relative velocity is reversed, \(\alpha-\beta=-(a-b)\), and minimised \(A(a-\alpha)^2+B(b-\beta)^2\). The result is

\[ \alpha=\frac{(A-B)a+2Bb}{A+B},\qquad\beta=\frac{(B-A)b+2Aa}{A+B}, \]

the correct laws of elastic collision.

Derivation for the elastic case. Write \(\beta=\alpha+a-b\) and minimise \(F(\alpha)=A(a-\alpha)^2+B(2b-a-\alpha)^2\). Then \(F'(\alpha)=-2A(a-\alpha)-2B(2b-a-\alpha)=0\) gives \(\alpha(A+B)=Aa+2Bb-Ba\), as stated. Note that the minimisation again reproduces conservation of momentum, \(A\alpha+B\beta=Aa+Bb\).

The law of rest: the lever

A lever of length \(c\) carries weights \(A\) and \(B\) at its ends, with the fulcrum at distance \(x\) from \(A\). Maupertuis considered small motions, in which the speeds and distances of the ends are proportional to their arms, so the action is proportional to \(Ax^2+B(c-x)^2\). Requiring this to be minimal gives \(Ax=B(c-x)\): Archimedes’ law of the lever.

Assessment

The derivations reach correct results, but the choice of what to minimise is adjusted to each case: Maupertuis needed the extra condition on relative velocity for elastic bodies, and the lever argument rests on a quantity chosen to give the right answer. The principle as he stated it was too vague to be a law of mechanics, and he gave it a theological reading. Euler had already given the precise version for a particle in 1744 (Lesson 08), and it was that version, not Maupertuis’s, that entered physics.

Exercise 7.1In Maupertuis’s elastic law, set \(A=B\). What happens? Then let \(B\to\infty\) with \(b=0\).

Show solution
\(A=B\): \(\alpha=b\), \(\beta=a\); the bodies exchange velocities. \(B\to\infty\), \(b=0\): \(\alpha\to-a\), \(\beta\to0\); the small body rebounds from a fixed wall with reversed velocity.

Exercise 7.2Check that Maupertuis’s elastic solution conserves kinetic energy \(\tfrac12A\alpha^2+\tfrac12B\beta^2\).

Show solution
Momentum conservation gives \(A(a-\alpha)=B(\beta-b)\); reversal of relative velocity gives \(a+\alpha=\beta+b\). Multiplying, \(A(a^2-\alpha^2)=B(\beta^2-b^2)\), which is energy conservation.

Exercise 7.3Find where the fulcrum must be placed on a 3 m lever to balance 20 kg against 40 kg, using the law of rest.

Show solution
Minimise \(20x^2+40(3-x)^2\): derivative \(40x-80(3-x)=0\), so \(x=2\) m from the 20 kg weight and 1 m from the 40 kg weight. Indeed \(20\times2=40\times1\).
Lesson 08

From Maupertuis to Euler, Lagrange and Jacobi

For the general reader. Maupertuis named the principle; others made it exact. Within a century it had become one of the foundations of physics: the laws of motion can be written as the statement that a single number, the action, is stationary along the true path. The same idea guides the path integrals of quantum mechanics.

Goals
  • State the principle of least action in Euler’s form and in Jacobi’s geometric form.
  • Derive a trajectory from it.
  • Distinguish Maupertuis’s principle from Hamilton’s principle.

Euler’s version

In an appendix to his Methodus inveniendi lineas curvas (1744), Leonhard Euler showed that a particle moving under central forces follows a path for which \(\int v\,ds\) is a minimum, among paths with the same endpoints, provided the speed is determined by the conservation of energy. Euler gave Maupertuis the credit for the general principle, and defended him later in the König affair. Joseph-Louis Lagrange extended the result in 1760 to systems of particles.

Principle of least action (Maupertuis–Euler–Lagrange form)

Let a conservative system have kinetic energy \(T\) and potential \(V\), with total energy \(E=T+V\) fixed. Among all paths in configuration space joining two given configurations and traversed with energy \(E\), the actual motion makes the abbreviated action

\[ S_0=\int 2T\,dt=\int\sum_i p_i\,dq_i \]

stationary. For short enough paths it is a minimum.

Jacobi’s form

For one particle of mass \(m\), \(2T\,dt=mv\,ds\) and \(v=\sqrt{2(E-V)/m}\), so

\[ S_0=\int\sqrt{2m\,(E-V(\mathbf x))}\;ds. \]

Carl Gustav Jacob Jacobi observed in the 1830s that time has disappeared: the trajectories are the geodesics of the metric \(d\sigma^2=2m(E-V)\,ds^2\). The same equation describes light rays in a medium of refractive index \(n(\mathbf x)\propto\sqrt{E-V(\mathbf x)}\). Maupertuis’s corpuscular optics of 1744 is exactly this analogy, with light faster where the index is larger.

Hamilton’s principle

William Rowan Hamilton in 1834–35 gave a different principle: with both endpoints fixed in time, the actual motion makes \(S=\int(T-V)\,dt\) stationary. Hamilton’s principle varies paths with fixed duration; Maupertuis’s fixes the energy instead. The two are related by a Legendre transform, \(S=S_0-Et\), and they lead to the same equations of motion. In quantum mechanics the phase of the wave function is \(S/\hbar\), and Louis de Broglie took the parallel between Maupertuis’s and Fermat’s principles as the starting point of wave mechanics.

Exercise 8.1A particle moves in a uniform field \(V=mgy\). Show using Jacobi’s form that the horizontal component of \(\sqrt{E-V}\,\hat{\mathbf t}\) is constant along the path (\(\hat{\mathbf t}\) the unit tangent), and deduce that the path is a parabola.

Show solution
The integrand \(\sqrt{2m(E-mgy)}\sqrt{1+y'^2}\) does not depend on \(x\), so (as in Snell’s law for horizontal layers) \(\sqrt{E-mgy}\,\frac{1}{\sqrt{1+y'^2}}=K\) is conserved. This is \(\sqrt{E-mgy}\cos\theta\), proportional to the horizontal velocity \(v\cos\theta\). Then \(1+y'^2=(E-mgy)/K^2\). Differentiating, \(2y'y''=-mgy'/K^2\), so \(y''=-mg/(2K^2)\), constant: a parabola.

Exercise 8.2Show that for a free particle (\(V=0\)) the principle gives straight lines, and explain why the principle says “stationary” and not always “least”. Consider a particle constrained to a sphere.

Show solution
With \(V=0\), \(S_0=\sqrt{2mE}\times\text{length}\), so the paths are the shortest curves: straight lines in the plane, great circles on a sphere. Between two points on a sphere there are two great-circle arcs. The longer one (more than half a great circle) is a genuine trajectory but not a minimum of length: it passes the antipodal point, a conjugate point, after which the minimum property fails.
Lesson 09

Heredity and probability

For the general reader. In the 1740s most naturalists believed that each living thing was already formed in miniature in the egg or the sperm. Maupertuis rejected this. Children resemble both parents, he argued, so both must contribute material. To show that traits are inherited, and not repeated by chance, he followed an unusual trait through a family over several generations and calculated the odds.

Goals
  • Summarise the arguments of Vénus physique and Système de la nature.
  • Reproduce Maupertuis’s probabilistic argument for inheritance.
  • Compare it with a modern analysis of a dominant trait.

Against preformation

The Dissertation physique à l’occasion du nègre blanc (1744), prompted by an albino child shown in Paris, and its expansion Vénus physique (1745), published anonymously, argued that preformation could not explain resemblance to both parents or the appearance of hybrids such as mules. Maupertuis proposed that particles from every part of each parent’s body meet and combine, guided by something like chemical affinity, to form the embryo. Errors in the arrangement of particles could produce new varieties, and he speculated that new species might arise in this way. Historians have read these passages as early anticipations of particulate inheritance and of variation as a source of new forms, though Maupertuis gave no mechanism of selection.

The Ruhe family

In Système de la nature (1751) and his Lettres (1752) he described polydactyly, extra fingers and toes, in the family of Jacob Ruhe, a Berlin surgeon. The trait appeared in several generations and was passed on through both mothers and fathers. Maupertuis estimated that polydactyly occurs in about one person in 20,000, and argued that its repeated appearance in one line by chance was so improbable that it must be inherited.

The argument in modern form

Suppose a trait occurs independently in each person with probability \(p\). The probability that it appears by chance in a given parent, child and grandchild is \(p^3\). For \(p=1/20\,000\) this is \(1/(8\times10^{12})\). Compared with a hypothesis \(H\) of inheritance under which an affected parent has an affected child with probability \(q\), the likelihood ratio for two transmissions is

\[ \frac{P(\text{data}\mid H)}{P(\text{data}\mid\text{chance})}=\frac{p\,q^2}{p^3}=\Big(\frac{q}{p}\Big)^2. \]

With \(q=\tfrac12\), as for an autosomal dominant trait, the ratio is \(10^8\). Maupertuis did not have the concept of a likelihood ratio, but his argument was one of the first uses of probability to test a biological hypothesis.

Cosmology and utility

In the Essai de cosmologie (1750) he criticised arguments for God drawn from the intricate details of animals, and argued that the evidence should come from general laws, above all least action. He also proposed to measure happiness, treating a pleasure or pain as the product of its intensity and its duration, an early version of the calculus later associated with utilitarianism.

Exercise 9.1A trait has population frequency \(p=1/20\,000\). In a family it appears in a grandmother, her son, and two of his four children. Taking the grandmother’s trait as given, compare the probability of the rest of the pattern under independent chance and under a dominant model in which each child of an affected parent is affected with probability \(\tfrac12\).

Show solution
Chance: the son is affected with probability \(p\), and exactly two of four children with probability \(\binom42p^2(1-p)^2\approx6p^2\). Total \(\approx6p^3\approx7.5\times10^{-13}\). Dominant model: \(\tfrac12\times\binom42\big(\tfrac12\big)^4=\tfrac12\times\tfrac{6}{16}\approx0.19\). The likelihood ratio is about \(0.19/(7.5\times10^{-13})\approx2.5\times10^{11}\): overwhelming evidence for inheritance.

Exercise 9.2Maupertuis noted that the trait passed through both a mother and a father. Why does this matter for the theory of preformation?

Show solution
Ovists held that the embryo is preformed in the mother’s egg, and spermists that it is preformed in the father’s sperm; either way only one parent supplies the form. A trait transmitted by fathers in some cases and mothers in others shows that both parents contribute hereditary material, as Maupertuis’s particle theory required.
Lesson 10

Laws of attraction and the figures of the stars

For the general reader. Maupertuis’s case for Newton in 1732 was cautious. He did not claim that gravity must fall off as the inverse square of distance; he asked what the world would look like under other laws, and argued that the inverse square is singled out by its consequences. This lesson works through the mathematics behind that argument.

Goals
  • Prove Newton’s shell theorem and see which force laws make a sphere attract like a point.
  • Find which power laws allow stable circular orbits.
  • Understand the argument of the Discours about flattened stars.

Spheres that attract like points

Newton showed in the Principia (Book I, Section 12) that a uniform spherical shell attracts an outside particle as if its mass were at the centre when the force varies as \(r^{-2}\), and also when it varies as \(r\). These are the only power laws with this property, up to adding the two together. Maupertuis made this one of his arguments: only under the inverse square (among the decreasing laws) do the planets and the Sun act on each other as points, which is why Kepler’s laws hold so simply.

Shell theorem (inverse square)

Let a thin uniform spherical shell of mass \(M\) and radius \(R\) attract a particle of mass \(m\) at distance \(r\) from its centre by the law \(F=Gm\,dM/s^2\) for each element \(dM\) at distance \(s\). Then the net force is \(GMm/r^2\) toward the centre if \(r>R\), and zero if \(r<R\).

Proof via the potential. The potential of the shell is \(\Phi(r)=-G\int dM/s\). A ring at polar angle \(\theta\) has mass \(\tfrac M2\sin\theta\,d\theta\) and distance \(s^2=r^2+R^2-2rR\cos\theta\), so \(s\,ds=rR\sin\theta\,d\theta\). Then

\[ \Phi(r)=-\frac{GM}{2}\int_0^\pi\frac{\sin\theta\,d\theta}{s}=-\frac{GM}{2rR}\int_{|r-R|}^{r+R}ds=-\frac{GM}{2rR}\big(r+R-|r-R|\big), \]

which is \(-GM/r\) for \(r>R\) and the constant \(-GM/R\) for \(r<R\). Differentiating gives the force.

Stable circular orbits

Proposition

For an attractive central force \(F(r)=k\,r^{-n}\) with \(k>0\), circular orbits exist at every radius, and they are stable under small radial perturbations if and only if \(n<3\). The radial oscillation about a circular orbit has angular frequency \(\sqrt{3-n}\) times the orbital angular velocity.

Proof. With angular momentum \(L\), the radial equation is \(m\ddot r=L^2/(mr^3)-k\,r^{-n}\). Circular orbits satisfy \(L^2/(mr_0^3)=k\,r_0^{-n}\). Linearise with \(r=r_0+\delta\): \(m\ddot\delta=\big[-3L^2/(mr_0^4)+nk\,r_0^{-n-1}\big]\delta=-(3-n)\frac{L^2}{mr_0^4}\,\delta\). Since \(\Omega^2=L^2/(m^2r_0^4)\) is the square of the orbital angular velocity, \(\ddot\delta=-(3-n)\Omega^2\delta\). For \(n=2\) the radial and orbital frequencies are equal, so the orbit closes after one turn: the ellipse of Kepler, with fixed apsides.

Flattened stars

In the Discours Maupertuis applied the theory of rotating fluid bodies to the heavens. A star spinning fast enough should be strongly flattened, and he suggested that some faint nebulous patches seen in telescopes might be such flattened stars seen edge-on, and that changes in the brightness of some stars might come from their rotation. He also discussed how a body passing close to Saturn might leave a ring. The details proved wrong, but the idea of explaining the shapes of celestial objects by gravity and rotation became a central theme of astronomy.

Exercise 10.1Repeat the potential calculation for the force law \(F\propto s\) (potential \(\propto s^2\)) and show that a shell again acts as a point mass at its centre, for particles both inside and outside.

Show solution
Take \(\Phi=\tfrac{\kappa}{2}\int s^2\,dM\). Averaging \(s^2=r^2+R^2-2rR\cos\theta\) over the shell, the cosine term integrates to zero, so \(\Phi=\tfrac\kappa2M(r^2+R^2)\). The force \(-\Phi'(r)=-\kappa Mr\) is that of a point mass \(M\) at the centre under the same law, for every \(r\).

Exercise 10.2For \(n=2\), the radial and orbital frequencies agree. What is the apsidal angle (the angle between successive perihelia) for a nearly circular orbit when \(F\propto r^{-n}\)? Evaluate it for \(n=2\) and \(n=1\).

Show solution
The time from one perihelion to the next is \(2\pi/(\Omega\sqrt{3-n})\), during which the angle advances by \(2\pi/\sqrt{3-n}\). For \(n=2\), \(2\pi\): the orbit closes. For \(n=1\), \(2\pi/\sqrt2\approx254.6^\circ\): successive perihelia fall about \(105^\circ\) short of a full turn, and the orbit traces a rosette. Newton used this in the Principia to show that the nearly fixed apsides of the planets require a law very close to the inverse square.
Part III · Life and legacy
Lesson 11

President in Berlin, 1740–1753

Frederick II became king of Prussia in 1740 and wanted a great academy. He invited Maupertuis, the most famous French scientist of the moment, to direct it. Maupertuis went to Berlin, followed the king on campaign in Silesia, and in April 1741 was captured by Austrian soldiers after the battle of Mollwitz. He was robbed, then treated with courtesy in Vienna and released, and was back in Paris by June. He was elected director of the Paris Academy for 1742 and was received into the Académie française on 27 June 1743.

He returned to Berlin in 1745 and on 25 August married Eleonore von Borck, from a Prussian noble family. In 1746 he became president of the reorganised Royal Prussian Academy of Sciences and Letters, with near-absolute authority over appointments, prizes and publication. Euler, already in Berlin, directed the mathematics class and was his strongest support. Maupertuis set prize questions, recruited foreign members, and used French as the Academy’s language. He continued to publish: the Essai de cosmologie (1750), Système de la nature (1751), and in 1752 a collected Œuvres with Lettres and the Lettre sur le progrès des sciences, a programme of research that proposed, among other things, experiments on hybridisation and a city where only Latin was spoken.

His administrative style was autocratic, and his health, troubled by lung disease, was declining. These two facts help explain how badly the next crisis went.

DiscussionMaupertuis’s scientific reputation rested largely on choosing and organising projects: the Lapland expedition, the Berlin Academy, the programme of the Lettre sur le progrès des sciences. How should historians weigh this kind of contribution against individual discoveries?

Lesson 12

König, Akakia, death and legacy, 1751–1759

The König affair

In March 1751 Samuel König, a Swiss mathematician whom Maupertuis had brought into the Berlin Academy, published a paper criticising the principle of least action. He quoted a letter of Gottfried Wilhelm Leibniz to Jakob Hermann, apparently stating the principle decades earlier. König said the original had belonged to Samuel Henzi, a Swiss executed in Bern in 1749, and could not produce it. Maupertuis had the Academy investigate. In 1752, with Euler leading the case, the Academy declared the letter unauthentic, in effect accusing König of forgery. König resigned his membership. Most scholars now think the letter was probably a genuine copy, or at least not a forgery by König, and the Academy’s judgement has generally been seen as a misuse of authority.

Voltaire

Voltaire, then at Frederick’s court and now hostile to Maupertuis, took König’s side. In late 1752 he published the Diatribe du docteur Akakia, a satire mocking Maupertuis’s character and the more speculative proposals of the Lettres. Frederick had copies burned, and Voltaire left Prussia in 1753. The satire was widely read and fixed an absurd image of Maupertuis for generations. Voltaire had already ridiculed the Lapland voyage in Micromégas.

Last years

Ill and humiliated, Maupertuis left for France in 1753, returned to Berlin in 1754, and left for good in 1756. His membership of the Paris Academy, cancelled when he took office in Berlin, was renewed with a pension. In 1757 he set out for Italy but stayed seven months in Bordeaux, and in October 1758 he reached Basel, where he lived with the Bernoulli family. He died there on 27 July 1759, before his wife could arrive from Berlin, and was buried at Dornach, near Basel.

Legacy

  • Geodesy: the Lapland measurement settled the oblate figure of the Earth and helped establish Newtonian physics in France.
  • Mechanics: the principle of least action, made precise by Euler, Lagrange, Hamilton and Jacobi, is a cornerstone of classical and quantum physics.
  • Biology: an early particulate theory of heredity, a family pedigree studied with probability, and speculation on the origin of varieties.
  • Institutions: eight years at the head of the Berlin Academy in its most brilliant period.
  • Honours: Fellow of the Royal Society (1728), member of the Académie française (1743), and member of most European academies of his time; a lunar crater bears his name.

Final projectCompare the three principles of Fermat (1662), Maupertuis (1744) and Hamilton (1834) for a single ray or particle crossing a plane interface. State each precisely, derive the law of refraction from each, and explain in two pages why Maupertuis’s and Fermat’s principles predict opposite speed ratios but the same observed path.

Reference

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Reference

Sources and further reading

Biography

  1. J. J. O’Connor and E. F. Robertson, Pierre Louis Moreau de Maupertuis, MacTutor History of Mathematics.
  2. B. Glass, Maupertuis, Pierre Louis Moreau de, Dictionary of Scientific Biography.
  3. Pierre Louis Maupertuis, Wikipedia.
  4. French Geodesic Mission to Lapland, Wikipedia.
  5. M. Terrall, The Man Who Flattened the Earth: Maupertuis and the Sciences in the Enlightenment, University of Chicago Press, 2002.
  6. P. Brunet, Maupertuis, 2 vols., Blanchard, Paris, 1929.

Science

  1. P.-L. M. de Maupertuis, Discours sur les différentes figures des astres, Paris, 1732.
  2. P.-L. M. de Maupertuis, La Figure de la Terre, déterminée par les observations de Messieurs de Maupertuis, Clairaut, Camus, Le Monnier et de M. l’Abbé Outhier, accompagnés de M. Celsius, Paris, 1738.
  3. P.-L. M. de Maupertuis, Accord de différentes lois de la nature qui avaient jusqu’ici paru incompatibles, Mém. Acad. Roy. Sci. Paris (1744).
  4. P.-L. M. de Maupertuis, Les lois du mouvement et du repos déduites d’un principe métaphysique, Hist. Acad. Roy. Sci. Berlin (1746).
  5. P.-L. M. de Maupertuis, Vénus physique, 1745; Système de la nature, 1751; Œuvres, 4 vols., Lyon, 1756.
  6. A. C. Clairaut, Théorie de la figure de la terre, tirée des principes de l’hydrostatique, Paris, 1743.
  7. L. Euler, Methodus inveniendi lineas curvas maximi minimive proprietate gaudentes, Lausanne and Geneva, 1744, Additamentum II.
  8. B. Glass, Maupertuis, pioneer of genetics and evolution, in Forerunners of Darwin 1745–1859, Johns Hopkins, 1959.
  9. Maupertuis provides evidence of hereditary particles, EBSCO Research Starters.
  10. H. Goldstein, C. Poole and J. Safko, Classical Mechanics, 3rd ed., Addison-Wesley, 2002, §8.6 (the principle of least action).
  11. C. Lanczos, The Variational Principles of Mechanics, 4th ed., Dover, 1970.